Lab 1 Report

docx

School

Community College of Philadelphia *

*We aren’t endorsed by this school

Course

102

Subject

Electrical Engineering

Date

Jan 9, 2024

Type

docx

Pages

Uploaded by PresidentValorTarsier8

COMMUNITY COLLEGE OF PHILADELPHIA PHIALDELPHIA, PENNSYLVANIA Experiment Number: 1 Title: Resistance Color Code Experiment Performed by: Partners: Engineer Course: Engineering 102 Lab Section No: 901 Lab Day/Hour: Tue Thu 1PM-3PM Lab Instructor: Dr.W.A.Gontar Date Performed: 09/20/2021 Date Due: 09/21/2021

Purpose The purpose of this experiment is to read and comprehend color code of the resistors, know how to measure resistance by using the Data Acquisition/Switch Unit equipment, and compare nominal and experimental values. Procedure In this experiment, value of three resistors is recorded by two methods; they were color code method and the Data Acquisition/Switch Unit equipment. In color code method, the tolerances of the resistors would be applied to specify their accuracy after their nominal values were calculated, while the value of the resistors was obviously displayed on the screen of the Data Acquisition/Switch Unit equipment. Therefore, there would be nominal values and experimental values. The percent error would be calculated to compare nominal and experimental values, and it would measure accuracy.

Experiment 1 1 Data Sheets Part I: Resistors Color Resistor Band 1 Band 2 Band 3 Tolerance Band 1 Red Red Red Gold 2 Brown Black Red Gold 3 Red Violet Red Gold Part II: Measured Value of the Resistors by Using the Data Acquisition/Switch Unit Equipment Resistor Measured Value 1 2.177 kΩ = 2177 Ω 2 0.989 kΩ = 989 Ω 3 2.676 kΩ = 2676 Ω Calculations I. Resistor 1 a. Accepted Value

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Experiment 1 2 Band 1: Red Band 2: Red Band 3: Red Tolerance Band: Gold The resistance R in Ohms is given by the formula: R = (Colorband 1 x 10 + Colorband 2 ) x MultiplierBand First replace each color by its numerical value. Color Band 1 = RED = 2 Color Band 2 = RED = 2 Multiplier Band = RED = 10 2 = 100 Thus the nominal value for the resistance is: R = (2x10 + 2) x 100 = 2200 Ω The tolerance band is gold which indicates a 5% tolerance. Since 5% of 2200 is 110, the resistance should lie between 2090 Ohms and 2310 Ohms. b. Percent Error % Error = ¿ Measured Value − Accepted Value Accepted Value ∨ x 100% = | 2177 − 2200 2200 | x 100% = 1.0% II. Resistor 2 a. Accepted Value

Experiment 1 3 Band 1: Brown Band 2: Black Band 3: Red Tolerance Band: Gold The resistance R in Ohms is given by the formula: R = (Colorband 1 x 10 + Colorband 2 ) x MultiplierBand First replace each color by its numerical value. Color Band 1 = BROWN = 1 Color Band 2 = BLACK = 0 Multiplier Band = RED = 10 2 = 100 Thus the nominal value for the resistance is: R = (1x10 + 0) x 100 = 1000 Ω The tolerance band is gold which indicates a 5% tolerance. Since 5% of 1000 is 50, the resistance should lie between 950 Ohms and 1050 Ohms. b. Percent Error % Error = ¿ Measured Value − Accepted Value Accepted Value ∨ x 100% = | 989 − 1000 1000 | x 100% = 1.1% III. Resistor 3

Experiment 1 4 a. Accepted Value Band 1: Red Band 2: Violet Band 3: Red Tolerance Band: Gold The resistance R in Ohms is given by the formula: R = (Colorband 1 x 10 + Colorband 2 ) x MultiplierBand First replace each color by its numerical value. Color Band 1 = RED = 2 Color Band 2 = VIOLET = 7 Multiplier Band = RED = 10 2 = 100 Thus the nominal value for the resistance is: R = (2x10 + 7) x 100 = 2700 Ω The tolerance band is gold which indicates a 5% tolerance. Since 5% of 2700 is 135, the resistance should lie between 2565 Ohms and 2835 Ohms. b. Percent Error % Error = ¿ Measured Value − Accepted Value Accepted Value ∨ x 100% = | 2676 − 2700 2700 | x 100% = 0.89%

Your preview ends here

Eager to read complete document? Join bartleby learn and gain access to the full version

Access to all documents
Unlimited textbook solutions
24/7 expert homework help

Experiment 1 5 Answers to Questions Quiz A 1. In a series circuit with one resistor R, V applied = 5V and IR= 0.2 A, find the resistance R of the circuit. R = V I = 5 0.2 = 25 Ω  C is my answer 2. The power dissipated in the above resistor is: P = V*I = 5*0.2 = 1 watt  A is my answer 3. The resistor with Red-Blue-Green-Gold has a value of: R = (2*10 + 6) *100000 = 2600000 Ω = 2.6 MΩ  A is my answer 4. Create a table showing the rated resistance and the measured resistance for each resistor in the packet. Also show the percentage error. Resistor Color Code Measured Value Accepted Value Percent error 1 Red-Red-Red-Gold 2.177 kΩ = 2177 Ω 2200 1.0% 2 Brown-Black-Red-Gold 0.989 kΩ = 989 Ω 1000 1.1% 3 Red-Violet-Red-Gold 2.676 kΩ = 2676 Ω 2700 0.89% 5. The workstation was cleaned and all the parts for the lab were returned to the workstation drawer? True

Experiment 1 6 Analysis and Discussion Resistance measurement easily completed when we determined which channel matches the measuring wire on the Data Acquisition/Switch Unit equipment, and then we read the results on its screen. The results obtained after practicing the experiment were within the tolerance of the theoretical calculation. Percent error was very low. The purpose of the experiment was achieved.