StudySheetMBG353
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Subject
Chemistry
Date
Jan 9, 2024
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Name of
Media
Test For
Organism
Observation
Of Media
Results/Conclusion
Lactose
Broth
Lactose
1
Still Red, No Gas
formation
(-/-), fermentation -ve
2
Red to yellow
color, Bubble
trapped
(+/+), fermentation +ve
Glucose
Broth
Glucose
1
Still Red, no gas
formation
(-/-) fermentation -ve
2
Red to Yellow
Colour
Bubble trapped
(+/+) fermentation +ve
Starch Agar
Plate
Presence of
amylase
1
Clear Zone Around
Growth
(+,starch hydrolyzed +
ve amylase)
2
Blue Colour
Formed around
growth
-,starch not hydrolyzed
-ve amylase
Urea
Slant
Presence
Of urease
1
Bright Pinkish
purple on slant
+, urease +ve
2
No colour change
still yellow
-,urease -ve
Tryptophan
Broth
Test for
Indole
1
No change, still
work
-
2
Red Ring Formed
on top
+
MR
Broth
Mixed
Acid
Fermen
tation
1
No Red formation,
still Clear
-
2
Red to Light Red
colour
+
VP
Broth
Acetyl
Methyl
Carbinol
presence
1
Light Red colour
formed
+
2
No colour change,
still clear
-
Citrate
Citrate
1
Bright blue color
+
Slant
growth
on slant
2
No colour change,
Still Dark Blue
-
2. The IMVIC pattern for the bacterium E.coli as follows: ++--
In the same manner, write down the IMVIX patterns for organisms #1 and #2 from the
results in your table:
#1 - -++
#2 ++- -
1.
What is the function of Iodine in the starch hydrolysis test?
The function of Iodine is to react with starch to form a dark blue-colored complex.
If the area is clear, that means the organism broke down the starch that its due to
its production of amylase.
2.
What is the function of the Durham tube in the carbohydrate broth?
The function of the Durham tube is to detect the gas production.
Gas will be trapped in Durham tube and a bubble will form. The presence of a
bubble indicates fermentation and gas production of fermentation.
3.
a) Both the MR and VP tests determine whether a bacteria can use an organic
compound as a source of energy. What is this compound?
b) Even though the energy source is the same, the MR and VP tests determine
separate metabolic. What are the end products of these pathways for each test?
For the MR, it will be mixed stable acids (lactic, acetic, formic acid).
For the VP, it will be acetyl methyl carbinol.
4.
How is indole production detected in the indole test?
The presence of indole is present when a red ring is present at the surface of the
broth.
The presence of Indole when a red ring is formed at the top of the broth.
Starch Agar Plate:
Testing for Amylase
Typtophan Broth:
Test for Tryptophan broth transforms to Indole via the addition of kovac reagent
MRVP Broth
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Mixed Acid Fermentation
Metabolizes acids to other acids, from glucose
Lactic acid, Formic acid, etc
VP
Acetyl methyl, carbinol from glucose
Metabolizes pyruvic acid to other acids (ie. lactic, formic, and acetic acid), from
glucose
Lactate, Formic, etc
VP
Neutral products like Acetyl methyl carbinol and ethyl alcohol from glucose
metabolism
Interpretation of Results
Record your results in the table. Follow the interpretation guidelines below.
Carbohydrate Fermentation
Positive test for fermentation = acid production (yellow colour). You must also
record
whether or not gas is produced. Do this by checking the inverted tube for the presence
of a “good size” air bubble.
Negative test for fermentation = original red/orange colour (no acid has been produced).
Indicate your results as acid/gas.
Choose between:
+ / + (acid & gas), + / -
(acid but no gas),
or
- / - (no acid or gas)
Starch Hydrolysis
After incubation, place several drops of Gram’s iodine onto the bacterial cultures. Try to
cover both the culture and the surrounding media – ie.
aim for an ‘edge’.
Examine the plate for a clear zone surrounding the growth --- a positive result.
Negative result? – the media immediately surrounding the bacterial growth appears
deep blue.
