Synthesis of phenacetin lab report

the Infrared spectroscopy experiment  by using(FTIR) to identify the unknow compound from the list : EthanolIsoamyl acetateHexanal1-PropanolAnisaldehydeValerophenoneBenzoic AcidCyclohexanonemethyl iso-butyl ketoneBenzyl alcoholPropionaldehydeBenzaldehydePhenylacetic acid3-methylcyclohexanoneMethanolEthyl acetatePinacolonewhich compound is represented in the picture ?

Which set of H's in the phenacetin analog shown below correspond to HA/HA' in the 1H NMR spectrum shown below? Phenacetin1HNMR Chem235.12.fid 7.9 7.8 7.7 7.6 HA/HA' HB/HB' N A/A' 7.5 11 Group 1 one H3C 10 B 7.2 7.1 7.0 F1 (ppm) C/C' ZI 6.8 6.7 6.6 6.5 6 f1 (ppm) 5 [Choose ] [Choose ] CH3 Group 2 900 -800 700 -600 -500 400 -300 -200 100 -0 > -3800 3600 3400 3200 -3000 2800 2600 2400 -2200 -2000 1800 -1600 1400 - 1200 -1000 -800 600 -400 -200 -200

Can you please help me analyze these spectrum tests. The spectrum tests used were FTIR and 1H-NMR. the experiment is ester hydrolysis and 1,7-Dimethyl-heptanedioate, diethyl ether, KOH, and HCl were used.

Identify the compound from the compound bank based on the IR data

Please label the pea

Chapter 5: INTEGRATED SPECTROSCOPY PRO Compound 9 is a high-boiling liquid (boiling point 201'C), that reacts with alkoxide to yield spectra, along with C NMR data, are given below Elemental Analysis: C, 49.16; H, 4.13, contains manes an ether. The Mass, IR, and 'H NMR Mass Spectrum 91 65 172-170 170 180 190 200 100 I0 120 130 140 Is0 160 30 40 60 70 90 Infrared Spectrum Wave Number, cm 1 4000 3000 2500 1300 1200 1100 B00 700 2000 1500 1000 10 11 12 13 ' Η ΝMR Wavelength, microns 14 15 2. ppm, 5 "C Spectral Data: Structure: singlet, 130.1 ppm; doublet, 129.0 ppm, doublet, 127.8 ppm; doublet, 127.7 ppm; triplet, 29.3 ppm C2000 Brooks/Cole Publishing Company Absorbance

please fill out the chart or part of it based on the compound

Match the spectra to the structures: 3-bromotoluene and methyl 4-methoxybenzoate. CH 3 3-bromotoluene 200 Spectrum B 200 Br (ignore the CDCI3 signal) CH3O methyl 4-methoxybenzoate OCH3 Spectrum A 100 100

DEPT-135 DEPT - 90 DEPT - 45 T 200 CDS-03-521 180 4/5 160 140 - H₂CO T 120 75% + 100 ppm U 80 LL 60 40 20 0

can you validate the synthesis of isoamyl acetate through the esterification reaction of isoamyl alcohol and acetic acid using the attached Carbon-13 NMR spectra.

please help with this, i want to use this to study.     please draw a compound given the following info

Question and diagrams are attached. Thank you!

IH NMR spectrum of methyl-m-nitrobenzoate 'H nmr , 8: 8.86 (t, IH), 8.42(dd, IH), 8.37 (dd, IH). 7.67 (t, IH), 4.01(s, 3H). [t - triplet, dd - doublet of doublet, s- singlet] IR spectrum of methyl-3-nitrobenzoate

Need help solving 19

Draw the structure of the compound identified by the simulated 'H NMR and ¹3C NMR spectra. The molecular formula of the compound is C₁0H₁2O. (Blue numbers next to the lines in the 'H NMR spectra indicate the integration values.) ¹H NMR 1H 2H 2H 2H 2H 3H IT 111 10 8 6 8 (ppm) 13C NMR III. 220 200 180 160 140 60 40 20 100 8 (ppm) Deduce the structure from the spectra. Select Draw More CHO 2 Ć Rings 120 80 Erase Q 2 Q

Which hydrogen is more deshielded?? And why???

Properly annotate the NMR spectra of your unknown alcohol TFA ester. Make sure that you draw the structure of your parent alcohol on your spectra.

The H NMR spectra below is representative of what compound? Chem. shift Rel. area 2.26 1.50 7,04 1.00 1.00 7.37 TMS 10 4 O ppm Chemical shift (8) o-bromotoluene toluene p-bromotoluene m-bromotoluene 2. 6, Intensity

12. Consider the data below to answer the following questions. C₂H₁40 IR: MS: 1715 cm-¹ M* at m/z = 114, a-cleavage fragment at m/z=71 McLafferty rearrangement fragment at m/z = 86 ¹H NMR: 0.928 (6H, triplet) 1.59 8 (4H, sextet) 2.36 8 (4H, triplet) a) Calculate the degree of unsaturation for this compound. b) What functional group is indicated by the IR data? c) Propose a structure consistent with the spectral data presented above. d) Interpret the mass spectral data by showing both fragmentation patterns.

What are the errors in the following answer?

6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-

Use the spectra on page 5 of the activity and the structure below to assign the CNMR spectrum for propyl benzoate. d oby b 9 The peak at -168 ppm corresponds to carbon [Select] The small peak at ~130 ppm corresponds to carbon [Select] The peak at -66 ppm corresponds to carbon [Select] The peat at -22 ppm corresponds to carbon [Select]

Question for experiment: esterification reactions of vanillin: the use of NMR to determine a structure.

Use the spectrometric data below to elucidate a structure. They will be a combination of 1H NMR, 13C NMR, IR, and MS.

question 14