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6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-

6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-
Transcribed Image Text:6. (Chapter 15 - 47b) An aromatic compound, C9H12 has the following H NMR spectrum and a peak at 750 cmt in its IR spectrum. Answer the following questions. Chem. shift Rel. area 1.19 2.31 2.64 7.13 1.50 1.50 1.00 2.00 TMS 10 3 O ppm Chemical shift (6) 4(a). The IR peak at 750 cm in its IR spectrum indicate that the compound is. disubstituted = 4(b) The name of the compound is = Intensity-
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