Urea Hydrolysis
Following incubation, observe the tubes for growth and any colour changes. Positive reaction:
a deep
pink-purple colour.
IMViC Tests
For the indole test, add about 5 drops of Kovac’s reagent directly to the tubes of
tryptone broth. Do not shake the tube. Observe the tube immediately for the formation
of a bright red ring at the top of the broth (positive). If the top portion remains yellowish
or brownish, this is a negative result.
For the MR-VP tests, aseptically transfer 1 ml of each of the cultures to two separate
sterile plastic tubes.
One plastic tube will be used for the MR test, the other plastic tube
will be used for the VP test. Add the following test reagents to the tubes as indicated:
MR test:
Add 3 drops of the methyl red reagent to one tube. Positive result
= red colour
(indicates acid production)
VP test:
Add 15 drops of Barritt’s reagent A, mix well. Then add 5 drops of Barritt’s
reagent B, mix well. Let tube sit for 10-15 minutes, shaking often. Positive result
= light
red colour
For the citrate test, observe the tube for growth and colour changes. Positive result
=
growth + deep blue colour, Negative result
= no growth, media remains green
True motility
True motility (self-propulsion) may be due to structural appendages called flagella
(singular, flagellum). These are thin protein tubes attached to the bacterial cell wall
which rotate to provide propulsion for the cell. Not all bacteria have flagella; hence,
some types of bacteria are non-motile. Flagella are generally too thin to be seen in live,
unstained bacteria even at high magnification.
While it is not possible to see flagella using the light microscope, true motility can be
detected in live bacteria by observing rapid changes in cell position. True motility will
result in the bacteria spinning around (rotational movement) or traveling long distances
across the field of view (translational movement), while changing directions from time to
time.
Brownian motion and streaming
All microbes suspended in liquid medium will appear to move quickly back and forth. This type of
movement is called Brownian motion and is due to the random vibrations produced when the microbes
collide with water molecules. Brownian motion should not be confused with true motility, as even non-
motile organisms will display this type of behavior.
In this exercise you will examine live bacteria for motility using two techniques: the wet mount and the
hanging drop mount.
Motility Media
Motility media is a semi-solid growth media that is used to determine bacterial motility. It
is an example of an indirect method of motility testing. In addition to basic nutrients
motility media also contains:
•
0.5 % agar
– Routine solid media usually contains 1.5 % agar. The lower concentration of agar in
the motility media allows the bacteria to migrate away from the line of inoculation. The
presence of agar prevents diffusion of the cells, so that any distribution of bacteria throughout
the media results only from true motility.
triphenyl tetrazolium (TPT)
– tetrazolium salts are used as an indicator of bacterial
growth. During growth, bacteria are able to take up and reduce the tetrazolium,
producing an insoluble, red compound called
formazan
. In this way, the site of bacterial
growth in the tube can be easily identified by the presence of a dark red color.
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Hanging Drop Mount
1.
Place a small drop of bacterial culture in the middle of a cover slip.
2.
Using a toothpick spread a small amount of petroleum jelly around the outside of the
depression on a cavity slide.
3.
Place the cavity slide over the drop of culture so that the cavity is covering the drop, but not
touching the drop. Gently press down to form a seal.
4.
Carefully invert the slide so that the cover slip is now on the top and the drop of culture is
hanging in the depression.
5.
Follow the steps below for focusing on the bacteria.
Figure 1
: Top view of cavity slide with petroleum jelly distributed in thin lines around the depression
(shown as a circle).
Figure 2:
Method for placing the the cavity slide to capture the drop of culture inside the depression.
Note that the drop does not touch the cavity slide and maintains a convex shape.
Wet mount
1.
Place a single drop of culture on a clean, labelled slide.
2.
Cover with a cover slip.
3.
Follow the steps below for focusing on the bacteria.
Viewing Live Cells Under the Microscope
1.
Close the condenser diaphragm 90%.
2.
Begin with the 4X objective, then switch to 10X and finally 40X. Never use the
oil immersion lens to view live cells. Why?
3.
