Module4.4_Delossantos

I need help with my MATLAB code. I am trying to plot the semi major axis and eccentricity with the following code with rungge kutta method. I have two different nnn's in the code which produce two different step sizes. So, I am wondering why both give the same exact plots for semi-major axis and eccentricity. The orbital dynamics fucntion considers J2, drag, SRP, and third body effects.   % Orbital elements obtained from TLE inc = 63.5000118; % Inclination (degs) raan = 19.999977; % RAAN (degs) ecc = 0.001; % Eccentricity argp = 120.02165342; % argument of perigee (degs) v = 0; % True anomaly (degs)   a = 6584.697271; % Semi-major axis (km)   mu = 3.986e5; period = (2*pi*sqrt((a^3)/mu));     % Calculating the state vector in eci frame [x, y, z, vx, vy, vz] = kep2cart(a, ecc, inc, raan, argp, v); Y = [x, y, z, vx, vy, vz];   options = odeset('RelTol', 1e-12, 'AbsTol', 1e-12);   nnn1 = 800; t_step1 = period/nnn1; m6 = 50; h_step6 = t_step1/m6; t_total6 = 0:h_step6:10*period;   [t6,…

Derive the component transformation equations for tensors shown below where [C] = [BA] is the DCM (direction cosine matrix) from frame A to B.  ^B [T] = [C]^A [T] [C]^T

permanent-magnet (pm) genera x Bb Blackboard Learn L STAND-ALONE.mp4 - Google Dri x O Google Drive: ülwgjuó jc lis u O ME526-WindEnergy-L25-Shuja.p x O File | C:/Users/Administrator/Desktop/KFUPM%20Term%232/ME526/ME526-WindEnergy-L25-Shuja.pdf (D Page view A Read aloud T) Add text V Draw Y Highlight O Erase 17 of 26 Wind Farms Consider the arrangement of three wind turbines in the following schematic in which wind turbine C is in the wakes of turbines A and B. Given the following: - Uo = 12 m/s A -XẠC = 500 m -XBC = 200 m - z = 60 m - Zo = 0.3 m U. -r, = 20 m B - CT = 0.88 Compute the total velocity deficit, udef(C) and the velocity at wind turbine C, namely Vc. Activate Windows Go to Settings to activate Windows. Wind Farms (Example Answer) 5:43 PM A 4)) ENG 5/3/2022 I!

****USE MATLAB TO SOLVE THIS QUESTION**** 5. A composite cantilever beam, made of High Strength (HS) carbon/epoxy material with [04/304], plies, has uniformly applied load qo. When qo=50N/m, length of the beam, L=0.1m, and width of the beam, b-0.05m. Find the maximum deflection of the beam. (for the HS carbon fiber/epoxy, E₁1 =131 GPa, E₂2= 11.2 GPa, V12 = 0.28, G12 = 6.55 GPa and ply thickness t=0.2mm) 90-50N/m L

Help!!! Please answer all Correctly!!! Please

I thought the letters represented the connection between the forces and magnitude. Can you help me truly understand how to evaluate this correctly? Thanks

Help me with this ENGINEERING GRAPHICS problem.

sample calculations 目 File Edit View Insert Format Data To 100% $ % .0 .00 12: fx | A 1 Variable Value Units diameter height m 4 volume m^3 3 The image above shows a section of a Google sheet. What formula should be written in cell B4 to calculate the volume of a cylinder with a diameter value in B2 and height in B3? a) =0.25*PI()*B2^2 * B3 b) =PI()*B2^2 * B3 c) =pi*diameter^2 * height d) =PI*B2^2 * B3 3 5

HW_5_01P.pdf PDF File | C:/Users/Esther/Downloads/HW_5_01P.pdf 2 Would you like to set Microsoft Edge as your default browser? Set as default To be most productive with Microsoft Edge, finish setting up your Complete setup Maybe later browser. (D Page view A Read aloud V Draw 7 Highlight 2 of 3 Erase 5. Two cables are tied to the 2.0 kg ball shown below. The ball revolves in a horizontal circle at constant speed. (Hint: You will need to use some geometry and properties of triangles and their angles!) 60° 1.0 m 60° © 2013 Pearson Education, Inc. (a) For what speed is the tension the same in both cables? (b) What is the tension? 2. 2:04 PM O Type here to search C A 2/9/2021 (8)

Parvinbhai

I need help coding in MATLAB. I have a .txt file containing the following data. That data is saved in a file named data.txt. I am wondering how I could extract all or some of that data into another .m file. Can you show me the code.   [[5.0018696581196584, 17.863820207570207, -13.086858974358975], [5.0018696581196584, 17.863820207570207, -13.086858974358975], [5.0018696581196584, 17.863820207570207, -13.086858974358975]]

W Determine the transformed reduced stiffness matrix for a unidirectional ply oriented at 45 degrees to the global x-axis for the material. S [Q]= [150.72 2.41 2.41 8.04 0 0 English (United Kingdom) Text Predictions: On - Q Search 23 Where: Using the formula below: F3 E [T] = $ 4 € R [T]-¹= F 0 0 GP F5 10] [cos²0 sin²0 -sin cose Accessibility: Good to go % 5 [cos²0 sin²0 sin cose Q = [T]¹[Q][T] T T F6 6 G sin²0 cos²0 sin cose sin 20 cos²0 -sin@cose 2sin cose -2sin@cose cos²0-sin²0] & H -2sin cose 2sin cose cos²0-sin²0] FB LU U * 00 O J F9 8 ( 9 F10 K M Focus GO F11 0 B P