LAB 8 REPORT
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Wheatstone Bridge Circuit
LAB 8 REPORT
MELISSA FERNANDES
12.09.2023
LAB PARTNER: SHYKIA WILLIAMS
EMT 1150
PROF; DR CHEN XU Table of Contents
OBJECTIVE
.........................................................................................................................................................
3
MATERIALS
.......................................................................................................................................................
3
PROCEDURE
......................................................................................................................................................
3
DATA
....................................................................................................................................................................
4
RESULTS AND CONCLUSION
.........................................................................................................................
0
Appendix
............................................................................................................................................................
2
OBJECTIVE
Understand the principle of Wheatstone bridge circuit, determine the load voltage of bridge circuit, and use bridge
circuit to measure unknown resistor.
MATERIALS
1.
Breadboard 2.
Resistors 3.
Multimeter 4.
Multimeter probes 5.
Power supply 6.
Switch 7.
Alligator clips
PROCEDURE
The circuit was built from the left side to the right. We had to place the resistors in the right order and add a potentiometer and switch. After everything was placed in its proper position, we connected the 6.8k ohm resistor and attached jumper wires. Before attaching the battery, we measured the jumper wires. Additionally, we measured the distance after moving the jumper wires closer to the battery source. Next, we needed to test the voltage using resistor 1, which had a resistance of 4.7k ohms, by moving one of the jumper wires closer to the potentiometer. You should
measure 0 volts while the switch is off and any number when it is on, therefore I measured two separate values. After that, we completed all the additional measurements required for this lab. DATA
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R
AB
R
BC
R
AC
Position1
0.03
9.52
9.53
Position2
2.54
7.01
9.51
Position3
3.44
6.10
9.52
The function of a potentiometer is to provide variable resistance.
Loop 1
E-VR1-VR2=0
=8.71 V – 3.97V – 4.77V
= 0
Loop 2
E-VR3-VR4=0
Loop1
Loop2
E
8.71 V E
8.71 V
V
R1
3.97 V V
R3
5.14 V V
R2
4.77 V V
R4
3.61 V Sum of V
R1 and V
R2
8.74 V
Sum of V
R3 and V
R4
8.74 V
= 8.74 V – 5.14V -3.61 V
= 0
V
A
V
B
V
C
V
D
V
E
V
F
V
M
8.71 V
8.71 V 8.71 V 3.60 V 0.04V
0.04 V
4.71 V I
total
I
1
I
2
0.85 mA
0.33 mA 0.54 mA
R
total
R
branch1
R
branch2
6.35 k
10.23 k
6.65k
(R1+R2) // (R3+R4)
4.7k + 5.6 k = 10.3 k
10k + 6.8k = 16.8 k
¿
(
16.8
k
)(
10.3
k
)
16.8
+
10.3
k
¿
173,0404,00
27.1
k
= 6.36 k
1.
Balance the bridge.
a.
Close the switch and measure the voltages between the Point D and Point M.
V
DM =
4.07 V b.
How could you obtain this voltage from the measurements made in steps 2 and 3?
c.
Place a Load resistor (1KΩ) between Point M and Point D. Measure the Load
voltage (V
Load
) V
Load =. 1.1V
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RESULTS AND CONCLUSION
To conclude, this lab report was challenging to complete, but thankfully, I had the instructor’s support. She guided me in the right direction, and I was able to complete the lab. I found the calculations of this lab challenging but is still attempted all of them. My voltage measurements were not the same as the calculation. Which shows that something went wrong during the measurements, or the formula used. 1) Calculate each voltage in exercise 8.2.2 and compare it to the measured value. 4.7k
+ 5.6k
= 10.3k
9/10.3 = 0.873 V
Voltage at R1 was 3.97 V.
10k + 6.8k = 16.8
9/16.8k = 0.536
Voltage at R2 was 4.77 V.
2) Calculate each current in exercise 8.2.4 and compare it to the measured value
I1= 9/4.7k
= 1.91 mA
I2= 9/5.6 k
= 1.61 mA
Total = 3,52 mA
I3= 9/10k
= 0.9 mA I4= 9/6.8k
= 1.32 mA
Total = 2.22 mA
3) Calculate the resistances in exercise 8.2.5 and the total resistance and compare it to the corresponding measured values. 9/1.91 = 4.7k
R1= 4.7k
9/1.61 = 5.59 k
R2= 4.7k 9/0.9 = 10k
R3= 10k
9/1.32 = 6.8k
4) Of what advantage is it to measure voltage to a common point (or ground)? To ensure the safety and proper operation of the circuit, voltage must be maintained within a specific range. Elevated voltage has the potential to cause damage to your equipment.
5) Research Resistance thermometer on internet, discuss how to use bridge circuit to measure the temperature change. Resistance thermometers are sensors that detect temperature by taking use of a metal's or metal oxide's ability to change electrical resistivity in response to temperature changes. 1
Appendix
2
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3
4
5
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