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Experiment 4 Enthalpy of Chemical Reactions GRADING RUBRIC EXPERIMENT 4 – LAB REPORT Worksheet (80 pts) Student name: ____Paulina Uribe___ Lab partner name: ___Britney Nguyen___ TA name: ___Rose___ Day & time of the lab: _02/15_ The lab report packet for this experiment should consist of the following in THIS ORDER: The lab report packet for this experiment should consist of the following: 1. (10 pts) IN-lab notebook pages 1.1. Experimental procedure 1.2. Recorded experimental values and the file name (as saved on your USB drive) 1.3. Observations if any were noted 2. (70 pts) The WORKSHEET 3.1 (22 pts) POST-lab data analysis 3.2 (10 pts) Figures of graphs with captions in the right positions. Tables with captions 3.3 (38 pts) Complete (full sentence) answers to the discussion questions (DQ; Provide well- rounded answers composed with complete sentences for full credit. If you need to refer to any of the data or tables produced during the “Data Analysis” section, clearly indicate their location within your answers for the graders to find them readily.) Complete this worksheet and turn in your digital lab packet to Canvas. Feel free to adjust space in this document as needed. The tables provided here are only an example of these may look like, feel free to replace the entire tables with your own creations using Excel, etc All tables and figures (graphs) must be accompanied by captions which should be positioned above tables and below figures. TURN IN the digital copy to Canvas on the due date by 11:59 pm. All electronic material must be completed by the due date to avoid late penalties. 1 P. Sotelo SP2023
Reaction 1 Reaction 2 Reaction 3 Reaction 4 Reaction 5 Time (s) Temperature °C Time (s) Temperature °C Time (s) Temperature °C Time (s) Temperature °C Time (s) Temperature °C 0 21.4 0 20.5 0 21.1 0 20.9 0 20. 15 21.4 15 20.5 15 20.9 15 20.8 15 20. 30 21.3 30 20.4 30 21 30 20.8 30 20. 45 21.3 45 20.4 45 21 45 20.8 45 20. 60 21.3 60 20.4 60 27.7 60 20.9 60 20. 75 21.2 75 20.5 75 33.3 75 20.7 75 20. 90 31.2 90 21.4 90 33.5 90 20.7 90 20. 105 34.6 105 21.4 105 33.4 105 20.7 105 20. 120 34.7 120 21.4 120 33.2 120 21.6 120 22. 135 34.8 135 21.4 135 33.2 135 23 135 35. 150 34.7 150 21.4 150 33 150 23.7 150 38. 165 34.6 165 21.6 165 33 165 24.4 165 38. 180 34.5 180 21.4 180 33 180 25.3 180 39. 195 26.3 195 39. 210 26.9 210 39. 225 27.9 225 3 240 28.5 240 3 255 29 255 38. 270 29.5 270 38. 285 30 285 38. 300 30.4 300 38. 315 30.5 315 38. 330 30.6 330 38. 345 30.9 345 38. 360 30.9 360 38. 375 31.1 375 38. 390 31.2 390 38. 405 31.3 405 37. 420 31.2 420 37. 435 31.1 435 37. 450 31.2 450 37. 465 31.3 465 37. 480 31.2 480 37. 0 20 40 60 80 100 120 140 160 180 200 0 5 10 15 20 25 30 35 40 Reaction 1 Time Temperature 0 20 40 60 80 100 120 140 160 180 200 19.5 20 20.5 21 21.5 22 Reaction 2 Time Temperture Highest temp: 21.6°C 0 20 40 60 80 100 120 140 160 180 200 0 5 10 15 20 25 30 35 40 Reaction 3 Time Temperature 0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 Reaction 4 Time Temperature 0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 40 45 Reaction 5 Time Temperature Highest temp: 34.8°C Highest temp: 33.5°C Highest temp: 31.3°C Highest temp: 39.2°C 2 P. Sotelo SP2023
3 P. Sotelo SP2023
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(22 pts) POST-LAB DATA ANALYSIS Post-lab should contain all work done outside of the lab, especially sample calculations for every type of math operation, as detailed in the DATA ANALYSIS in reference to DQs . You may choose to show your work in the post-lab notebook pages or typed in the data analysis and discussion portions of the worksheet. PART B: The Reaction of Hydrochloric Acid and Ammonium Hydroxide The following steps will guide you on how to proceed with data analysis using the software of your choice, Excel or LoggerPro: 1. If you choose to use Excel , open your file (.txt) from Part B in Excel. 4 P. Sotelo SP2023
