Spring 2023 CHEM 120-Det of Eq Constants-Post Lab Q-M-Th Final v2
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Spring 2023 CHEM 120
Determination of Equilibrium Constants Post-Lab Questions M-Th.
Make sure that your responses to these discussion questions is legible, if your responses are
illegible they will not receive credit. We suggest that you type your responses. Using the data
that you collected and wrote in your lab notebook during lab, organize your data into the
required tables or graphs. Make sure that you format the table properly, i.e. include a title and
labels for your columns, etc. Also make sure your plots are properly formatted and clearly
labeled.
1.
In a table, compile the
[FeSCN
2+
] for the serial dilutions
and the associated absorbance
values. Please make sure to include all proper labels and units. (2 points)
Solution
[SCN
-
]
initial
, (M)
[FeSCN
2+
]
eq
, (M)
Absorbance
Stock Solution
0.000200
0.000200
0.628
Dilution 1 (50.0%)
0.000100
0.000100
0.253
Dilution 2 (25.0%)
0.0000500
0.0000500
0.108
Dilution 3 (12.5%)
0.0000250
0.0000250
0.029
2.
In a second table, tabulate the absorbance values for the trial solutions with the
volumes of 0.0020 M Fe(NO
3
)
3
and 0.0020 M KSCN used. Please include all proper labels
and units. (2 points)
Sample Number
0.0020
M Fe(NO
3
)
3
(mL)
0.00200 M KSCN
(mL)
Absorbance
1
9.0
1.0
0.094
2
8.0
2.0
0.179
3
7.0
3.0
0.200
4
6.0
4.0
0.332
5
5.0
5.0
0.537
6
4.0
6.0
0354
7
3.0
7.0
0.324
8
2.0
8.0
0.273
9
1.0
9.0
0.148
3.
During lab, a student observed a darkening of the color in the “temperature” solution
when placed in an ice water bath. Based on these observations,
A.
Is the reaction Fe
3+
(aq) + SCN
–
(aq)
⇌
FeSCN
2+
(aq) endothermic or exothermic?
Exothermic, the color darkened indicating that the reaction is moving towards products. It
moves forwards in motion. Heat was a product.
B.
What would happen to the average value of K if the experiment were performed at a
higher ambient temperature? (3 points)
The increase of temperature means the reactants are favored. The average K
decreases.
4.
What changes did you observe in your “NaCl” and “NaH
2
PO
4
” solutions when you added
the reagents? Based on your observation, does the addition of these reagents shift the
equilibrium to the reactants side or the products side? (3 points)
For NaCl the solution became lighter and then basically clear slowly. NaH
2
PO
4
the
solutions became clear immediately. This means there was a shift towards reactants. To
make it at equilibrium again we have to shift towards product.
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Write the basic equilibrium equation for (CH3)2NH. Be sure to include the
proper phases for all species within the reaction.
1
U
+
4
2
0₂
Reset
(
H₂O
3
)
4 5
→
(CH3)2NH
OH-
5
6
6
(s)
2+
7
N
H3O+
3+ 4+
8 9 0
☐o
(1)
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H
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this is an ungraded question please help me.
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Table 1: Absorbance data recorded for five 0.200 M Fe(NO:)3 solutions at 20.0 °C
Beaker
0.0020 M
[FESCN2+] (M) Abs.
0.00200
SCN (mL)
Fe(NO3)3
(mL)
5.0
0.00
0.00 M
-0.001
2
5.0
2.00
8.0 x 10-5 M
0.278
5.0
3.00
1.2 x 10-4 M
0.415
4
5.0
4.00
1.6 x 10-4 M
0.555
5.0
5.00
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0.671
Part 1: y=3386x+0.0043
R^2=0.9991
Part II – Determining Concentration of an Unknown
Table 2: Best-fit line and Absorbance data of unknown solution
Best-fit line equation from Part I
Absorbance reading of unknown
0.338
Part III – Determining the Equilibrium Constant
Test tube
0.0020 M
0.00200
H20 (mL)
Abs.
Net Abs
Fe(NO3)3
(mL)
SCN-(mL)
1
3.00
0.00
7.00
0.000
2
3.00
2.00
5.00
0.119
0.119
3
3.00
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3.00
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3.