For the wet mounts, first focus on the edge of an air-bubble, or on the edge of
the cover slip. This edge will appear as a solid black line. For the hanging-
drop mount, first focus on the edge of the drop. The cells should now also be
in focus.
4.
Under 40X, look for small black circles or rods in the liquid. If you are focused
correctly and still cannot see the cells, try closing the diaphragm even more or
lowering the condenser in order to increase contrast.
5.
Note the shape and movement of the cells. Determine whether your
organisms show true motility or Brownian motion.
Interpretation of Results
Complete the provided worksheet for the organisms being examined.
Motility Media:
Notice the way the media has changed colour in the presence of growing bacteria. You
may notice that the bacteria have only grown in the vicinity of the path that was created
by your inoculating needle. What does this indicate?
Otherwise you might notice that
the entire tube has changed colour. What does this indicate?
The Endospore Stain
Introduction
Certain bacteria are able to form specialized structures called
endospores
. These
structures can resist a variety of chemical treatments, extremes of temperature, and dry
conditions. As such, they represent a type of survival mechanism for the cell. (Note that
spores are killed, however, by autoclaving which is why we autoclave all contaminated
materials in the laboratory).
Clostridium
and
Bacillus
are two genera which commonly
produce these structures. While what “triggers” vegetative cells to form endospores is
not completely understood, it appears to occur when the cells are stressed due to lack
of nutrients or water or when exposed to extreme environments.
The endospore staining technique is an example of a structural stain which is designed
to better allow the microscopic visualization of these structures. Two stains are used;
Malachite green (which stains the spores) and safranin (the counterstain which stains
vegetative cells and sporangia). Heat (steam) is used to enable the malachite green to
penetrate the thick spore coat.
Procedure
1.
Work in Pairs
2.
Obtain a plate containing the bacillus cultures. These will be shared between
you and your partner
3.
Prepare air-dried and heat-fixed smears of the two cultures.
4.
Fill a staining tray three-quarters with water and place on a hot plate.
5.
Heat the water to create a “steam bath”.
6.
Place small squares of paper toweling over the prepared bacterial smears
and place the slides on the wire portion of the staining tray.
7.
Immediately saturate the paper toweling with 5% malachite green stain.
8.
Do not let the stain “dry out”! Continue to add the malachite green as
necessary. Stain the preparations for 10 minutes.
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9.
Remove the staining tray from the hot plate and allow the slide to cool.
10.
Remove the paper toweling from the slides.
11.
Rinse the slides with water, then counterstain with safranin for approximately
1 minute.
12.
Rinse the slides with water and pat dry with bibulous paper.
13.
Examine the slides using the microscope and the oil immersion technique.
Interpretation of Results
Note that the spores may be detected within the cell (sporangium) in “younger” cultures
(at early stages of sporulation) or may appear alone (ie. outside the vegetative cells) in
“older” cultures (at later stages of sporulation). If the spores are found within the cells,
make a note of their position. This can be a taxonomic feature; ie. may aid in the
identification of the organism.
a.
central
b. terminal
c. sub-terminal
d. terminal with swollen sporangium
e.
extruded
Introduction
Disinfectants are chemical formulations that reduce the number of bacteria to a safe
level. Disinfectants do not sterilize, and are generally ineffective against bacterial
spores. The effectiveness of a disinfectant depends upon the concentration of the
chemical, the length of time of treatment, the number of bacterial cells initially present
and the susceptibility of the test organism. Common disinfectants include 70% alcohol,
chlorine bleach, soaps and detergents. Antiseptics are compounds that are used to
disinfect living tissues. 3% hydrogen peroxide, iodine, and 70% alcohol can be safely
used as antiseptics. Additionally, many (human) cultures have a knowledge and use of
compounds that can be used to treat infections or clean surfaces. Frequently, the
scientific and medical community “discovers” substances have been known for
centuries in some cultures. Often these “home-remedies” work due to trace compounds
that are naturally found in these substances.
The disc-diffusion assay is a method used to determine the efficacy of a compound to
destroy a test organism. It can be used to compare several different concentrations of a
disinfectant, or directly compare several types of disinfectant against one type of
microbe.