a. Open Excel and select the “data” tab. b. Select the “From Text” action, and select the desired file to import. c. Excel should automatically identify your data as “Delimited”. Ensure that this is the selected file type and click “Finish”. d. Some versions of Excel will import data sets without retaining their numerical values (your data will not be erased, but Excel will treat numbers as letters). Data cannot be analyzed in this state. To convert the text into values, select a column, and click “Text to Columns” under the Data tab. Numbers that are successfully converted to values will be aligned on the right side of the cell. Generate a new graph for each reaction. e. Highlight the desired data set, select “Insert” from the task bar in the top left, then select “Insert Scatter”. f. From the “Design” tab, you can change the name of an axis by selecting “Add Chart Element”, then “Axis Titles”. g. Ensure that each graph (three total) plots Time on the x-axis and Temperature on the y-axis. h. Identify the maximum temperature value for each reaction and label it on its graph. i. Add an appropriate title to each graph by selecting “Add Chart Element”, then “Chart Title”. If you choose to use Logger Pro 3.14, open the (.txt or .qmbl) file saved on your USB drive from Part B. To generate a new graph for each reaction: Select “Insert” from the task bar in the top left, then select “ Graph ”. o You can change the name (and corresponding data of) an axis by simply left - clicking on it and selecting the desired option from the drop-down menu. To toggle between the temperature readings from each different reaction, click on the y-axis title (Temperature) to access the drop-down menu, then select “More” to see options for each individual run. o Ensure that each graph (three total) plots Time on the x-axis and Temperature on the y-axis. o Select “Analyze” and “Statistics” to add a statistics legend to each graph. o Add an appropriate title to each graph by right -clicking on the graph and selecting “Graph Options”. o Copy and paste all three graphs into the R&D section of the report. (2 pts/each) FIGURES (five total) Figure 1: (insert caption below the figure) 5 P. Sotelo SP2023
0 20 40 60 80 100 120 140 160 180 200 0 5 10 15 20 25 30 35 40 Reaction 1 Time Temperature Figure 1: The reaction of Hydrochloric acid and Sodium Hydroxide had a maximum temperature of 34.8°C at 135 seconds. Figure 2: 0 20 40 60 80 100 120 140 160 180 200 19.5 20 20.5 21 21.5 22 Reaction 2 Time Temperture Figure 2: The reaction of Sodium Hydroxide and Ammonium Chloride had a maximum temperature of 21.6°C at 165 seconds. Figure 3: 6 P. Sotelo SP2023 Highest temp: 34.8°C
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0 20 40 60 80 100 120 140 160 180 200 0 5 10 15 20 25 30 35 40 Reaction 3 Time Temperature The reaction of Hydrochloric Acid and Ammonium Hydroxide had a maximum temperature of 33.5°C at 90 seconds. Figure 4: 0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 Reaction 4 Time Temperature The reaction of Hydrochloric Acid and Magnesium Hydroxide had a maximum temperature of 31.3°C at 405 seconds. Figure 5: 7 P. Sotelo SP2023 Highest temp: 33.5°C Highest temp: 31.3°C
0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 40 45 Reaction 5 Time Temperature The reaction of Hydrochloric Acid and Magnesium Metal had a maximum temperature of 39.2°C at 180 seconds. 2. The net ionic equations for each of the three sub-reactions performed in Part B are shown below. Use the equation for Hess’s Law with the values in Table 5 to calculate the “theoretical” molar enthalpy of each reaction, and record the values in Table 6. Reaction 1: HCl (aq) + NaOH (aq) H 2 O (l) + NaCl (aq) + heat Net: H + (aq) + OH (aq) H 2 O (l) + heat Reaction 2: NaOH (aq) + NH 4 Cl (aq) NH 3 (aq) + H 2 O (l) + NaCl (aq) + heat Net: OH (aq) + NH 4 + (aq) NH 3 (aq) + H 2 O (l) + heat Reaction 3: HCl (aq) + NH 3 (aq) NH 4 Cl (aq) + heat Net: H + (aq) + NH 3 (aq) NH 4 + (aq) + heat Table 5 : Enthalpies of formation. Compound Δ H f ° (kJ/mol) OH (aq) –229.99 H + (aq) 0 H 2 O (l) –285.83 NH 4 + (aq) –132.51 NH 3 (aq) –80.29 Hess’s Law : ∆ H rxn ° = ∆ H f products ° ¿ ∆ H f reactants ° ¿ (3 pts) Table 6 : Calculated “theoretical” molar enthalpies of Reactions 1-3. Equation/Reaction Net Ionic Equation Δ H rxn (kJ/mol) 8 P. Sotelo SP2023 Highest temp: 39.2°C
1 H + (aq) + OH (aq) H 2 O (l) + heat -55.84 kJ/mol 2 OH (aq) + NH 4 + (aq) NH 3 (aq) + H 2 O (l) + heat -3.62 kJ/mol 3 H + (aq) + NH 3 (aq) NH 4 + (aq) + heat -52.22 kJ/mol 3. (3 pts) Calculate the amount of heat energy ( q ) in kJ that was absorbed by the surroundings, calorimeter and water, for each sub-reaction. Use 1.03 g/mL for the density of all solutions. Use the specific heat of water, 4.184 J/(g·°C), for all solutions. The calorimeter constant is 25.5 J/°C. Reaction 1: 6120 J Reaction 2: 502 J Reaction 3: 5660 J 4. (3 pts) Calculate the enthalpy change, ∆ H rxn , for each sub-reaction in terms of kJ/mol. Remember that the sign of q from the calorimeter represents the surroundings (+) and q from the reaction represents the system (−). Reaction 1: - 61.2 kJ/mol Reaction 2: - 5.02 kJ/mol Reaction 3: - 56.6 kJ/mol 9 P. Sotelo SP2023
