Lab3_Kinematics HW

docx

School

Eastern Kentucky University *

*We aren’t endorsed by this school

Course

101

Subject

Mechanical Engineering

Date

Jan 9, 2024

Type

docx

Pages

5

Uploaded by MateRam13707

Report
PHY 101 Lab 3: Kinematics Data Activity 1 0 10 20 30 40 50 60 70 0 10 20 30 40 50 60 70 Time X Position Y 1. What is the average speed of the train during the time interval from 0 s to 10 s? 4m/sec 2. Using the equation: v = s 2 s 1 t 2 t 1 , calculate the average speed of the train as it moves from position x = 50m to x = 60m. 0.667m/sec 3. What does the slope of the line during each time interval represent? It represents the velocity 4. From time t = 35 s until t = 45 s, the train is located at the same position. What is slope of the line while the train is stationary? The slope is straight or 0
5. Calculate the average speed of the train as it moves from position x = 70m to x = 55m. What does the sign of the average velocity during this time interval represent? It represents a negative change in velocity or -3m/sec 6. What is the displacement of the train from time t = 0s until t = 50s? +55 7. What is the total distance traveled by the train from time t = 0s until t = 50s? 85m 8. What is the slope of the line during the time interval t = 45 to t = 50? -3 9. What does the sign of the slope in question 8 represent in terms of the motion of the train? It indicates that the train is in reverse 10.What is the average velocity of the train during the interval t= 0s to t = 50s? 0.9m/sec 11.Does the train’s average velocity during the interval t= 0s to t = 50 s provide a complete picture of the train’s motion during this time? No, because the train was moving in reverse and the average velocity is positive. Activity 2 Data Table 1 Time vs. Displacement Time (s) Displacement (m) 0 0.00 0.76 0.25 1.58 0.50
Time vs. Displacement 2.49 0.75 3.24 1.00 3.99 1.25 4.73 1.50 5.51 1.75 6.23 2.00 Data Table 2 Velocity vs. Time Time (s) Velocity (m/s) 1 0.32 2 0.32 3 0.32 4 0.32 5 0.32 6 0.32 7 0.32 8 0.32
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
  • Access to all documents
  • Unlimited textbook solutions
  • 24/7 expert homework help
0 1 2 3 4 5 6 0 0.2 0.4 0.6 0.8 1 1.2 1.4 1.6 1.8 2 Tumble buggy Activity 3 Data Table 3 Acceleration over Increasing Displacement Time (s) Average time (s) Average Time 2 (s 2 ) Displacement (m) Trial 1 = 0.62 0.38 0.1 Trial 2 = Trial 3 = Trial 1 = 0.81 0.66 0.2 Trial 2 = Trial 3 = Trial 1 = 0.85 0.72 0.3 Trial 2 = Trial 3 = Trial 1 = 1.05 1.1 0.4 Trial 2 = Trial 3 = Trial 1 = 1.26 1.59 0.5 Trial 2 = Trial 3 = Trial 1 = 1.34 1.70 0.6 Trial 2 =
Trial 3 = Trial 1 = 1.37 1.88 0.7 Trial 2 = Trial 3 = Trial 1 = 1.6 2.56 0.8 Trial 2 = Trial 3 = 12.What is the shape of the graph when displacement is graphed vs. time? It is a diagonal line going up and to the right 13.What is the shape of the graph when displacement is graphed against time squared? It’s a diagonal line going up and to the right 14.What do the shapes of these graphs tell you about the relationship between distance and displacement for an object traveling at a constant acceleration? As long as the travel is 1 dimensional, the distance and displacement will be the same.