A tank has a hole in the bottom with a cross-sectional area of 0.0025 m² and an inlet line on the side with a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m². The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through the inlet. (Vin = 4.47 m/s).
A tank has a hole in the bottom with a cross-sectional area of 0.0025 m² and an inlet line on the side with a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m². The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through the inlet. (Vin = 4.47 m/s).
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
Related questions
Question
The red questions please q4 and q5 and q7
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Vo)
it LTE1
Assignment 2 Fluid..
ASSIGNMENT 2: FLUID FLOWS
SEAA 1513 Fluid Mechanics (Section 01)
Session 2021/2021 Semester I
Due date is 3 December 2021 before 5 pm.
Answer all the Questions
1) Figure 1 shows a siphon that is used to draw water from a swimming pool. The tube that makes up the
siphon has an inside diameter of 40 mm and terminates with a 25 mm diameter nozzle. Assuming that
there are no energy losses in the system, calculate the volume flow rate through the siphon and the pressure
at points B and E. (pB = -4.50 kPa, pe = 24.93 kPa).
2) The problem, as shown in Figure 2, is to estimate the pressure at locations A and B so that these values
can be used to estimate the ventilation in a bicycle helmet currently being designed. Assume an air density
of p = 1.2 kg/m3 and an air speed of 12 m/s relative to the helmet. Point A is a stagnation point, and the
velocity of air at point B is 18 m/s. (p2= 86.4 Pa, p4 =-108 Pa).
3) Figure 3 shows a stream of water flows into an open tank. The speed of the incoming water is V = 7 m/s,
and the section area is A = 0.0025 m². Water also flows out of the tank at a rate of Q = 0.003 m³/s. Water
density is 1000 kg/m³. Sketch the CV on the diagram and what is the rate at which water is being stored
(or removed from) the tank? (14.5 kg/s).
4) A tank has a hole in the bottom with a cross-sectional area of 0.0025 m² and an inlet line on the side with
a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m².
The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water
surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the
rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through
the inlet. (Vin = 4.47 m/s).
5) From Figure 5, a horizontal pipe carries cooling water at 10° C for a thermal power plant. The head loss
in the pipe is:
0.02()v²
h, =
2g
Where, L is the length of the pipe from the reservoir to the point in question, V is the mean velocity in the
pipe, and D is the diameter of the pipe. If the pipe diameter is 20 cm and the rate of flow is 0.06 m³/s, what
is the pressure in the pipe at L = 2000 m? For water (10°C): y = 9810 N/m³. (418 kPa).
6) At the maximum rate of power generation, a small hydroelectric power plant (in Figure 6) takes a
discharge of 14.1 m/s through an elevation drop of 61 m. The head loss through the intakes, penstock, and
outlet works is 1.5 m. The combined efficiency of the turbine and electrical generator is 87%. What is the
rate of power generation? (7.16 MW).
7) As shown in Figure 7, assume that the head loss in the pipe is given by hị = 0.014(L/D)(V 2/2g), where L
is the length of pipe and D is the pipe diameter. Assume a = 1.0 at all locations. Determine the discharge
of water through this system and sketch the HGL and the EGL for the system. (Q = 1.99 m³/s; pmax = 373
kPa gage, and pmin = -82.6 kPa gage).
8) As shown in Figure 8, water flows from the reservoir on the left to the reservoir on the right at a rate of
0.453 m/s. The formula for the head losses in the pipes is hL = 0.02(L/D)(V²/2g). What elevation in the
1
left reservoir is required to produce this flow? Also carefully sketch the HGL and the EGL for the system.
Note: Assume the head-loss formula can be used for the smaller pipe as well as for the larger pipe. (z1 =
39.32 m).
9) Water at 10°C is flowing from section 1 to section 2. At section 1, which is 25 mm in diameter, the gage
pressure is 345 kPa and the velocity of flow is 3.0 m/s. Section 2, which is 50 mm in diameter, i« ^
above section 1. Assuming, there are no energy losses in the system, calculate the pressure pɔ
КРа).
10) Water with a density of 1000 kg/m³ flows through a vertical venturimeter as shown in Figure 9..
gage is connected across two taps in the pipe (station 1) and the throat (station 2). The area ratio Athroatapipe
is 0.5. The velocity in the pipe is 10 m/s. Find the pressure difference recorded by the pressure gage.
Assume the flow has a uniform velocity distribution and that viscous effects are not important.
(Apgage=150kPa),
11) Determine the external reactions in the x- and y-directions needed to hold this fixed vane, shown in Figure
10. which turns the oil jet in a borizontal plane Here V. is 18 m/s Va -17 m/s and 0- 0 15 m3/s (Er"
Transcribed Image Text:3:03
Vo)
it LTE1
Assignment 2 Fluid..
