5CL Lab 6 Submission Template - S23
pdf
keyboard_arrow_up
School
University of California, Los Angeles *
*We aren’t endorsed by this school
Course
5C
Subject
Electrical Engineering
Date
Feb 20, 2024
Type
Pages
5
Uploaded by aed.academics
Activity
1 - Measuring Resistance and Capacitance:
List
your 12 resistor-capacitor combinations with their
measured
(not printed) values.
Calculate
the predicted RC time constants for each of these 12 combinations with the measured
values. Show your results in data table format.
Activity
2 - Simple RC Circuit:
Draw
the circuit diagram for your simple RC circuit. Include the PASCO voltmeter and
label
the battery voltage, the resistance of your resistor, and the capacitance of your capacitor (measured values).
Include
your voltage vs. time plot(s) that show your data for both charging and discharging.
Report
your fit values (A,
B, t
0
for rise, A, B, y
0
for discharge).
Resistance→100K ohm, measured 98900 ohm
Capacitance→10μf, measured 0.00001177 f
Voltage=6V
Rise:
A = 5.34 +- 6.2 x 10^-4
B = 0.931 +- 0.0011
t
0
= 4.48 +- 8.82 x 10^-4
Discharge:
A = 24 +- 0.075
B = 0.0836 +- 1.6 x 10^-4
y
0
= 0.0789 +- 0.0026
Activity
2 - Simple RC Circuit (cont.): How does the rise A parameter compare with your power supply voltage? What
is your measured RC time constant for the voltage rise and how does it compare to your prediction? Using the decay
RC time constant and your measured capacitance, what is the resistance in the PASCO voltmeter?
Our Rise A parameter is A = 5.34 +- 6.2 x 10^-4 and our power supply voltage is 6V. Therefore, our Rise A parameter
is smaller than the power supply voltage.
RC time constant is t = 1/B → B = 1.074 s, which was just slightly below our predicted value.
t = RC → R = t/C = 1.19 kΩ
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Activity
3 - Capacitors in Series: Draw the circuit diagram for your capacitors in series and label the resistance of your
resistor, the capacitance of your capacitors, and the voltage on your power supply. What is the equivalent
capacitance of the two capacitors? Does the capacitance increase or decrease when capacitors are in series?
What do you predict your RC time constant will be? Sketch the voltage vs time plot (rise only, no discharge). Report
your best fit parameters (A, B, t
0
). How does the rise A parameter compare with your power supply voltage. What is
your measured RC time constant for the voltage rise and how does it compare to your prediction?
C
eq
= (1/100 + 1/470)^-1 = 82.46 uF = 0.0000824 F
The capacitance decreases when capacitors are in series
A = 5.46 +- 1.8 x 10^-4
B = 0.115 +-2.1 x 10^-5
t
0
= 2.78 +- 8.6 x 10^-4
Predicted RC = (98900ohm)(0.0000824F) = 8.15 sec
The rise A parameter is a little bit less than the power supply voltage. The measured RC time constant is 1/B = 1/0.115 = 8.7 sec, which is around the predicted RC of 8.15
Activity
4 - Capacitors in Parallel: Draw the circuit diagram for your capacitors in parallel and label the resistance of
your resistor, the capacitance of your capacitors, and the voltage on your power supply. What is the equivalent
capacitance of the two capacitors? Does the capacitance increase or decrease when capacitors are in parallel? What
do you predict your RC time constant will be?
Sketch the voltage vs time plot (rise only, no discharge). Report your best fit parameters (A, B, t
0
). How does the rise A
parameter compare with your power supply voltage. What is your measured RC time constant for the voltage rise and
how does it compare to your prediction?
C
eq
= 10 + 100 = 110 uF
The capacitance increase when capacitors are in parallel.
Predicted RC = (98900ohm)(0.00011F) = 10.879 sec
A = 5.43 +- 1.3 x 10^-4
B = 0.0857 +- 9.1 x 10^-6
t
0
= 7.554 +- 5.8 x 10^-4
The rise A parameter is a little bit less than the power supply voltage. The measured RC time constant is 1/B = 1/0.0857 = 11.67 sec, which is a little higher than the predicted RC of 10.879
Related Documents
Related Questions
If the resistors used for charging and discharging were the same, the charging anddischarging waveform would be ________.a. Symmetricalb. Nonsymmetrical
arrow_forward
Regarding behavior of inductors and capacitors in circuits, select the correctstatement -a) Voltage leads current in a capacitive circuit,b) Current leads voltage by 180 degrees in a pure capacitor,c) Voltage leads current by 45 degrees in a pure inductor,d) Current leads voltage in an inductive circuit,e) Current lags voltage in a pure capacitor by 90 degrees,f) Current lags voltage by 90 degrees in a pure inductor
arrow_forward
How does the internal resistance of the multimeter (in voltage setting) affect the charging/discharging rate of the capacitor. Explain.
arrow_forward
1. A purely resistive circuit the current is leading by 90° with respect to voltage.
2. A purely inductive circuit the current is lag behind the voltage by 90°.
3. A purely capacitive circuit the current is lead by 90° with respect to the voltage.
4. A capacitor element stored magnetic energy.
5. An inductor element stored electrical energy.
6. Resistor elements consume power.
7. Angle between current and voltage is called power.
8. The power factor angle for a purely resistive is zero.
9. The power factor angle for a purely inductive load is -90°.
10. The power factor of a purely capacitive is leading.
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning
Related Questions
- If the resistors used for charging and discharging were the same, the charging anddischarging waveform would be ________.a. Symmetricalb. Nonsymmetricalarrow_forwardRegarding behavior of inductors and capacitors in circuits, select the correctstatement -a) Voltage leads current in a capacitive circuit,b) Current leads voltage by 180 degrees in a pure capacitor,c) Voltage leads current by 45 degrees in a pure inductor,d) Current leads voltage in an inductive circuit,e) Current lags voltage in a pure capacitor by 90 degrees,f) Current lags voltage by 90 degrees in a pure inductorarrow_forwardHow does the internal resistance of the multimeter (in voltage setting) affect the charging/discharging rate of the capacitor. Explain.arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Cengage Learning