CEE370L_Test5_Report_Vergara, Kailah Reign

Problem 1: (50 points) In Avengers 2, Captain America's improved shield is made from unobtainium, a new material that will soon be available in a store near you. Unobtainium has the normal stress- strain diagram shown. The proportional limit, the elastic limit and the yield point are identical in this material. o [MPa] 2001 175 150 125 100 Fig.1 Normal stress-strain 75 50 25 0 0. 0.05 0.1 0.15 0.2 0.25 Unobtainium has a Poisson's ratio of 0.3. a. [6pts] Identify the yield point oy, the ultimate stress ou and the fracture stress of. Include units. c. [25pts] A bar of unobtainium has a length of 1.5 m, a width of 100mm and a height of 50 mm, as shown. The cross-sectional area is 50mm 100mm = 5 x 10-³m². The bar is subjected to an axial force of 375 kN. Find the normal stress in a cross-section of the bar. b. [5pts] How do you find Young's modulus from this graph? Find its value with units. whesta fins dus al hoss P = 375 KN 1.5 m 0.3 50 mm 100 mm & [mm/mm] Is the material within its…

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HEAT TRANSFER CASE:  I want to know what temperature in (°F) the cylinder will have inside. It's a heat transfer problem. what is T2 ? HEAT TRANSFER They gave me an answer all squashed together that i can't make sense of it. If you could help me makes sense of it thank you!

A metallic strain gauge produces an electrical resistance change when subjected to mechanical strain. However, engineers don't measure this voltage drop directly using a voltmeter. Why don't we directly measure the voltage drop across the strain gauge, and instead, use a Wheatstone Bridge? Damgraph >

QUESTION 7 A model tow-tank test is conducted on a bare hull model at the model design speed in calm water. Determine the effective horsepower (hp) for the ship, including appendage and air resistances. The following parameters apply to the ship and model: Ship 1,100 Model Length (ft) Hull Wetted Surface Area (ft2) Speed (knots) 30 250,000 15 Freshwater Water Seawater 50°F 70°F Projected Transverse Area (ft²) Cair 7,500 0.875 Appendage Resistance (% of bare hull) 10% Hull Resistance (Ibf) 20

Constants | Periodic Table Part A A 71 kg man's arm, including the hand, can be modeled as a 79-cm-long uniform cylinder with a mass of 3.5 kg In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity? Express your answer with the appropriate units. ? h = Value Units Submit Request Answer

PHYS X PHYS X 印 PHYS X PHYS X POTPHYS X PHYS X E PHYS X E PHYS top/semester2/physics%20for%20engineers/PHYS220_CH15_Lecture%20Notes_Problems%2015 19,15.29 S (D Page view A Read aloud V Draw Problem-15-19: page-475 A 0.500-kg object attached to a spring with a force constant of 8.00 N/m vibrates in simple harmonic motion with an amplitude of 10.0 cm. Calculate the maximum value of its (a) speed, and acceleration. (b) the speed and the acceleration when the object is 6.00 em from the equilibrium position, and (c) the time interval required for the object to move from.r50 to r5 8.O0 cm. Solution:

Describe the extent to which your data indicate that mechanical energy is conserved. Consider the percentage differences in the energy changes in Data Table 2 and Data Table 3 in youranswer.

E and 5 v X O file:///C:/Users/Hp/Desktop/mm/OUTCOME%20NO.2%20and%205%20with%20Problems.pdf + O Fit to page D Page view A Read aloud 1 Add notes Problems 1. A brass rod of diameter 25 mm and length 250 mm is subjected to a tensile load of 50 kN and the extension of the rod is equal to 0.3 mm. Find the Young's Modulus or Modulus of Elasticity. 99+ to search hp delete prt sc 14 DI backs & 7 8 24 4 P EJR -0 J K H D. F

HW4 Q9

⦁ “God himself could not sink this ship” This is an advertisement for the Titanic, produced in the early 1900s. However, after colliding with an iceberg at dawn on April 15, 1912, two rivers were formed, and out of the 2,200 people on board, 1,500 people, including the captain, sank with the ship. According to a later investigation, the “temperature change theory” (DBTT theory) was the most promising cause of the sinking. Give a brief guess of the cause of the ship's sinking in relation to temperature.

Study Area Document Sharing User Settings Access Pearson mylabmastering.pearson.com P Pearson MyLab and Mastering The crash cushion for a highway barrier consists of a nest of barrels filled with an impact-absorbing material. The barrier stopping force is measured versus the vehicle penetration into the barrier. (Figure 1) Part A P Course Home b My Questions | bartleby Review Determine the distance a car having a weight of 4000 lb will penetrate the barrier if it is originally traveling at 55 ft/s when it strikes the first barrel. Express your answer to three significant figures and include the appropriate units. Figure 1 of 1 36 μΑ S = Value Units Submit Request Answer Provide Feedback ? Next >

Please show work for practice problem 12

APPLICATIONS OF FIRST ORDER DIFFERENTIAL EQUATIONS Newton’s Law of Cooling and Joint Proportions   At 4:00pm, a thermometer reading of 28 deg C is taken outside where the ambient temperature is –11 deg C. At 4:05 pm, the thermometer reads 8 deg above zero. After a while, the thermometer is returned to the room maintained at 28 deg C. At 4:12pm, the thermometer reads 15 deg C. When was the thermometer returned to the room?

The purpose of this problem is to show the relationship between material constants typically used in engineering practice. This is useful because you may often have access to measurements of or tabulated values of some constants (e.g., Young's modulus and Poisson's ratio) but need another constant (e.g., shear modulus) for a calculation. Use the expression Cijkl = µ(dildjk + dikdjl) + Ad¿jdkl to derive the following: (a) Young's modulus, E = µ(3X+2µ)/(X+μ), from the definition 11 = Ee11 in a unconfined (022 = 0,033 = 0) uniaxial tension test. (b) Poisson's ratio, v = \/(2(X + μ)), from the definition v = €22/11 in the same test as in (a). (c) Shear modulus, μ = G = 012/(2€12) = E/(2(1 + v)). Use the results to show that C can also be written Cijkl Ev/((1+v)(1 − 2v))dij§kl. = E/(2(1 + v))(duðjk + dikdjl) +

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