EE306Fall2018FinalAnswerKey
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University of Texas *
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Course
306
Subject
Electrical Engineering
Date
Jan 9, 2024
Type
Pages
13
Uploaded by MateCloverWolverine31
EE306
Introduction
to
Computing
Fall
2018
Final
Exam
Dr.
Nina
Telang
(TAs:
Vignesh
Radhakrishnan,
Jefferson
Lint,
Dylan
McCoy,
Suhas
Raja)
UT
EID:
kega
Printed
Name:
Ttlfi"g
Your
signature
is
your
pledge
that
you
have
not
and
will
not
cheat
on
this
exam,
nor
help
other
students
to
cheat
on
this
exam.
Signature:
Instructions:
1.
2.
3.
4.
This
is
a
180
minute
closed
book,
closed
notes
exam.
No
calculators
or
other
electronic
devices
are
allowed.
Please
refer
to
the
LC-3
ISA
sheet,
data
path,
state
graph
and
other
reference
sheets
which
have
been
attached
to
the
exam.
Please
answer
all
questions
neatly
in
the
space
provided.
WRITE
YOUR
FINAL
ANSWER
IN
THE
SPACE
PROVIDED
FOR
EACH
QUESTION.
ONLY
THE
FINAL
ANSWER
WILL
BE
GRADED.
NO
PARTIAL
CREDIT
WILL
BE
GIVEN.
Problem
#
1
/20
Problem
#
2
/15
Problem
#
3
/10
Problem
# 4
/10
Problem
#
5
/10
Problem
#
6
/15
Problem
#
7
/10
Problem
#
8
/10
.
Nina
K.
Telang
1
1.
{20
points]
Answer
the
following
short
questions
in
the
space
provided.
@)
[2
points]
Consider
the
LC-3
load
instruction,
LD.
During
which
stages
of
the
instruction
cycle
of
this
instruction
are
MAR
and
MDR
updated.
b
Ynslvuckon,
Pb"d,v
Orb(wv\al,a
(ii)
[2
points]
The
INT
signal
for
the
keyboard
is
generated
using
bits
14
and
15
of
the
KBSR.
Say
that
A
=
KBSR[15],
and
B =
KBSR[14].
How
would
you
generate
the
INT
signal
given
only
NOT
and
OR
gates?
Write
the
logic
expression.
nor
(ot
()
o
wot(8))
(iii)
[4
points]
Design
a
4-to-16
decoder
using
two
3-to-8
decoders,
one
NOT
gate,
and
AND
gates
(any
number
that
you
need).
A
\D/
'
(iv)
[2
points]
Write
an
LC-3
code
snippet
that
performs
the
logical
OR
operation
of
the
contents
in
R1
and
R2,
and
puts
the
result
in
R3.
NoT
R4,
A
NOT
Ll((LL
And
13,
&,
2
NoT
K3,
13
Nina
K.
Telang
2
(v)
[4
points]
Shown
below
are
the
contents
of
registers
before
and
after
the
LC-3
instruction
at
location
x3210
is
executed.
Identify
the
instruction
stored
at
x3210.
Write
the
instruction
in
hexadecimal.
Answers
in
any
other
format
will
not
be
considered.
Before
After
RO
|
xFFID
|
xFFID
RL__|
x301C
|
x301C
R2_
|
x2F11
|
x2FI1
R3_
|
x5321
|
x5321
R4
|
x331F
|
x33IF
X
4
8oF
R5
|
xIF22
|
xIF22
R6
|
x0IFF
|
xOIFF
R7__
|
x341F
|
x3211
PC_
|
x3210
|
x3220
N
0
0
Z
1
1
P
0
0
(vi)
[6
points]
A
gated
D-latch
is
shown
in
the
figure
below.
Answer
the
following
short
questions:
(a)
What
is
the
output
A
if
inputs
D
and
WE
are
both
1?
|
(b)
What
is
the
output
A
if
D=0
and
WE=1?
0
(c)
List
the
values
of
S,
R
that
can
never
occur
given
this
D-latch?
Why
will
these
values
never
occur?
§=0=0
wll
never
occr
WE
—¢
Nina
K.