In this lab, you will investigate household disinfectants, and also a product you find at
home to treat bacteria/infections and bring a sample to lab. You will make a liquid
preparation of the compound and describe it to the class. Does this substance have
historical or cultural use? Please share. You will compare your compound with other
common household disinfectants.
Do not bring illegal substances, explosives, or otherwise dangerous or noxious
substances into school. Use common sense. If handling the compound requires
special PPE, handling, or equipment, do not bring it in
. If you’re unsure, please ask
your instructor for approval.
The disc-diffusion assay:
In this exercise, we will spread a “lawn” of bacteria on an agar plate to achieve confluent
growth. Sterile paper discs will be applied using sterile forceps. We will apply household
disinfectants and our home-remedy on these discs. During incubation, the disinfectants
will diffuse out of the paper disks into the surrounding medium forming concentration
gradients around the disks. Bacteria that are sensitive to a particular concentration of a
compound will not be able to grow within this area, which is called the zone of inhibition.
Most household products have proprietary formulations, and we do not know exactly
how much of the agent is in each product. Following incubation, the diameters of these
zones of inhibition can be compared to determine the relative sensitivity of the organism
to the substance.
Figure 1:
Arrangement of paper discs on the agar. Distribute your paper discs on to the
agar in a pattern similar to the one shown above. Prior to incubation, there will be no
growth visible (left). After incubation, you will see zones of inhibition of varying sizes
(right). More effective disinfectants will have larger zones.
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Figure 2
: The zone of inhibition is measured with a
ruler or calipers. Zone sizes can be recorded for
several compounds on one plate and compared.
Larger zones have greater inhibitory effect against
the bacteria spread on the plate.
Image from https://www.biologycorner.com/worksheets/case_study_bacteria_resistance.html
Antibiotic Sensitivity Testing
Antibiotics are chemical compounds produced by a microorganism which kill or inhibit
the growth of other types of microorganisms. In nature, bacteria and fungi produce
antibiotics as defensive mechanisms against competing microbes. Antibiotics can be
purified from microbes and are used as powerful medicines to combat bacterial
infections.
Penicillin was the first antibiotic discovered and remains the most widely used antibiotic
today. This antibiotic is produced by the mould, Penicillium. Penicillin kills bacteria by
attacking the protective peptidoglycan cell wall that surrounds a bacterial cell. Other
antibiotics, such as erythromycin and tetracycline attack bacteria by blocking protein
synthesis. A broad spectrum antibiotic is one that is capable of killing both Gram-
positive and Gram-negative cells. Antibiotics are extremely effective medicines because
they demonstrate selective toxicity. Selective toxicity means that the antibiotic will attack
and kill bacterial cells without harming human cells, by targeting structural and
molecular differences between bacterial and human cells.
In this exercise you will determine the sensitivity of Gram-positive and Gram-negative
bacteria to several common therapeutic antibiotics using the Kirby-Bauer disc diffusion
assay. In this assay, the test bacteria are spread evenly over the surface of a Mueller-
Hinton agar plate. Mueller-Hinton agar is the standard media used in antibiotic
sensitivity testing because it supports the growth of most pathogens and is low in
certain antibiotic inhibitors. Following inoculation, paper discs containing specified
dosages of various antibiotics are placed on the surface of the plate and the plate is
incubated at the appropriate growth temperature.
During incubation, the antibiotics diffuse out of the paper disks into the surrounding
medium forming concentration gradients around the disks. Bacteria that are sensitive to
a particular concentration of an antibiotic will not be able to grow within this area, called
the zone of inhibition. Following incubation, the diameters of these zones of inhibition
are measured and compared to standards to determine the sensitivity of the organism
to the antibiotics.
Figure 1
: On this incubated agar plate, bacteria has been spread uniformly across the
entire surface, creating what is sometimes referred to as a “lawn” (bacterial growth,
bacteria marked as “a”). Small discs of sterile paper have been applied to the surface
(discs marked as “b”) . The discs were dosed with a known quantity of antibiotic, or a
disinfectant solution. The antimicrobial compound diffused out of the paper, creating a
zone of inhibition where the bacteria could not grow (c).
