lab_10_Delta-Wye_Transformer

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Georgian College *

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2010

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Electrical Engineering

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Feb 20, 2024

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Lab 10 ELEC 2023 – PTD1 Lab #10 - Delta - Wye Transformer Thando Ncube (200537131), Zakrallah Shaker (200525699) Georgian College ELEC - 2023 Power Transmission and Dist Instructor: John Miller Date: November 23, 2023 In conformance with Section 8 of the Georgian College Academic Policies and Procedures the author(s) confirm that this work submitted for assessment is solely their work and is expressed in their own words. Any uses made within it of the works of any other author, in any form (ideas, equations, figures, texts, tables, programs, etc.), are properly acknowledged at the point of use. A list of the references used is include pg. 1

Lab 10 ELEC 2023 – PTD1 Equipment: 1. LabVolt AC Power Supply 2. Three Hammond Single Phase 300VA Transformers 3. LabVolt Data Acquisition and Control Interface 4. LabVolt Resistive Load Module 5. Computer with LVDAC-EMS and LVDAM-EMS software Procedure: During this lab you will complete several tests with different loads and connection configurations, on a three phase delta-wye transformer and load, and record various voltages and current measurements for all three phases. 1. Using the 208V:120V ratio, connect the primary coils of the three transformers to the variable power supply, in a delta connection. 2. Connect the transformer secondary coils to a wye-connected three-phase resistive load. Have your connections checked prior to the first test . NOTE: Due to the large number of voltage readings required, use a single channel on the DACI and move the voltage leads as required. Test 1: No Load Test/ 3. Turn OFF all load switches. 4. Apply 208V to the transformer primary and record the values in the table. Test 2: Full Load Test (primary currents) 5. Turn ON all load switches, and record the values in the table. Test 3: Unbalanced Load 6. Adjust the load as shown in the Load Table, and record the values in the table. Test 4: Full Load Test (transformer currents) 7. With the power off, reconnect the meters to measure the currents and angles of each indicated in the table. 8. Adjust the load as shown in the Load Table, and record the values in the table. Load Selection Table: Red Black Blue Test # 1200 600 300 1200 600 300 1200 600 300 1 OFF OFF OFF OFF OFF OFF OFF OFF OFF 2 & 4 ON ON ON ON ON ON ON ON ON 3 ON ON ON OFF ON ON OFF OFF ON 171.43*3 = 514.29^2*119.8 Data Table: PRIMARY SECONDARY Test V AB V BC V CA I A I B I C I AB I CA V an V bn V cn V ab V bc V ca pg. 2

Lab 10 ELEC 2023 – PTD1 1 210.2 211 211 0.292 0.291 0.299 120.9 121.3 121.4 209.3 210.1 209.6 2 209.5 210.6 210.2 0.835 0.837 0.840 119.3 119.8 119.8 207.3 206.6 207.2 3 209.2 210.5 210.1 0.668 0.800 0.687 118.9 119.8 120. 2 206.8 208.2 207.5 4 0834 <- 48.7 0.481< -17.6 0.488 <- 78.7 For test 4 change the circuit as shown below and record the currents WITH their angles using the phasor analyzer. TEST 4 Move your ammeters as shown below, and use the phasor analyzer to get the angles Lab 10 Submission: Calculations: 1. From test 2 calculate primary power using the average voltage and the average line current. Assume a power factor of 1.0 as the load is all resistive. 2. From test 2 calculate secondary power using the line to neutral voltages and the value of the resistive load. 3. For the Unbalanced Load Test 3 calculate secondary load currents based on the connected load (assume 120° phase displacement at the secondary). 4. Calculate the transformer efficiency for test 2. 5. Include a screen shot of your phasor analyzer showing the currents for test 4. pg. 3

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Lab 10 ELEC 2023 – PTD1 6. Remember that P total = P 1 + P 2 + P 3 Watts = √ ❑ V LL I L Cos φ (if using Wye line to line voltage) = 3 x V LN I L Cos φ (if using Wye line to neutral voltage) = √3 x V LINE-LINE x I LINE x Cos θ (using Delta Line Current) = 3 x V LINE-LINE x I PHASE x Cos θ (using Delta phase current) Delta V phase = V LL Balanced load I LINE = √ ❑ x I PHASE Unbalanced load These currents are calculated WITH the Absolute angles I A = I AB ∠ θ - I CA ∠ θ I B = I BC ∠ θ - I AB ∠ θ I C = I CA ∠ θ - I BC ∠ θ 1) P = √3 x V LINE-LINE x I LINE x Cos θ = √ ❑ *210.1*0.837= 304.58W 2) Rt = 171.43*3 = 514.29 119.8^2/171.43= 83.72W 3) 118.9/171.43 = 0.69A 119.8/171.43 = 0.70A 120.2/171.43 = 0.70A 4) Eff = Pin/Pout = 304.58/83.72 = 3.64 5) 6) pg. 4