Consider the equilibrium that you studied in this experiment:
Fe (aq) + SCN (aq) FESCN²* (aq)
Direction of
shift (copy
from previous
Type of stress
(ex: reactant
Test
Tube
added, product
removed, temp
inc)
Explain how the direction of shift relieves the applied stress.
page)
Forward
Reaction
Forword
Reaction
3
Backword
4
Peaction
Backword
Reac Hon
Fonword
Reachion
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What is the value of the equilibrium constant Kc
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Calculating an equilibrium constant from a heterogeneous equilibrium...
Try Again
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Bis
2/5
Your answer is wrong. In addition to checking your math, check that you used the right data and DID NOT round any intermediate calculations.
Fluoride anion and hydronium cation react to form hydrofluoric acid and water, like this:
F (aq)+H3O (aq)→HF (aq) + H2O(l)
At a certain temperature, a chemist finds that a 9.9 L reaction vessel containing an aqueous solution of fluoride anion, hydronium cation, hydrofluoric acid, and
water at equilibrium has the following composition:
compound amount
F
0.146 g
H₂O
0.364 g
HF
4.96 g
892. g
H₂O
Calculate the value of the equilibrium constant K for this reaction. Round your answer to 2 significant digits.
K
8.4 x 10
C
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Activity 1: Complete Me!
Direction: Complete the following table. Write your answer on a separate sheet
of paper.
Equilibrium
Reaction
Effect
Keq
expression
Stress
Equilibrium
shift (encircle
your answer)
Forward
applied
(encircle
your answer)
Ha + Cla =
| 2HCI
Decreasing
the pressure
(increase,
decrease, no
change) in
the number
(HCIJ
Keq -
Backward
No Shift
of moles of
HCl(g)
(increase,
decrease, no
change) in
the volume of
Increasing
Fe,O +4 Ha
+ heat 2
Forward
Keq =
the
Backward
3Fe + 4H,O
temperature
No Shift
water vapor
collected
of (increase,
decrease, no
change)
the number
of moles of
NO
2NO + Oz
2NO + heat
Forward
Backward
No Shift
Addition
(NO,P
|NO]F|0,]|
Keq =
helium
Forward
H,CO» =
CO2 + H,O
Removal
of (increase,
decrease, no
change) in
the amount
Keq -
(H,CO,
CO2
Backward
No Shift
of H,CO,
(increase,
decrease, no
change)
in
amount of o,
(increase,
the volume of decrease, no
change)
in the
Increasing
the
Forward
Backward
No Shift
Keq=
temperature
the
4 NH3%g + 502
2 4NO+ 6…
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Complete Parts 1-2 before submitting your answer.
2
NEXT >
A 0.1000 M solution of a weak acid, HA, is 3.0% dissociated. Fill in the ICE table with the
appropriate value for each involved species to determine the unknown concentrations of all
reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
HA(aq) + H₂O(l) = HsO-(aq) + A-(aq)
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2
NEXT >
A 0.1000 M solution of a weak acid, HA, is 3.0% dissociated. Fill in the ICE table with the appropriate value for each
involved species to determine the unknown concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
HA(aq)
H₂O(1)
=
H,O*(aq)
A (aq)
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раper.
Effect
(encircle your shift (encircle
answer)
(increase,
Equilibrium
Reaction
Keq
expression
Stress
Equilibrium
applied
your answer)
Forward
H2 + Cl2 2
2HCI
(HCI]?
Keq-
Decreasing
the pressure decrease, no
Backward
change) in
the number
No Shift
of moles of
HCl(g)
(increase,
decrease, no
temperature change) in
the volume
of water
Increasing
the
Forward
FesO4(s) +4 H2)
+ heat 2
3Fee) + 4H2Og)
[H,0]*
[H2J*
Keq
Backward
No Shift
vapor
collected
of (increase,
decrease, no
change) in
the number
of moles of
NO
2NO + O2ia)
| 2NO2) + heat
(NO,
Keq
(NO]?(0;]
Addition
helium
Forward
Backward
No Shift
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1
2
NEXT
>
The pH for 6.1 x 104 M solution of cocaine, a weak base, is 9.60. Let cocaine be represented by
the generic base, B. Fill in the ICE table with the appropriate value for each involved species to
determine the unknown concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
B(aq)
+
H₂O(1)
0
6.1 × 10-4
9.60
-4.0 x 10-5
2.1 × 10-4
-2.1 × 10-4
5.7 × 10-4
3
=4
OH(aq)
+
BH*(aq)
RESET
-9.60
2.5 x 10-10
-2.5 x 10-10
4.0 × 10-5
-5.7 × 10-4
Stv
A
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Part A.