Use-Dilution Assay
Introduction
As we learned this week in lecture, the Use-Dilution assay is used to determine the
effective concentration of a disinfectant compound on a simulated surface.
In this lab we will use one of the disinfectants and one of the bacterial species from our
disc-based assay last week and determine the appropriate concentration to use it at.
The AOAC Use-dilution method is an assay used to determine the efficacy of a liquid
disinfectant on an inanimate surface. In this test, objects called carriers are “exposed”
by submerging in fresh solution of bacteria. In a standard assay,
Staphylococcus aureus
(Gram positive, pathogenic),
Salmonella enterica
(Gram negative, pathogenic) and
Pseudomonas aeruginosa
(Gram negative, pathogenic) are used to coat the carriers.
These carriers are submerged in disinfectant solution for a defined time, and then
subsequently placed into tubes of non-selective growth media and incubated. To read
the result, the technician will examine the tubes of media for signs of growth.
A tube that has growth after incubation is considered a positive result, which indicates
that this treatment did not inhibit or destroy the bacteria. A full-scale use-dilution assay
will typically use 60 carriers, and the AOAC recommends the following as a passing
criteria for a disinfectant:
For each microbe, three complete and separate replicated trials should be done
For
S. aureus
, 0-3 positive carriers is a passing result
For
P. aeruginosa
, 0-6 positive carriers is a passing result.
For
S. enterica
, 0-2 positive carriers is a passing result.
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a)
b)
c)
Figure 1:
Simplified illustration of the Use-dilution assay. Carriers (penicylinders) are submerged in
bacterial culture, removed, and allowed to dry. (a) Note that the carriers should remain upright and not
laying down as depicted here. The carriers are then submerged in various dilutions of the disinfecant (b).
After the required time, the carriers are moved into sterile broth and incubated (c).
In our lab, we will perform a simplified version of the assay. We omit several steps and
experimental controls from official method, but overall process remains the same. We
will not be using pathogenic bacteria which are reccommended by the AOAC method.
Interpretation of Results
After incubation, observe the tubes for growth and record your results. Tubes that
remain clear demonstrate that the concentration was effective at either inhibiting or
destroying the bacteria. The tube with the most dilute concentration of disinfectant
indicates, roughly, the
Minimum Inhibitory Concentration (MIC)
of the disinfectant
against the bacteria used in this study
.
For any tubes that remained clear (no growth), there could still be viable cells that are
inhibited, but not killed. The
Minimum Bactericidal Concentration
is the concentration
that kills 99.9% of cells.
Consider: Is it possible to experimentally determine the MBC with the results of this
experiment?
1.
[2 marks]
Bacterial cultures grown in liquid broths often have characteristic patterns of growth.
Name and describe any two patterns of growth that might be observed in a test tube of inoculated
media.
One pattern of growth is turbid where the broth in the test tube appears to be cloudy
Another pattern of growth is Flocculent where prescence of large particles are dispersed throughout
the broth.
Sediment is when prescence of solid material at the bottom of te tube; may swirl up when tube is
gently tapped.
Pellicle is when thick or thin film covering the surface of the broth.
Ring of growth forms at the surface of the broth.
Turbid
(adj)
Flocculent
(adj)
Sediment
(noun)
Pellicle
(noun)
Ring(noun
)
2.
[9 marks]
Using the
EXPECTED
results from your three organisms and your lab notebook, fill in the
following table. If no result exists, write “NA”.
EC
SEP
BS/BT
Did the organism grow
on MSA? (Y/N)
N
Y
Y/N
Provide colour of
growth on MSA, if
present.
N/A
Clear Colourless
Opaque Beige matte
colour/ N/A
Did the organism grow
on MAC? (Y/N)
Y
N
N
Provide colour of
growth on MAC, if
N/A
N/A
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present.
Purple/Yellow
Did the organism grow
on blood agar? (Y/N)
Y
Y
Y
Provide name of
hemolysis reaction if
growth was present.
