NUC350_M2.7_Quiz
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Question 1 10 / 10 pts For PWR (Pressurized Water Reactor) type plants, what is a pressurizer “outsurge” and how does the pressurizer control system respond? An outsurge is caused by a decrease in reactor coolant temperature and results in an increase in pressurizer pressure as the steam bubble is expanded. The pressurizer control system responds by
actuating sprays.
An outsurge is caused by an increase in reactor coolant temperature and results in an increase in pressurizer pressure as the steam bubble is compressed. The pressurizer control system responds by actuating sprays.
An outsurge is caused by an increase in reactor coolant temperature and results in a decrease in pressurizer pressure as the steam bubble is compressed. The pressurizer control system responds by energizing heaters.
An outsurge is caused by a decrease in reactor coolant temperature and results in a decrease in pressurizer pressure as the steam bubble is expanded. The pressurizer control system responds by
energizing heaters.
Question 2 10 / 10 pts With regard to typical Westinghouse design PWR (Pressurized Water Reactor) type plants, which of the following correctly lists control systems that utilize reactor coolant “Tavg” as an input signal? Rod control, steam dump control, and steam generator level control
Steam dump control, steam generator level control, and pressurizer pressure control
Rod control, steam dump control, and pressurizer level control
Steam dump control, pressurizer level control, and steam generator level control
IncorrectQuestion 3 0 / 10 pts With regards to a boiling water reactor (BWR), why are the control rods inserted from the bottom of the core? Control rods enter from the bottom of the core such that flow through the core is not impeded.
Control rods enter from the bottom of the core to ensure reliable insertion when a Scram signal is
initiated
Control rods enter from the bottom because there is a large percentage of voids in the upper part of the core and if the rods entered from the top the neutron flux would be severely depressed
Control rods enter through the bottom of core for ease of maintenance on the control rods. Wrong answer
Question 4 10 / 10 pts The purpose of the stainless steel weld overlay/clad in the reactor vessel: Provide the necessary corrosion resistance
Provide the vessel protection from neutron embrittlement
Protect the vessel from temperature changes
Protect the vessel from pressure changes.
Question 5 10 / 10 pts With regard to BWR (Boiling Water Reactor) type plants, what is the purpose of the Control Rod
Drive System Scram Inlet and Outlet Valves? Control flow of water necessary for rapid rod insertion.
Control emergency boration flow in the event of rapid rod insertion.
Control flow of water to the rod drive motor coolers.
Control flow of reactor coolant recirculation in the event of rapid rod insertion.
Question 6 10 / 10 pts With regard to typical Westinghouse design PWR (Pressurized Water Reactor) type plants, what is the basis for the “Overtemperature ΔT” (OTΔT) reactor trip signal? Protect the steam generator u-tubes from excess stress.
Steam dump control, pressurizer level control, and steam generator level control
Protect the nuclear fuel and fuel cladding from overheating conditions.
Protect the reactor core from departure from nucleate boiling conditions.
Question 7 10 / 10 pts
The figure shown below depicts a typical “Differential Rod Worth” curve for a PWR (Pressurized Water Reactor) type plant.
Which of the following describes the reason for the general shape of the curve?
Control rod speed is programmed higher towards the middle of rod travel.
Xenon peaks typically appear at the center of the core.
Neutron flux is higher towards the center of the core.
Reactor coolant flow is higher towards the center of the core.
Question 8 10 / 10 pts With regards to a boiling water reactor (BWR), what is the function of the recirculation pumps.
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Provide cooling water for reactor plant components
Recirculate water through the core to adjust reactor power by changing pump speed thus flow rate through the core.
Recirculate water through the reactor vessel to ensure the reactor core is covered
Recirculate water through the jet pumps to ensure the core is cooled in the event of a loss of coolant accident.
Question 9 10 / 10 pts The figure shown below depicts the logic of a typical BWR (Boiling Water Reactor) Recirculation Pump Speed Controller. What is the purpose of the device shown in the red oval?
Ensures adequate pump speed to cool the reactor in the event of a power excursion
Prevents a pump run-out condition
Restrains recirculation pump speed to prevent pump overheating
Restrains recirculation pump speed to prevent a power excursion
Question 10 10 / 10 pts With regards to a boiling water reactor (BWR), what are the purpose of the jet pumps? Increase coolant pressure through the core
Regulate flow through the reactor core.