Name:
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Learning Goals
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2) Characterize the DES by finding the red: green ball ratio, Krg.
3) Design an investigation to test the effect of changing temperature, number of balls and
activation energy barrier has on the
Part 1: Play
Instructions:
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(https://phet.colorado.edu/en/simulation/legacy/reversible-reactions)
2) Play with the simulation. Click on EVERYTHING!
3) Answer the following questions:
I
1) Put some number of balls (>50) in one of the wells. In a table, record the number of
green and red balls in each well as a function of time. (Suggested time length: 5
minutes, suggested intervals: 15-20 seconds) Paste the table into this document.
(Google spreadsheet will work well for this.)
2) Paste in a graph of your data. Describe the shape of the graph and what it means in
terms of the red and green…
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Complete Parts 1-2 before submitting your answer.
1
2
NEXT
0.030 moles of a weak acid, HA, was dissolved in 2.0 L of water to form a solution. At
equilibrium, the concentration of HA was found to be 0.013 M. Fill in the ICE table with the
appropriate value for each involved species to determine the unknown concentrations of all
reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
HA(aq)
+
H₂O(l)
=
H3O+ (aq)
+
A-(aq)
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whether the forward or reverse reaction is favored.
AgCl → Ag* + Cl'Ksp=1.6 x 1010 Choose... -
A + B + CK=4.9 x 103 Choose...
CH3COOH + CH3C00" + H*Kg=1.8 x 10-5 Choose...
Alš+ + 30H Ksp=3.7 x 1015 Choose... -
Choose...
Reverse
Forward
Al(OH)3
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Complete Parts 1-3 before submitting your answer.
3
A 0.020 M aqueous solution of HCIO2 is prepared. Fill in the ICE table with the appropriate value for
each involved species to determine concentrations of all reactants and products..
Initial (M)
Change (M)
Equilibrium (M)
-2x
1.2 x 10-² - 2x
0
0.020 + x
1
HCIO₂(aq)
0.020
0.020 - x
+
2
H₂O(l)
1.2 x 10-²
0.020 + 2x
0.010
0.020 - 2x
H3O+ (aq)
+X
1.2 x 10-² + x
-X
+
NEXT
1.2 x 10-² - x
CIO₂ (aq)
RESET
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1.2 x 10-² + 2x
>
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equilibrium constant expression and solving it. Complete Parts 1-2
before submitting your answer.
2 H2O(g) 2 H2(g) + O2(g)
1
2
NEXT
At this temperature, the Kc = 2.4 × 10-3 and the equilibrium concentrations of H2O and
H2 are 0.11 M and 0.019 M, respectively. If [×] represents the equilibrium concentration
of O2, set up the equilibrium expression for Kc to solve for the concentration. Each
reaction participant must be represented by one tile. Do not combine terms.
Ко
=
=
2.4 × 10-3
RESET
[0.11]
[0.019]
2[0.11]
2[0.019]
[0.11]²
[0.019]²
[x]
[x]²
[2x]
[2x]2
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10.0
20.0
30.0
40.0
50.0
Use the References to ac
O A. 1.9x10-4 M/min
OB. 1.6x10-3 M/min
O C. 2.2x10-3 M/min
O D. 3.4x10-3 M/min
O E. 7.8x10-4 M/min
es it
For the reaction 2 SO3 →→→→2 SO₂ + O₂, calculate the average rate, A[SO3]/At, between 20.0 min and 40.0 min for the loss of SO3.
Time (min) [SO3], M [SO₂], M
[0₂], M
0.0
0.0
0.124
0.0
0.092
0.032
0.016
0.068 0.056 0.028
0.050
0.074 0.037
0.037
0.087
0.044
0.028
0.096
0.048
ded for this question
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Kindly answer all the items. Thank you!
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Predict the direction in which the equilibrium will lie for the reactionH2SO3(aq) + HCO3– (aq) <-> HSO3–(aq) + H2CO3(aq).Ka1(H2SO3) = 1 × 10–2; Ka1(H2CO3) = 4.2 × 10–7
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Pls help ASAP
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Consider the following reaction:
CO(g) + 2H2 (g) = CH3OH(g)
The reaction between CO and H2 is carried out at a specific temperature with initial concentrations of CO = 0.29 M and H2 = 0.50 M.At equilibrium, the concentration of CH, OH is 0.16 M.
Part A
Find the equilibrium constant at this temperature.
Express your answer using two significant figures.
Ke =
Submit
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