Beta Hemolysis
Beta Hemolysis
Alpha/Gamma
Hemolysis
3.
[11 marks]
Determine if the following statements are true or false and circle your
answer.
T
F
Aseptically transferring a loopful of nutrient broth to nutrient broth was used as a
negative control.
T
F
MSA detects the ability of Gram-positive organisms to ferment the sugar arabinose.
T
F
The use of a Bunsen burner creates a sterile environment surrounding Bunsen burner
flame.
T
F
Differential media limits the ability of organisms to grow allowing the technician to
determine if the organism is healthy.
T
F
We should always use the red portion of the flame when using a Bunsen burner as this
area is “red hot”.
T
F
In the selective/deiffential media lab, Nutrient agar was used as a positive control for
viability of the microorganisms used.
T
F
An ocular micrometer is used to measure cells and needs to be calibrated before use.
T
F
Phenol red is the pH indicator used in MacConkey Agar
T
F
Gram negative organisms can not retain the primary stain during gram staining due to
their thin cell membrane.
T
F
Isopropanol is used as the decolorizer during gram staining.
T
F
Gram positive cells appear pink in colour after the gram stain is complete.
Gram Negative Stains will absorb everything, but the crystal violet and Iodine
treatment since it will be washed away by the Ethanol treatment. It will be unable to
do so; because E.coli bacteria is not acidic.
Special Mention: The main use of Bunsen burner is not to produce an aseptic
environment, but to prevent upward flowing particles that could contain contaminants
or other types of bacteria from falling back into the sterile environment, that the
Bunsen burner created. Bunsen burner “locks” the sterile environment.
Total Magnification
1000x
Draw student’s observation
Gram Stain Result
Shape / Arrangement
Size (µm)
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Your Learning Points 3
Osiagwu, Chiemeka K
A reaction is carried out by mixing together a solution of K,CO, and a solution of Fe(NO,),.
K,Co, (aq) + Fe(NO,), (aq) - FeCo, (s) + 2KNO, (aq)
Assume the purple particles below each represent 1 mole of particles. Construct the balanced net
ionic equation by dragging the appropriote components into the gray boxes. Drag each unreacted
spectator ion along with its balancing coefficient into the blue box that represents the aqueous
solution.
Spectator ions
Balanced Net lonic Equation
+
FeCo, (s)…
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2. Go to NutritionCalc Plus and search for (USDA) beef, ground, pan browned, 30% fat. How many grams of total
fat əre provided in a 3 oz serving?
O 41 grams
O 6 grams
O 22 grams
O 15 grams
3. Go to NutritionCalc Plus and search for (USDA) beef, ground, pan browned, 30% fat and (USDA) beef, ground,
pan browned, 10% fat. Evaluate the nutrition information for a 3 oz serving. How does the saturated fat content of
the ground beef, 30% fat, compare to the saturated fat content of the ground beef, 10% fat?
O The ground beef, 30% fat, contains 4 more grams of saturated fat than the ground beef, 10% fat
O The ground beef, 30% fat, contains 8 more grams of saturated fat than the ground beef, 10% fat
O The ground beef, 30% fat, contains 6 more grams of saturated fat than the ground beef, 10% fat
O The ground beef, 30% fat, contains 2 more grams of saturated fat than the ground beef, 10% fat
4. Go to NutritionCalc Plus and search for (USDA) cheese, parmesan, grated. How many grams of total fat…
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Choose the best classification based on the chain length for the monosaccharide
shown.
80
CHO
H
OH
CH₂OH
$
4
2
R
Window Help
a
F
27 28
X G the pineal gland stimulates pro x Glycogen: Mammalian Energy X
%
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Question 18 of 20
A
6
MacBook Air
F6
Y
H
&
7
F7
U
*
*00
8
A) triose
B) tetrose
C) pentose
D) hexose
E) heptose
FB
1
(
9
K
☎ a s
C The structure for D-fructose is X
F9
O
O
OT
C
P
PI *
DOCX
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Please solve
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Read the page 1,2 and 3 carefully
Lab Report
Page:-2
If a yellow/green precipitate appears, this indicates that a reducing sugar is present. If the solution
You have to make two parts one is discussion/ analysis and another one is conclusion based on these remains blue, this means an absence of a reducing sugar. Some disaccharides (e.g. sucrose) and all
polysaccharides (e.g. starch) are not reducing sugars because they do not have free aldehyde
experiment procedure and results.
groups.
