Copy of 5CL Pre-Lab 6 Submission Template - S23v2

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University of California, Los Angeles *

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5C

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Electrical Engineering

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Feb 20, 2024

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pdf

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3

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Q1a: Draw a circuit diagram containing a power supply, switch, resistor, and capacitor. 2 Q1b: With the 4 resistor values and 3 capacitor values on the pre-lab, calculate all 12 corresponding RC time constants. Give your results in data table(s) format. Show an example calculation below. Resistor Capacitor RC 1 10 10 5.1 10 51 10 10 100 100 10 1000 1 100 100 5.1 100 510 10 100 1000 100 100 10000 1 470 470 5.1 470 2397 10 470 4700 100 470 47000 ࠵? = R*C ex. R = 1, C = 10 RC = 1*10 = 10 capacitor 11 Fresistor · switch -
Q2a: When the capacitor fully charges and saturates in voltage, do you expect the voltage across the capacitor to be the same as the battery voltage, less than the battery voltage, or greater than the battery voltage? 3 Q2b: When the capacitor voltage is saturated and you open your switch again, do you expect the capacitor to keep its charge or lose its charge? Q2c: Although there is not a complete circuit that includes the battery, there is another complete circuit that you make because you have the voltmeter with an input resistance of order 1 M Ω connected to the capacitor. Draw the circuit diagram consisting of your capacitor and the voltmeter acting as a resistor. What is its RC time constant? We would expect that the voltage across the capacitor to be the same as the battery voltage. We would expect that the voltage across the capacitor to be less than the battery voltage after the switch is opened. r7 · Il - RC = (Mr) C C R3 8 power supply
Q3a: Draw a circuit diagram containing a power supply, switch, resistor, and two capacitors in series . What is the total capacitance of a 100μf capacitor and a 470μf capacitor in series? 4 Q3b: Draw a circuit diagram containing a power supply, switch, resistor, and two capacitors in parallel . What is the total capacitance of a 100μf capacitor and a 470μf capacitor in parallel? Ct+= ) = (i+ c) - " = 82 . 46 MF " Cor = 0 , + 22 = 188 + 470 - =570mF
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