Ex 4 - An Introduction to Volumetric Glassware -EDIT

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Mohawk College *

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116

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Chemistry

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Feb 20, 2024

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6

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CHEM CH116 Experiment 4 – Report Form Lab Report Name Student ID Procedure A-1: 10.00-mL Transfer Pipette Table A-1: Mass of Delivered 10.00-mL Samples of Distilled Water (three best trials) Trial Number Mass of Receiving Flask (g) Mass of Receiving Flask + 10.00-mL Sample (g) Mass of 10.00-mL Sample (g) 1 74.0531 84.0243 9.9712 2 84.0275 93.9528 9.9353 3 93.9548 103.9171 9.9623 Mean (average) mass: _____9.9546____ g Mean volume delivered (convert the mean mass from above to a volume value assuming 1 g = 1 mL): _____9.9546____ mL Is the above volume within the pipette specifications of 10.00 mL ± 0.02 mL? Explain. No. Ten milliliter (10 ml) pipette has a tolerance of 0 0.02 mL. So the accuracy is between 9.98 mL- 10.02ml range. Since the mean volume delivered is 9.95ml, the above volume is not within the pipette specifications. Procedure A-2: 1000.0-μL Micropipette Table A-2: Mass of Delivered 1000.0-μL Sample of Distilled Water (three best trials) Trial Number Mass of Receiving Flask (g) Mass of Receiving Flask + 1000.0-μL Sample (g) Mass of 1000.0-μL Sample (g) 1 3.22 4.22 1.00 2 4.22 5.22 1.00 3 5.22 6.22 1.00 Mean (average) mass: ______1.00______ g Mean volume delivered (convert the mean mass from above to a volume value assuming 1 g = 1 mL); _______1000____ μL Page 1 of 6
CHEM CH116 Experiment 4 – Report Form Is the above volume within the pipette specifications of 1000.0 ± 20.0 μL? Explain. Yes. One milliliter (1 mL) / 1000 μL pipette has a tolence of ± 20.0 μL. Since the measurement is 1000 μL , it is in the typical accuracy range/ within the pipette specifications. Procedure A-3: 250.0-mL Volumetric Flask Table A-3: Concentration and Conductivity of the Prepared NaCl(aq) Solution Mass of Weigh Boat + NaCl Sample (g) Mass of Weigh Boat + Residue (g) Mass of NaCl Sample (g) Meniscus Checked by the Instructor Concentratio n of NaCl Solution (g/L) Conductivity Reading (mS/cm) 5.2422 3.2149 2.0273 8.1092 16.00 Show how the g/L concentration of NaCl was calculated: g/L concentration of NaCl = 2.0273 g 250 ml × 1000 ml = 8.1092 g/L = 8.109 g/L Were you required to repeat this procedure? Explain. No. As the conductivity reading is accurate for the above concentration of NaCl solution , repeating the procedure was not required. Procedure A-4: 10.00-mL Mohr Pipette If you completed this procedure, then provide your results below. Table A-4: Mass of Delivered 4.00-mL Sample of Distilled Water (three best trials) Trial Number Mass of Receiving Flask (g) Mass of Receiving Flask + 4.00-mL Sample (g) Mass of 4.00-mL Sample (g) 1 2 3 Mean (average) mass: _______________ g Mean volume delivered (convert the mean mass from above to a volume value assuming 1 g = 1 mL): _______________ L Page 2 of 6
CHEM CH116 Experiment 4 – Report Form How was using the Mohr pipette different from using a transfer pipette? Explain Procedure B-1: Unknown Salt (NaCl) Solution Analysis and Density Calculations Table B-1: Density of Unknown Salt Solution using a 10.00-mL Transfer Pipette (three best trials) Trial Number Mass of Receiving Flask (g) Mass of Receiving Flask + 10.00-mL Sample (g) Mass of 10.00-mL Sample (g) Density (g/mL) 1 65.8331 76.7485 10.9154 1.091 2 76.7485 87.6232 10.8747 1.087 3 87.6232 98.5281 10.9049 1.090 Range of mass measurement : 10.9154 g - 10.8747g = 0.0407 g Sample density calculation: Trial 1 Density = mass ( g ) volume ¿¿ = 10.9154 g 10.00 mL = 1.091 g/mL Trial 2 Density = mass ( g ) volume ¿¿ = 10.8747 g 10.00 mL = 1.087 g/mL Trial 3 Density = mass ( g ) volume ¿¿ = 10.9049 g 10.00 mL = 1.090 g/mL Procedure B-2: Concentration Calculations by Using the Calibration Curve Table B-2: Concentration of the Salt (NaCl) (three best trials) Trial Number Density (g/mL) Concentratio n % (w/v) 1 1.091 12.51 Page 3 of 6
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CHEM CH116 Experiment 4 – Report Form 2 1.087 11.98 3 1.090 12.38 Sample concentration calculation: Trial 1 y = 0.0076x + 0.9959 1.091 = 0.0076x + 0.9959 1.091 – 0.9959 = 0.0076x 0.0951 = 0.0076 x x = 0.0951 0.0076 = 12.51 % (w/v) Trial 2 y = 0.0076x + 0.9959 1.087 = 0.0076x + 0.9959 1.087 – 0.9959 = 0.0076x 0.021 = 0.0076 x x = 0.0911 0.0076 = 11.98 % (w/v) Trial 3 y = 0.0076x + 0.9959 1.090 = 0.0076x + 0.9959 1.090 – 0.9959 = 0.0076x 0.0941 = 0.0076 x x = 0.0941 0.0076 = 12.38 % (w/v) Mean concentration: ______12.29____ % (w/v) Procedure B-3: Deviation Calculations Table B-3: Individual Deviations (three best trials) Trial Number Individual Deviation from the Mean, %(w/v) 1 0.22 2 0.31 3 0.09 Sample individual deviation calculation: Trial 1 Individual deviation = │calculated concentration - mean concentration│ = │12.51 – 12.29│ = 0.22 %(w/v). Trial 2 Individual deviation = │calculated concentration - mean concentration│ Page 4 of 6
CHEM CH116 Experiment 4 – Report Form = │11.98 – 12.29 │ = 0.31 %(w/v). Trial 1 Individual deviation = │calculated concentration - mean concentration│ = │12.38 – 12.29 │ = 0.09 %(w/v). Mean of Individual Deviations: ______0.20____ % (w/v) Page 5 of 6
CHEM CH116 Experiment 4 – Report Form Page 6 of 6
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