Use the following spectroscopic data to work out the structure of an organic compound: IR Spectrum 4000 (quid film) 100 80 60 40 20 % of base peak 1715 3000 2000 1600 1200 800 V (cm³) M+ 74 Mass Spectrum 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH₂ CH₂t CHt proton decoupled solvent No significant UV absorption above 220 nm 1 200 160 120 80 40 ° 5 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) exchanges with D₂O T L 12 11 10 9 8 7 6 5 4 3 2 1 TMS L 8 (ppm)
Use the following spectroscopic data to work out the structure of an organic compound: IR Spectrum 4000 (quid film) 100 80 60 40 20 % of base peak 1715 3000 2000 1600 1200 800 V (cm³) M+ 74 Mass Spectrum 40 80 120 160 200 240 280 m/e 13C NMR Spectrum (50.0 MHz, CDCI, solution) DEPT CH₂ CH₂t CHt proton decoupled solvent No significant UV absorption above 220 nm 1 200 160 120 80 40 ° 5 (ppm) 1H NMR Spectrum (200 MHz, CDCI, solution) exchanges with D₂O T L 12 11 10 9 8 7 6 5 4 3 2 1 TMS L 8 (ppm)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:Use the following spectroscopic data to work out the structure of an organic
compound:
IR Spectrum
4000
(quid film)
100
80
60
40
20
% of base peak
1715
3000
2000
1600
1200
800
V (cm³)
M+
74
Mass Spectrum
40
80
120
160
200
240
280
m/e
13C NMR Spectrum
(50.0 MHz, CDCI, solution)
DEPT CH₂ CH₂t CHt
proton decoupled
solvent
No significant UV
absorption above 220 nm
1
200
160
120
80
40
°
5 (ppm)
1H NMR Spectrum
(200 MHz, CDCI, solution)
exchanges
with D₂O
T
L
12
11
10
9
8
7
6
5
4
3
2
1
TMS
L
8 (ppm)
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