1. Discussion: In discussion, you have to explain the results that are given in page:-3 based on the
experiment procedure.
2. Conclusion: Conclusion must be in 2 or 3 lines.
EXPERIMENTI
Page:-1
DETECTING COMPOUNDS MADE BY LIVING THINGS
INTRODUCTION
Specific compounds are necessary for life processes such as growth, development, reproduction
maintenance and repair. Scientists have developed a series of chemical tests to determine the
presence and absence in food samples of the building blocks of living…
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Please don't provide handwriting solution
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Intestinal epithelial cells pump glucose into the cell against its concentration gradient using the Nat-glucose symporter. Recall
that the Nat concentration is significantly higher outside the cell than inside the cell. The symporter couples the "downhill"
transport of two Na* ions into the cell to the "uphill" transport of glucose into the cell.
If the Na* concentration outside the cell ([Na* lout) is 141 mM and that inside the cell ([Na* lin) is 19.0 mM, and the cell
potential is –52.0 mV (inside negative), calculate the maximum energy available for pumping a mole of glucose into the cell.
Assume the temperature is 37 °C.
AG gluc
||
10.5
Incorrect
kJ
mol
What is the maximum ratio of [glucose] in to [glucose lout
that could theoretically be produced if the energy
coupling were 100% efficient?
1.13
2700
7.90
3.7 x 10-4
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Part A
Select the end products for digestion of starch.
Check all that apply.
sucrase
galactose
lactase
glucose
maltase
maltose
fructose
sucrose
lactose
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Based on the graph below what is the carrying capacity for the species represented by the BLUE line with squares.
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Please don't provide handwritten solution .....
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I need the correct answer fast
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Iodine Test – (use all 8 samples- SAMPLE: 5% of lactose, sucrose, glucose, galactose,
( 10 ml each) |place 1 ml of the sample in a
fructose, maltose, starch and xylose
test tube. Add a drop of iodine. Observed color produced. Heat (direct heating) and
note change in color. Cool and record again the result.
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- File Edit Dashboard. app.101edu.co 2 View S History HO ** # Bookmarks H- 3 E D Profiles Tab Aktiv Chemistry Choose the best classification based on the chain length for the monosaccharide shown. 80 CHO H OH CH₂OH $ 4 2 R Window Help a F 27 28 X G the pineal gland stimulates pro x Glycogen: Mammalian Energy X % 5 P I T G W Question 18 of 20 A 6 MacBook Air F6 Y H & 7 F7 U * *00 8 A) triose B) tetrose C) pentose D) hexose E) heptose FB 1 ( 9 K ☎ a s C The structure for D-fructose is X F9 O O OT C P PI * DOCXarrow_forwardPlease solvearrow_forwardRead the page 1,2 and 3 carefully Lab Report Page:-2 If a yellow/green precipitate appears, this indicates that a reducing sugar is present. If the solution You have to make two parts one is discussion/ analysis and another one is conclusion based on these remains blue, this means an absence of a reducing sugar. Some disaccharides (e.g. sucrose) and all polysaccharides (e.g. starch) are not reducing sugars because they do not have free aldehyde experiment procedure and results. groups. 1. Discussion: In discussion, you have to explain the results that are given in page:-3 based on the experiment procedure. 2. Conclusion: Conclusion must be in 2 or 3 lines. EXPERIMENTI Page:-1 DETECTING COMPOUNDS MADE BY LIVING THINGS INTRODUCTION Specific compounds are necessary for life processes such as growth, development, reproduction maintenance and repair. Scientists have developed a series of chemical tests to determine the presence and absence in food samples of the building blocks of living…arrow_forward
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- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
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Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning