Answered: For the Following question Graph all 4…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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For the Following question Graph all 4 : [I just need all 4 graphs and please explain and make clean solution]

Position vs time
Velocity vs time
Acceleration vs time
Force vs time

[For your convenience, I have solved the numerical solutions for the problem] (Please Look at the picture since it is much cleaner)

Question : A 550 kilogram mass initially at rest acted upon by a force of F(t) = 50e^t Newtons. What are the acceleration, speed, and displacement of the mass at t = 4 second ?

a =(50 e^t)/(550 ) [N/kg]

v = ∫_0^t▒(50 e^t )dt/(550 )= v_0 +(50 e^t-50)/550=((e^t- 1))/11

x = ∫_0^t▒(e^t- 1)dt/(11 )= x_0 +(e^t- t - 1)/(11 )

a(4s)=(50*54.6)/550= 4.96[m/s^2 ]

v(4s)=((e^4-1))/11= 4.87[m/s]

x(4s)=((e^4- 4 - 1))/11= 4.51 [m]

For the Following question Graph all 4 :
1. Position [m] vs time[s]
2. Velocity [m/s] vs time[s]
3. Acceleration m/2 vs time[s]
4. Force [N] vs time[s]
[For your convenience, I have solved the numerical solutions for the problem]
A550 kg mass initially at rest acted upon by a force of F(t) = 50 e' N. What
are the acceleration, speed, and displacement of the mass at t = 4 s?
50 et | N
a =
550 lkg!
rt (50 e')dt
50 et – 50
(et – 1)
V =
= vo +
550
550
11
* (e² – 1)dt
et
= xo +
t - 1
-
x =
11
11
50 * 54. 6
a(4s) :
m
= 4. 96
550
(e* – 1)
v(4s)
= 4.87
S
11
(e* –
x(4s) =
4 - 1)
-
= 4.51 [m]
11

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