HW 1 Solution

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Civil Engineering

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Jan 9, 2024

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CE 317 Geotechnical Engineering Homework No. 1 Problem 1 The resuts of a sieve analysis for a soil sample are given in the table. Sieve Opening (mm) Mass Retained (g) 4.75 17 2 54 1 76 0.85 14 0.425 120 0.25 135 0.075 89 Pan 23 (a) Plot (to scale) the particle size distribution curve. (b) Comment whether the soil is well graded, poorly graded or gap graded. Because of the wide distribution of particle sizes, the soil is well graded. (c) Determine C U and C C . 𝐷𝐷 10 = 0.1 𝐷𝐷 30 = 0.3 𝐷𝐷 60 = 0.7 𝐶𝐶 𝑐𝑐 = 𝐷𝐷 30 2 𝐷𝐷 60 𝐷𝐷 10 = 0.3 2 0.7 × 0.1 = 1.2 𝐶𝐶 𝑢𝑢 = 𝐷𝐷 60 𝐷𝐷 10 = 0.7 0.1 = 7 (d) Determine percentages of gravel, sand and fines in the sample. Gravel (≥ 4.75): 3.2% Sand (4.75 > & (≥0.075 ): 92.4% Fines (0.075>): 4.4% 0 10 20 30 40 50 60 70 80 90 100 0.01 0.1 1 10 Passing (%) Particle diameter (mm)
CE 317 Geotechnical Engineering Homework No. 1 Problem 2 Figure 1 shows the particle size distribution of a soil sample drawn to scale. Using the Figure, (a) Calculate C U and C C . 𝐷𝐷 10 = 0.12 𝐷𝐷 30 = 0.53 𝐷𝐷 60 = 1.55 𝐶𝐶 𝑐𝑐 = 𝐷𝐷 30 2 𝐷𝐷 60 𝐷𝐷 10 = 0.53 2 1.55 × 0.12 = 1.5 𝐶𝐶 𝑢𝑢 = 𝐷𝐷 60 𝐷𝐷 10 = 1.55 0.12 = 12.9 (b) Using the plot, determine percentage of gravel, sand and fines in the sample. Gravel (≥4.75): 25% Sand (4.75> & (≥0.075): 67% Fines (0.075>): 8% Problem 3 The resuts of a sieve analysis for an inorganic soil sample are given in the table. If the If the LL and the PL of the soil sample are 38 and 18 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 80 2 68 0.85 54 0.425 33 0.075 18 𝐿𝐿𝐿𝐿 = 38 𝑃𝑃𝐿𝐿 = 18 𝑃𝑃𝑃𝑃 = 𝐿𝐿𝐿𝐿 − 𝑃𝑃𝐿𝐿 = 38 − 18 = 20 0 10 20 30 40 50 60 70 80 0.01 0.1 1 10 Percent Passing D/mm
CE 317 Geotechnical Engineering Homework No. 1 Retained: #4 #200 𝑃𝑃𝑃𝑃𝑃𝑃 20% 62% 18% SC: Clayey Sand Problem 4 The resuts of a sieve analysis for a soil sample are given in the Table. C c = 0.5 and C u = 5. If the LL and the PL of the soil sample are 55 and 40 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 45 0.075 9 𝐶𝐶 𝑐𝑐 = 0.5 𝐶𝐶 𝑢𝑢 = 5 𝐿𝐿𝐿𝐿 = 55 𝑃𝑃𝐿𝐿 = 40 𝑃𝑃𝑃𝑃 = 15 Retained: #4 #200 𝑃𝑃𝑃𝑃𝑃𝑃 55% 36% 9% GP-GM: Poorly-graded Gravel with Silt Problem 5 The resuts of a sieve analysis for a soil sample are given in the table. C c = 2 and C u = 6. If the LL and the PL of the soil sample are 20 and 14 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 95 0.075 65 𝐶𝐶 𝑐𝑐 = 2 𝐶𝐶 𝑢𝑢 = 6 𝐿𝐿𝐿𝐿 = 20 𝑃𝑃𝐿𝐿 = 14 𝑃𝑃𝑃𝑃 = 6 Retained: #4 #200 𝑃𝑃𝑃𝑃𝑃𝑃 5% 30% 45% CL-ML: Silty Clay
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CE 317 Geotechnical Engineering Homework No. 1 Problem 6 The resuts are given in the Table. C c = 2.2 and C u = 7.2. Classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 100 0.075 2 𝐶𝐶 𝑐𝑐 = 2.2 𝐶𝐶 𝑢𝑢 = 7.2 Retained: #4 #200 𝑃𝑃𝑃𝑃𝑃𝑃 0% 98% 2% SW: Well-graded Sand Problem 7 The resuts of a sieve analysis for a soil sample are given in the table. If the LL and the PL of the soil sample are 52 and 24 respectively, classify the soil according to USCS classification. Sieve Opening (mm) % passing 4.75 86 0.075 70 𝐿𝐿𝐿𝐿 = 52 𝑃𝑃𝐿𝐿 = 24 𝑃𝑃𝑃𝑃 = 28 Retained: #4 #200 𝑃𝑃𝑃𝑃𝑃𝑃 14% 16% 70% CH: Fat Clay
CE 317 Geotechnical Engineering Homework No. 1

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