Telang
3
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Bors
Ze-\,\
s
Frp
Feockon
.
Nmznh%m'
(;.;«a::k
-
A
N=(-Y
x
|+
bod.bor
&%
'\
-1
[cere
)
_
<z
%
2.
[15
pomts]
lgata
is
stored
e;’
LC-3
memory
location
x3456
in
floating
point
format
such
that
there
is
1-bit
for the
sign,
5-bits
for
the
exponent,
and
10-bits
for the
fraction.
A
student
wants
to
write
a
program
that
will
output
the
data
in
decimal
format
(i.e.
the
screen
will
display
a
real
number
like
17.75
or
-0.5).
For
this
question,
give
all
numerical
responses
in
decimal.
0
‘I'V
3
\
@
What
are
the
smallest
and
largest
exponents
that
can
be
represented
using
the
given
format?
Note
that
“exponents”
refers
to
the
power
of
2.
v\ouvd/‘
RNVJ
@b
N“MAJA'LZJ
CPate
Donrenadined
)
~-15
o
NSy
E
\
(’)\c,s
g
(i)
Shown
below
is a
code
snippet
of
the
student’s
code.
After
the
executlon
of
these
lf
lines
of
code,
RS
should
contain
the
exponent
of
the
normalized
bi
-15
=
@
representation
of
the
number
stored
in
x3456
(e.g.
if
m[x3456]
=
1
l*
4
khen
RS
will
contain
4).
A
description
of
the
subroutine
BitShift
is
given
in
the
comments
[;)‘f
-
3\),
6\0\5
E
\b
of
the
program.
;
begin
code
snippet
F0-15
{15
;
RO
contains
bits
m-
m[x3456]
isolated
in
place
Ro:
AND
RORORUT™
1o,
cf
M’Tg’
N7
o~
1
AND
R1,R1,R1
l
fool\
/_J
;
BitShift
bit
shifts
the
value
in
R0
a
certain
direction
m
o
'
;
it
shifts
the
bits
the
number
of
times
specified
by
the
value
in
Rl
JSR
LD
R4,
VAL
£
q_
ADD
R5,R0,R4]
7
VAL
=#°
5
)(
-
9—71
as
=
;
end
code
snippet
E%@
b
¥\5
pp
z
@
(a)
What
direction
should
BitShift
shift
the
bits
of
RO
(right
or
left)?
@
(b)
What
value
should
R1
contain
before
BitShift
is
called
for
the
program
to
work
as
intended?
lo
(c)
What
value
should
R4
be
loaded
with
in
order
for
R5
to
contain
the
correct
value
after
this
program’s
execution?
-5
Nina
K.
Telang
4
(d)
In
the
BitShift
subroutine,
the
student’s
code
performed
the
following
steps:
Step
1:
Saved
the
values
of
R0
through
R7
in
memory
Step
2:
Checked
to
see
if
R1=0
Step
3:
If
not,
then
divided
the
number
in
RO
by
2,
decremented
R1,
and
looped
back
to
Step
2.
Step
4:
IfR1
=
0,
then
restored
the
values
in
RO
through
R7,
followed
by
RET.
If
RO
=
16
and
R1
=
2
before
the
execution
of
the
subroutine,
what
will
the
values
of
R0
and
R1
be
after
the
execution?
RO=16
,
Ri=2
¢
Does
this
subroutine
work
as
intended?
No
p
becanse
RO
15
1
QsL-rlflo‘
Ia
Yo
lask
si’br-
Nina
K.
Telang
5
3.
[10
points]
Dr.
Telang
has
decided
to
have
you
all
implement
another
LC-3
instruction
that will
have
the
opcode
1101
(currently
not
used).
This
instruction
will
be
called
BIC
and
will
clear
a
specified
bit
of
a
register.
The
format
is
as
follows:
15(14)13}12(11|10|9
(8
(7
|6
|5
[4
[3
|2
|1
JoO
1|1
|0
|1
|DR
SR
X
[x
[x
[x
[x
|x
(i)
The
least
significant
6
bits
are
marked
with
an
“x.”
