annotated-Week1_Activity_walkerr.docx

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ECPI University, Virginia Beach *

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221L

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Electrical Engineering

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Apr 3, 2024

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EET221L - Instrumentation and Measurement Lab Assignment # 1 Note: Show all the steps leading to the final answer. Showing just answer without steps will lead to lower credit. 1. Calculate the total resistance with uncertainty estimation, if the following resistors are R 1 = 10 k ± 5% and R 2 = 2.2k ± 10% are connected in series. 10k+2.2k=12.2k ohms Squareroot of 1x(5%)^2 + 1(10%)^2 = squareroot (25%) + (100%)= 11.18% Final answer 12.2k ohms + 11.18% 2. Calculate the total resistance with uncertainty estimation, if the following resistors R 1 = 6.8 k ± 5% and R 2 = 2.7k ± 5% are connected in parallel. 2.7/6.8+2.7=0.0807 (6.8/2.7+6.8)^2=0.5123 Squareroot (0.0807)^2 (5%)^2+(0.5123)^2(5%)^2 Final answer 1.932 +/- 2.593% 3. In a circuit, voltage across a resistor is measured as 1.02V with uncertainty of 0.002V and current is measured as 0.00345A with uncertainty of 0.00035A. Calculate the resistance value of the resistor with uncertainty. 1.02/0.00345=295.652ohm 1.02 ln(0.00345)= -5.782 1/0.00345= 289.8550
Square root (-5.782)^2(0.002)^2+(289.8550)^2(0.00035)^2 Final answer 295.652 +/- 0.1021 ohms 4. In a certain circuit current flowing through a resistor 330k ± 5% is measured as 0.01515 A with uncertainty of 0.0000144A. Calculate the voltage drop across the resistor with uncertainty. (330x10^3) (0.01515) = 4999.5v 2(4999.5v)/2(330x10^3)=0.01515 Square root (0.01515)^2(5%)^2+330x10^3)^2(0.000144)^2 Final answer 4999.5 +/- 47.520V
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