Quantitative 4 Conversions

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Feb 20, 2024

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Quantitative 4:Conversion from ppm to mg/m3 Use the following formula to complete the following. X ppm * MW = Y mg/m3 * 24.45 Note: For this equation the units do not cancel out. This is a condensed formula with several steps in the conversion process removed. Question 1 1 / 1 pts The PEL of Stibine is 0.5 mg/m3. What is this in ppm? (mol wt = 124.8) Correct! 0.098 2.55 5.10 0.5 10.21 X ppm * mw = Y mg/m3 * 24.45 X ppm * 124.8 = 0.5 mg/m3 * 24.45 = X ppm = 0.5 mg/m3 * 24.45 /124.8 = 0.098 ppm Question 2 1 / 1 pts The IDLH of Methyl isocyanate is 3 ppm. What is this in mg/m3? (mol wt = 57.1) Correct! 7.01 1.30 3.00 2.30 73.35 X ppm x mw = Y mg/m3 * 24.45

3 * 57.1 = Y mg/m3 * 24.45 (3 * 57.1)/ 24.45 = 7.01 mg/m3 Question 3 1 / 1 pts The PEL of Benzyl chloride is 5 mg/m3. What is this in ppm? (mol wt. = 126.6) Correct! 0.97 5.00 25.89 5.18 619.07 X ppm * mw = Y mg/m3 * 24.25 X ppm * 126.6 = 5 mg/m3 * 24.25 5 mg/m3 * 24.25 /126.6 = 0.97 Question 4 1 / 1 pts The PEL of Methyl isocyante (mol wt = 57.1) is 0.05 mg/m3. What is this in ppm? Correct! 0.021 2.3 0.12 0.05 70 X ppm * mw = Y mg/m3 * 24.45 X ppm * 57.1 = 0.05 mg/m3 * 24.45 X ppm = 0.05 mg/m3 * 24.45 / 57.1 = 0.021 ppm Question 5

1 / 1 pts The PEL of Cumene is 245 mg/ m3. What is this in ppm? (mol wt = 120.2) Correct! 49.8 1204.5 245.0 2.0 10.0 X ppm * MW = Y mg/m3 * 24.45 X ppm * 120.2 = 245 mg/m3 * 24.45 245 * 24.45 / 120.2 = 49.8 ppm Question 6 1 / 1 pts The PEL of Sulfuryl fluoride is 20 mg/ m3. What is this in ppm? (mol wt = 102.1) Correct! 4.79 0.20 83.52 4.18 20.00 X ppm * mw = Y mg/m3 * 24.45 X ppm * 102.1 = 20 mg/m3 * 24.45 20 * 24.45 / 102.1 = 4.79 ppm Question 7 1 / 1 pts The STEL of Sulfuryl fluoride is 10 ppm. What is this in mg/m3? (mol wt = 102.1) Correct! 41.76 10.00

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2.39 4.18 249.63 X ppm * mw = Y mg/m3 * 24.45 10 ppm * 102.1 = Y mg/m3 * 24.45 10 * 102.1 /24.45 = 41.76 ppm Question 8 1 / 1 pts The ceiling limit of Cumene is 75 ppm. What is this in mg/m3? (mol wt = 120.2) Correct! 368.71 15.26 4.92 75.00 39.19 X ppm * MW = Y mg/m3 * 24.45 75 ppm * 120.2 = Y mg/m3 * 24.45 75* 120.2 / 24.45 = 368.71 mg/m3 Question 9 1 / 1 pts The IDLH of Benzyl chloride is 10 ppm. What is this in mg/m3? (mol wt. = 126.6) Correct! 51.78 5.18 0.19

1.93 309.54 X ppm * mw = Y mg/m3 * 24.25 10 ppm * 126.6 = Y mg/m3 * 24.25 1 ppm *126.6 / 24.45= 51.78 mg/m3 Question 10 1 / 1 pts The IDLH of Stibine is 5 ppm. What is this in mg/m3? (mol wt = 124.8) Correct! 25.52 2.55 5.00 0.98 0.20 X ppm * mw = Y mg/m3 * 24.45 5 ppm * 124.8 = Y mg/m3 * 24.45 = 5 ppm * 124.8 / 24.25 = 25.52 mg/m3 (Will keep the highest of all your scores)

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