Some
of
these
bits
are
going
to
be
reserved
for
the
Selection
field,
which
will
identify
which
bit
to
clear
in
the
SR
and
stored
in
the
destination
register
DR.
For
example,
if
the
Selection
field
=
12,
then
bit
12
of
the
SR
will
be
cleared.
What
is
the
minimum
number
of
bits
marked
with
an
“x”
that
need
to
be
reserved
for
this
field?
q_
(i)
How
many
memory
accesses
does
this
new
instruction
make?
Include
all
stages
of
the
instruction
cycle.
|
(iii)
Isit
possible
for
this
instruction
to
change
the
condition
code
bits?
If
so,
give
an
example.
Y,¢
I~
(iv)
During
the
Fetch
Operands
phase,
a
temporary
register,
calle(@
is
loaded
with
'
the
value
that
corresponds
to
the
Selection
field
(e.g.
Selection
field
=3,
TR
=
x0008).
What
logical
structure
can
easily
produce
the
value
of
TR?
L1
(v)
Write
the
microinstructions
that
take
place
in
the
Execute
and
Store
Result
phase
of
the
instruction
cycle.
You
are
allowed
to
use
the
following
registers:
PC,
IR,
MAR,
MDR,
SR,
DR,
and
TR.
TR
«—
NOT(TQ)
TR
«—
TR
Avd>
SR
bR«
TR
Nina
K.
Telang
6
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4.
[10
points]
An
Aggie
has
tried
implementing
two
new
instructions
for
the
new
LC-4
machine,
PUSH
Rn
pushes
the
data
in
register
Rn
onto
the
stack.
Similarly,
POP
Rn
pops
the
data
at
the
top
of
the
stack
and
loads
into
register
Rn.
The
instructions
are
implemented
in
the
following
way:
PUSH
ADD
R6,
R6,
#-1
STR
Rn,
R6,
#0
POP
LDR
Rn,
R,
#0
(i)
Is
there
an
error
in
the
code?
If
so,
then
how
can
you
fix
it?
Qorer
am
POP
\
P(H/J'\h
Y\QA’LJo
|0
be
IILMM\’\DAA}U\
Q,’/Vh’\.
,0_5\4*
5
(ii)
For
the
following
stack
operations
(using
the
PUSH
and
POP
instructions
as
implemented
in
the
code
shown
above),
trace
the
contents
of
registers.
If
the
contents
cannot
be
known
with
the
given
information,
place
a
N/A
in
the
box.
m’
Other
than
R6,
the
registers
initially
contain
R1=0x1111,
R2=0x2222,
e
...R7=0x7777.
Each
column
shows
the
register
contents
after
all
previous
operations
(in
previous
columns).
PUSHR2
POP
R4
PUSH
R6
PUSHRS5
PUSHRI
PUSHR3
PUSHRI
PUSHR3
POP
R7
PUSH
R4
POP
RS
POP
R6
POP
R5
PUSH
R2
POPRI1
R1=0x1111
|RI=0xi11}
RI=
K11
Rl=pgh1t
Rl=
}z2z22
R2=0x2222
|R2=0y
2222
R2=
%2222
R2=j
2222
R2=
k2222
R3=0x3333
[R3=
x3333
R3=
x3333
R3=R>33>
R3=
X
3333
R4=0x4444
|Rd=
r4uyy
R4=N/p
R4=
N/A
R4=
nfp
R5=0x5555
|
R5=
%6555
R5=
k3333
R5=;Q3PFF
R5=
R
3FFF
R6
=0x4000
|
R6=K3PFF
R6=
K2PFF
R6=
X
3FFD
R6=
A3FFF
R7=0x7777
|R7=
X2222
R7=
x2222
R7=
p227L
R7=
p2227%
7
Nina
K.
Telang
5.
[10
points]
An
LC-3
operating
in
Interrupt
driven
I/O
mode
has
the
following
input
devices
connected
to
it:
Keyboard:
Interrupt
Vector
x80,
Priority
Level
4
Mouse:
Interrupt
Vector
x20,
Priority
Level
3
The
Interrupt
Enable
bits
for
both
these
devices
are
enabled
by default.
The
following
program
starts
at
x3000.
LD
RO,
Count
Loop
ADD
RO,
RO,
#-1
?[XLOOP
T
Count
.FILL
x02
The
keyboard
and
the
mouse-ISR
both
have
3
instructions
each
including
RTI.
The
mouse
raises
an
interrupt
during
the
decode
phase
of
the
ADD
instruction
when
RO
=
x01
and
the
keyboard
raises
an
interrupt
during
the
execute
phase
of
ADD
instruction
when
RO
=x01.
Your
task
is
to
complete
the
PC
trace
which
captures
the
values
of
PC
when
entering
the
fetch
phase
of
instruction
cycle.
Some
of
them
are
already
filled
for
you.
PC
TRACE
x3000
A
300]
x3002
X200\
%3002
mYoxol80]
m
Yog
ol
s+
mite
oigo)fal
v
x3002Y
Myoxolp
7001251
mihroizie
o
%3003
Nina
K.
Telang
8
6.
[15
points]
It’s
Throwback
Thursday
!!
Back
in
the
Fall
of
1985,
Dr.
Telang,
a
freshman
in
IIT,
was
introduced
to
the
microprocessor
Intel
8085.
Knowing
about
the
8085
was
considered
swag
back
then.
It
has
been
more
than
3
decades
now
and
Dr.
Telang
would
like
y’all
to
take
a
look
at
this
vintage
machine.
Investigate
the
8085
Microarchitecture/ISA(see
attached
sheets)
and
answer
the
®
(i)
following
questions:
What
is
the
maximum
data
width
the
8085
ALU
can
operate?
°}
bl
bs
‘What
is
the
maximum
number
of
memory
locations
that
can
be
addressed
by
80857
2\6:
Flag
Register
is
an
8-bit
register
in
which
five-bit
positions
contain
the
status
of
five
condition
codes
which
are
Zero
(Z),
Sign
(S),
Carry
(CY),
Parity
(P)
and
Auxiliary
carry
(AC).
The
flag
register
format
is
shown
below:
by
bs
bs
bsbs
b2
bi
by
[STZ[x[ACTx[P[x[CY]
Sign
(S)
flag
—
If
the
result
of
an
operation
is
negative,
this
flag
is
set (1),
otherwise
it
is
reset
(0).
Zero
(Z)
flag
—
Similar
to
‘Z’
condition
code
of
LC-3
Carry
(CY)
flag
-
If
an
instruction
results
in
a
carry
(for
addition
operation)
or
borrow
(for
subtraction
or
comparison)
out
of
the
MSB,
then
this
flag
is
set,
otherwise
reset.
Auxiliary
Carry
(AC)
flag
—
If
there
is a
carry/borrow
out
of
bit
3
and
into
bit 4
resulting
from
the
execution
of
an
arithmetic
operation,
it
is
set
otherwise
reset.
Parity
(P)
flag
—
This
flag
is
set
when
the
result
of
an
operation
contains
an
even
number
of
1’s
and
is
reset
otherwise.
The
table
shows
the
status
of
the
bits
in
the
flag
register
and
accumulator
after
each
of
the
following
instructions
are
executed.
Don’t
make
any
assumptions
on
the
initial
state
of
the
registers.
Your
task
is
to
fill
in
the
blanks.
Some
are
already
filled
for
you.
Instruction
|
Accumulator
[ S
|Z
|C
(AC
|
P
(Hexadecimal)
XRA
A
*
00
ol
]o
o
|1
MVI
B,
x70
*00
0
[1]0j0
|1
MVI
C,
x0A
X
0U
01110
lo0
|1
SUB
B
x40
€0
i
[1
[
SBB
C
X
%9
viploly
1O
ADD
C
%
&f
1101l
o0
10
Nina
K.
Telang
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(iv)
The
8085
has
the
ability
to
combine
two
registers
and
use
them
as
a
register
pair.
B
and
C
can
be
considered
as
one
BC
register
with
B
in
higher
order
bit
position
and
C
in
lower
order
bit
position.
Similarly,
D
and
E
can
be
combined
to
DE,
and
Hand
L
to
HL,
where
D
and
H
are
in
higher
order
positions.
MVID,
x0
MVIE,
x0
MVI
B,
xAB
MVIC,
x0
MOVL,B
MOV
H,C
DAD
B
DCX
H
INXD
What
will
be
the
value
of
the
register
pairs
after
the
above
program
is
executed?
Fill
in
the
table
provided.
[BC
=
xApoo
|DE
=
x
000\
[HL
=
x
Aphh
]
Nina
K.
Telang
10
.
[10
points]
Design
an
FSM
having
one
input
X
and
one
output
Z,
such
that
Z
is
the
2’s
complement
of
X.
The following
are
some
example
input
sequences
with
their
corresponding
output
sequences.
In
each
example
listed
below
the
LSB
is
the
rightmost
bit,
and
the
MSB
is
the
lefimost
bit.
Note
that
the
LSB
will
arrive
at
the
machine
input
first
followed
by
the
more
significant
bits.
Example
1:
X=0001,Z=1111
Example
2:
X
=0001001,Z=
1110111
Example
3:
X
=1110111,
Z
=
0001001
@)
Draw
the
state
graph
for
this
finite
state
machine.
(i)
How
many
storage
elements
do
you
need
to
implement
this
FSM?
%
(ili)
Complete
the
state
table
for
this
FSM. You
may
not
need
all
the
rows.
Present
State
Next
State
Z
8160
X=0
X=1
So
00
Sz
Sy
0
5
04
S
S3
]
Sa
’
0
Sg_
sl
O
Sy
i
S\
S3
o}
(iv)
Write
the
logic
expression
for
output
Z.
7=
Q
t
go
Nina
K.
Telang
11
8.
[10
points]
A
queue
is
a
data
structure
where
elements
are
removed
in
the
order
they
are
added
(like
a
bus
queue).
You
would
like
to
implement
this
data
structure
using
2
stacks,
named
inbox
and
outbox.
The
idea
is
that
inbox
is
a
stack
where
queue
elements
enter,
To
retrieve
elements
from
the
queue,
you pop
elements
from
stack
outbox.
When
you
PUSH
a
number
to
inbox,
the
number
gets
pushed
to
the
top
of
inbox.
Pushing
a2
number
to
outbox
works
in
the
same
way.
Similarly,
when
you
POP
an
element
from
either
inbox
or
outbox,
the
element
at
the
top
of
the
stack
gets
popped.
Jro?
i.
The
first
figure
below,jtems
that
have
lined
up
in
the
queue,
with
element
X
first,
and
element
Z
last.
Write
a
sequence
of
pseuda
instmictions
such
that
the
2
stacks
together
implements
this
queue.
Note
that
elements
have
already
entered
the
queue,
and
your
task
is
to
use
the
stacks
to
get
them
out
in
the
order
they
entered.
The
first
pseudo
instruction
has
been
shown,
with
the
outcome
shown
in
the
Inbox
stack.
-
Z
—>
[
X
—
4
—
Y
—
—_—
Inbox
Outbox
;
Write
your
pseudo
instructions
below.
The
first
one
is
written
for
you.
PUSH
Inbox
PuUsSH
Inbox
sk
[nbox
PP
lnbox
Pusy
O
whbox
PoP
lnboy
Pusit
Ouwhbor
PO?
Vnbox
Pusn
Ovdhox
Nina
K.
Telang
12
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ii.
The
first
figure
below shows
new
elements
A,
B,
C
(in
that
order)
have
entered
the
queue.
A
snapshot
of
the
two
stacks
shows
that
the
previous
elements
X,
Y,
Z
have
not
been
processed
yet.
Write
a
sequence
of
pseudo
instructions
such
that
the
2
stacks
together
implements
a
queue.
—
(e
—_—
&
>
—
8
b
—
A
Sz
—_—
a>
Inbox
Outbox
;
Write
your
pseudo
instructions
below.
PoP
Oulhoyw
Pop
Owrbox
Pof
O\/J’L:D)a
J\
{
oo
Puon
lnloox
Pusn
linbog
P09
Vwhox
Pusn
Ovdhaox
Nina
K.
Telang
13
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