Increase the total core flow while minimizing the flow external to the reactor vessel (recirculation loop flows).
Direct coolant flow through the reactor core.
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Related Questions
An overheating vehicle is being discussed.
Technician A states that coolant in a normal
flow cooling system flows from the radiator
to the heater core to warm up
the
passenger
compartment quickly. Technician B states
that in a reverse flow cooling system, coolant
flows to the cylinder heads first, which keeps
engine components at a more uniform
temperature. Who is correct?
Select one:
a. Technician A only
b. Technician B only
c. Both Technicians A andB
d. Neither Technician A nor B
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7)
arrow_forward
Get the following values for each stage using NIST tables:
Stage 5(feed water in): P5, T5, H5
Stage 6(feed water out ): P6, T6, H6
Explain how to get values please.
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Required information
Problem 07.025 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a
pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at -10°C, and
leaves as saturated vapor at the same pressure.
Problem 07.025.c - Total entropy change of the process
Determine the total entropy change for this process.
The total entropy change for this process is
kJ/K.
arrow_forward
###
Develop the objective for a project report of a cell for the energy reuse of superheated steam within a thermoelectric power plant.
The main focus is to determine the pressure drop within the system of this cell and the hydraulic compression pump contained within it.
The cell contains, in all, the following equipment:
Upstream:
Two (tap) switching valves
Two eccentric gearboxes
Two pressure gauges
Downstream:
Two pressure gauges
Two concentric magnifications
A check valve (ball)
A (tap) shut-off valve
An expansion joint
arrow_forward
جية - A -
Northern Technical University
Technical Eng. College/Kirkuk
Fuel and Energy Eng. Tech. Dep.
4th Year Students
Final Examination (2022-2023)
Subj.: Process of unit operation
Date: 6/6/2023
Time: 3 Hours:
Morning & Evening Study
Note/Answer only four questions, including the first question
Q.1: Water is to be cooled in a packed tower from 330 to 295 K by means of air flowing counter
currently. The liquid flows at the rate of 275 cm³/m² s and the air at 0.7 m³/m² s. The entering
air has a temperature of 295 K and a humidity of 20%. Calculate the required height of tower
and the condition of the air leaving at the top. The whole of the resistance to heat and mass
transfer can be considered as being within the gas phase and the product of the mass transfer
coefficient and the transfer surface per unit volume of column (ha) may be taken as 0.2 s¹.
Assuming, the latent heat of water at 273 K = 2495 kJ/kg, specific heat capacity of dry air =
1.003 kJ/kg K, specific heat capacity of…
arrow_forward
Three water coils are connected in parallel. The water supplied to the coils feeds into a commonreturn line. The first coil feeds 60 gpm of 125 o F water into the return line. The second coil feeds 50gpm of 120 o F water into the line. The third coil feeds 50 gpm of 118 o F water into the commonreturn line. What is the temperature of the water in the common line after the three streams ofwater mix?
arrow_forward
For the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate:
WFS_A * X - WFS_G(X-1) = 1
whereWFS_A = mass fraction of NH3 in solution form the absorberWFS_G = mass fraction of NH3 in solution from the generator
X-1 =mass of solution from the generator per unit mass of refrigerant flowFor large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psiConsider a large NH3/H2O plant operating per the schematic below:
Known/given:i. Refrigeration load = 500 tonsii. Evaporator temperature (state point 10) = 41.1 Fiii. Evaporator pressure (state point 10) = 75 psiaiv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber)v. Strong aqua solution temperature (state point 3) = 105 Fvi. Condenser temperature (state point 8) = 100 Fvii. Condenser and tower pressure (state point 7) = 211.9 psiaviii. Concentration split, WFS_G - WFS_A =6% by weight…
arrow_forward
!
Required information
Problem 07.025 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS
NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part.
Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a
pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at -10°C, and
leaves as saturated vapor at the same pressure.
Problem 07.025.b - Entropy change of the cooled space in an evaporating process
Determine the entropy change of the cooled space. (You must provide an answer before moving on to the next part.)
