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Q1. Collar A moves at a velocity, V4, to the right. The values of the kinematic parameters are given in the table. Complete the table by filling in the values in the yellow cells. Positive directions of the velocities are as shown in the figure. VA W AB B VB Table 1 L (mm) 0 (deg)B (deg) v4 (mm/s) @AB (rad/s) vB (mm/s) 420 20 60 800

Q1. Collar A moves at a velocity, V4, to the right. The values of the kinematic parameters are given in the table. Complete the table by filling in the values in the yellow cells. Positive directions of the velocities are as shown in the figure. VA W AB B VB Table 1 L (mm) 0 (deg)B (deg) v4 (mm/s) @AB (rad/s) vB (mm/s) 420 20 60 800

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
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hello, are you able to do the other question bsed on the sample solution? i am unable to get the answer, and i kinda still dont understand. please do a step by step explaination . need to find the values in the yellow boxes

1. Collar A moves in a constant velocity of 900 mm/s to the right. At the instant when 0 = 30°, determine (a) the angular velocity of rod AB, (b) the velocity of collar B. (BJ 15.34 on page 721) 30° 70° B Solution A With O-xy, we can express 30° 70° v, = 90020° = 900 î (mm/s) A B TRA = 300Z- 30° = 300 (0.866 î – 0.5 ĵ) (mm) Vg = VgZ-70° = V½( 0.342î – 0.94 Ĵ) (mm/s) Using v, V, + öx ĩ gives BA A V ( 0.342 î – 0.94 ĵ) = 900 î + Ôk × 300 (0.866 î – 0.5 ĵ) | "АВ" Component of î: 0.342 vB Ov A 150 0 = 900 (1) ליק Component of ĵ: VB A 0.94 v B + 259.80 = 0 (2) Solving the simultaneous equations (1) and (2) gives B VB = 1017 (mm/s) 3.68 (rad/s) Hence v = 1017Z-70° (mm/s) (ans) ö = ék= - 3.68 k (ans)
Transcribed Image Text:1. Collar A moves in a constant velocity of 900 mm/s to the right. At the instant when 0 = 30°, determine (a) the angular velocity of rod AB, (b) the velocity of collar B. (BJ 15.34 on page 721) 30° 70° B Solution A With O-xy, we can express 30° 70° v, = 90020° = 900 î (mm/s) A B TRA = 300Z- 30° = 300 (0.866 î – 0.5 ĵ) (mm) Vg = VgZ-70° = V½( 0.342î – 0.94 Ĵ) (mm/s) Using v, V, + öx ĩ gives BA A V ( 0.342 î – 0.94 ĵ) = 900 î + Ôk × 300 (0.866 î – 0.5 ĵ) | "АВ" Component of î: 0.342 vB Ov A 150 0 = 900 (1) ליק Component of ĵ: VB A 0.94 v B + 259.80 = 0 (2) Solving the simultaneous equations (1) and (2) gives B VB = 1017 (mm/s) 3.68 (rad/s) Hence v = 1017Z-70° (mm/s) (ans) ö = ék= - 3.68 k (ans)
Q1. Collar A moves at a velocity, v4, to the right. The values of the kinematic parameters are given in the table. Complete the table by filling in the values in the yellow cells. Positive directions of the velocities are as shown in the figure. VA B O AB В VB Table 1 L (mm)0 (deg)B (deg) v4 (mm/s)oAB (rad/s)VB (mm/s) 420 20 60 800
Transcribed Image Text:Q1. Collar A moves at a velocity, v4, to the right. The values of the kinematic parameters are given in the table. Complete the table by filling in the values in the yellow cells. Positive directions of the velocities are as shown in the figure. VA B O AB В VB Table 1 L (mm)0 (deg)B (deg) v4 (mm/s)oAB (rad/s)VB (mm/s) 420 20 60 800
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