ASSIGNMENT 2: FLUID FLOWS
SEAA 1513 Fluid Mechanics (Section 01)
Session 2021/2021 Semester I
Due date is 3 December 2021 before 5 pm.
Answer all the Questions
1) Figure 1 shows a siphon that is used to draw water from a swimming pool. The tube that makes up the
siphon has an inside diameter of 40 mm and terminates with a 25 mm diameter nozzle. Assuming that
there are no energy losses in the system, calculate the volume flow rate through the siphon and the pressure
at points B and E. (pB = -4.50 kPa, pe = 24.93 kPa).
2) The problem, as shown in Figure 2, is to estimate the pressure at locations A and B so that these values
can be used to estimate the ventilation in a bicycle helmet currently being designed. Assume an air density
of p = 1.2 kg/m3 and an air speed of 12 m/s relative to the helmet. Point A is a stagnation point, and the
velocity of air at point B is 18 m/s. (p2= 86.4 Pa, p4 =-108 Pa).
3) Figure 3 shows a stream of water flows into an open tank. The speed of the incoming water is V = 7 m/s,
and the section area is A = 0.0025 m². Water also flows out of the tank at a rate of Q = 0.003 m³/s. Water
density is 1000 kg/m³. Sketch the CV on the diagram and what is the rate at which water is being stored
(or removed from) the tank? (14.5 kg/s).
4) A tank has a hole in the bottom with a cross-sectional area of 0.0025 m² and an inlet line on the side with
a cross-sectional area of 0.0025 m², as shown in Figure 4. The cross-sectional area of the tank is 0.1 m².
The velocity of the liquid flowing out the bottom hole is V = /2gh, where h is the height of the water
surface in the tank above the outlet. At a certain time, the surface level in the tank is 1 m and rising at the
rate of 0.1 cm/s. The liquid is incompressible. Sketch the CV and find the velocity of the liquid through
the inlet. (Vin = 4.47 m/s).
5) From Figure 5, a horizontal pipe carries cooling water at 10° C for a thermal power plant. The head loss
in the pipe is:
0.02()v²
h, =
2g
Where, L is the length of the pipe from the reservoir to the point in question, V is the mean velocity in the
pipe, and D is the diameter of the pipe. If the pipe diameter is 20 cm and the rate of flow is 0.06 m³/s, what
is the pressure in the pipe at L = 2000 m? For water (10°C): y = 9810 N/m³. (418 kPa).
6) At the maximum rate of power generation, a small hydroelectric power plant (in Figure 6) takes a
discharge of 14.1 m/s through an elevation drop of 61 m. The head loss through the intakes, penstock, and
outlet works is 1.5 m. The combined efficiency of the turbine and electrical generator is 87%. What is the
rate of power generation? (7.16 MW).
7) As shown in Figure 7, assume that the head loss in the pipe is given by hị = 0.014(L/D)(V 2/2g), where L
is the length of pipe and D is the pipe diameter. Assume a = 1.0 at all locations. Determine the discharge
of water through this system and sketch the HGL and the EGL for the system. (Q = 1.99 m³/s; pmax = 373
kPa gage, and pmin = -82.6 kPa gage).
8) As shown in Figure 8, water flows from the reservoir on the left to the reservoir on the right at a rate of
0.453 m/s. The formula for the head losses in the pipes is hL = 0.02(L/D)(V²/2g). What elevation in the
1
left reservoir is required to produce this flow? Also carefully sketch the HGL and the EGL for the system.
Note: Assume the head-loss formula can be used for the smaller pipe as well as for the larger pipe. (z1 =
39.32 m).
9) Water at 10°C is flowing from section 1 to section 2. At section 1, which is 25 mm in diameter, the gage
pressure is 345 kPa and the velocity of flow is 3.0 m/s. Section 2, which is 50 mm in diameter, i« ^
above section 1. Assuming, there are no energy losses in the system, calculate the pressure pɔ
КРа).
10) Water with a density of 1000 kg/m³ flows through a vertical venturimeter as shown in Figure 9..
gage is connected across two taps in the pipe (station 1) and the throat (station 2). The area ratio Athroatapipe
is 0.5. The velocity in the pipe is 10 m/s. Find the pressure difference recorded by the pressure gage.
Assume the flow has a uniform velocity distribution and that viscous effects are not important.
(Apgage=150kPa),
11) Determine the external reactions in the x- and y-directions needed to hold this fixed vane, shown in Figure
10. which turns the oil jet in a borizontal plane Here V. is 18 m/s Va -17 m/s and 0- 0 15 m3/s (Er
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