The entropy change of the cooled space is
KJ/K.
arrow_forward
For the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate:
WFS_A * X - WFS_G(X-1) = 1
where WFS_A = mass fraction of NH3 in solution form the absorber WFS_G = mass fraction of NH3 in solution from the generator
X-1 =mass of solution from the generator per unit mass of refrigerant flow For large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psi Consider a large NH3/H2O plant operating per the schematic below:
Known/given: i. Refrigeration load = 500 tons ii. Evaporator temperature (state point 10) = 41.1 F iii. Evaporator pressure (state point 10) = 75 psia iv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber) v. Strong aqua solution temperature (state point 3) = 105 F vi. Condenser temperature (state point 8) = 100 F vii. Condenser and tower pressure (state point 7) = 211.9 psia viii. Concentration split, WFS_G - WFS_A =6%…
arrow_forward
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- Required information Problem 07.025 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at -10°C, and leaves as saturated vapor at the same pressure. Problem 07.025.c - Total entropy change of the process Determine the total entropy change for this process. The total entropy change for this process is kJ/K.arrow_forward### Develop the objective for a project report of a cell for the energy reuse of superheated steam within a thermoelectric power plant. The main focus is to determine the pressure drop within the system of this cell and the hydraulic compression pump contained within it. The cell contains, in all, the following equipment: Upstream: Two (tap) switching valves Two eccentric gearboxes Two pressure gauges Downstream: Two pressure gauges Two concentric magnifications A check valve (ball) A (tap) shut-off valve An expansion jointarrow_forwardجية - A - Northern Technical University Technical Eng. College/Kirkuk Fuel and Energy Eng. Tech. Dep. 4th Year Students Final Examination (2022-2023) Subj.: Process of unit operation Date: 6/6/2023 Time: 3 Hours: Morning & Evening Study Note/Answer only four questions, including the first question Q.1: Water is to be cooled in a packed tower from 330 to 295 K by means of air flowing counter currently. The liquid flows at the rate of 275 cm³/m² s and the air at 0.7 m³/m² s. The entering air has a temperature of 295 K and a humidity of 20%. Calculate the required height of tower and the condition of the air leaving at the top. The whole of the resistance to heat and mass transfer can be considered as being within the gas phase and the product of the mass transfer coefficient and the transfer surface per unit volume of column (ha) may be taken as 0.2 s¹. Assuming, the latent heat of water at 273 K = 2495 kJ/kg, specific heat capacity of dry air = 1.003 kJ/kg K, specific heat capacity of…arrow_forward
- Three water coils are connected in parallel. The water supplied to the coils feeds into a commonreturn line. The first coil feeds 60 gpm of 125 o F water into the return line. The second coil feeds 50gpm of 120 o F water into the line. The third coil feeds 50 gpm of 118 o F water into the commonreturn line. What is the temperature of the water in the common line after the three streams ofwater mix?arrow_forwardFor the NH3/H2O cycle the following relationship give the solution flow rate per unit refrigeration rate: WFS_A * X - WFS_G(X-1) = 1 whereWFS_A = mass fraction of NH3 in solution form the absorberWFS_G = mass fraction of NH3 in solution from the generator X-1 =mass of solution from the generator per unit mass of refrigerant flowFor large systems, a reasonable pressure drop between the evaporator and absorber is 1.5 psiConsider a large NH3/H2O plant operating per the schematic below: Known/given:i. Refrigeration load = 500 tonsii. Evaporator temperature (state point 10) = 41.1 Fiii. Evaporator pressure (state point 10) = 75 psiaiv. Absorber pressure (state point 11) = 73.5 psia (per rule of thumb above regarding pressure drop between the evaporator and absorber)v. Strong aqua solution temperature (state point 3) = 105 Fvi. Condenser temperature (state point 8) = 100 Fvii. Condenser and tower pressure (state point 7) = 211.9 psiaviii. Concentration split, WFS_G - WFS_A =6% by weight…arrow_forward! Required information Problem 07.025 - DEPENDENT MULTI-PART PROBLEM - ASSIGN ALL PARTS NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Refrigerant-134a enters the coils of the evaporator of a refrigeration system as a saturated liquid-vapor mixture at a pressure of 140 kPa. The refrigerant absorbs 200 kJ of heat from the cooled space, which is maintained at -10°C, and leaves as saturated vapor at the same pressure. Problem 07.025.b - Entropy change of the cooled space in an evaporating process Determine the entropy change of the cooled space. (You must provide an answer before moving on to the next part.) The entropy change of the cooled space is KJ/K.arrow_forward
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