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5. (2 pts) Using the ∆ H rxn values from Step 4 above and the balanced net ionic equations for Reactions 1 and 2, sum Reaction 1 and Reaction 2 appropriately (to yield the same net ionic equation as Reaction 3) to calculate the experimental molar enthalpy change for Reaction 3. Writing out the net ionic equations will help with this step. Reaction 1 = Reaction 2 + Reaction 3 -61.2 kJ/mol = -5.02 kJ/mol -56.2 kJ/mol 6. (2 pts) Using the “theoretical” Δ H rxn values calculated in Step 2 above, sum Reaction 1 and Reaction 2 appropriately to calculate the “theoretical” molar enthalpy change for Reaction 3 (the process for this step is analogous to that of Step 5 above). Reaction 1 = Reaction 2 + Reaction 3 -55.34 kJ/mol = -3.62 kJ/mol -52.2 kJ/mol 10 P. Sotelo SP2023
7. (1 pt) Determine the percent error (equation below) for the experiment using the answers obtained in Steps 5 and 6 above. Assume that a % error ≤ 15% is a reasonable result. 7.62% = | 52.22 kJ mol + 56.2 kJ mol 52.22 kJ mol | × 100 7.62% error PART C: The Formation of Magnesium Oxide Part B illustrated the additivity of reaction heats by utilizing Hess’s Law. In Part C, this principle can be applied to determine a heat of reaction that would be difficult to obtain by direct measurement – the change in enthalpy of formation of magnesium oxide from it elements in their standard states. This reaction is represented by the equation: (Equation 4) Mg (s) + ½ O 2 (g) MgO (s) This equation can be obtained by combining Equations 1, 2, and 3: (Equation 1) MgO (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 O (l) (Equation 2) Mg (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 (g) (Equation 3) H 2 (g) + ½ O 2 (g) H 2 O (l) The heats of reaction for Equations 1 and 2 will be determined from the experimental results. Δ H for Reaction 3 was not measured and is provided (–285.83 kJ). Equations 1, 2, and 3 will then be summarized to obtain the enthalpy of formation of MgO, Equation 4. If using Excel to import the .txt file saved on your USB drive from Part C. Generate a new graph for each reaction: 11 P. Sotelo SP2023
o Highlight the desired data set, select “Insert” from the task bar in the top left, then select “Insert Scatter”. o Ensure that each graph (two total) plots Time on the x-axis and Temperature on the y-axis. o Identify the maximum temperature value for each reaction and label it on its graph. o Add an appropriate title to each graph. o Copy and paste both graphs into the R&D section of the report If using Logger Pro 3.14 , open the file saved on your USB drive from Part C. Generate a new graph for each reaction: o Select “Insert” from the task bar in the top left, then select “Graph”. o Ensure that each graph (two total) plots Time on the x-axis and Temperature on the y-axis. o Add a statistics legend to each graph. o Add an appropriate title to each graph. o Copy and paste both graphs into the R&D section of the report Figure 4: 0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 Reaction 4 Time Temperature The reaction of Hydrochloric Acid and Magnesium Hydroxide had a maximum temperature of 31.3°C at 405 seconds. 12 P. Sotelo SP2023 Highest temp: 31.3°C
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Figure 5: 0 100 200 300 400 500 600 0 5 10 15 20 25 30 35 40 45 Reaction 5 Time Temperature The reaction of Hydrochloric Acid and Magnesium Metal had a maximum temperature of 39.2°C at 180 seconds. 8. (2 pts) Calculate the amount of heat energy ( q ) in kJ that was absorbed by the surroundings, calorimeter and water, for each sub-reaction. Use 1.01 g/mL for the density of the HCl solutions. Use the specific heat of water, 4.184 J/(g·°C), for all solutions. The calorimeter constant is 25.5 J/°C. Reaction 4: 4.66 kJ Reaction 5: 9.96 kJ 9. (3 pts) Calculate Δ H rxn for reactions #4 & #5 with respect to MgO and Mg (kJ/mol rxn). Record these values in Table 7. (hint: Determine ΔH and Determine the number of moles of MgO and Mg used.) 13 P. Sotelo SP2023 Highest temp: 39.2°C
10. (2 pts) In table 7, determine Δ H f for MgO: using the ∆ H rxn values from Step 10 above, sum Equations 4, 5, and 6 appropriately to calculate the experimental molar enthalpy change for Equation 7. Δ H f = –285.83 kJ for Equation 6. Table 7 : Reaction schemes for the formation of MgO. Equation Reaction Δ H rxn (kJ/mol) 4 MgO (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 O (l) -155 5 Mg (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 (g) -498 6 H 2 (g) + ½ O 2 (g) H 2 O (l) –285.83 7 Mg (s) + ½ O 2 (g) MgO (s) -628.83 155-498-285.33 = -628.83 kJ/mol 11. (1 pt) Determine the percent error for the answer obtained in Step 11. The “theoretical” value for Δ H f is –602 kJ/mol. Assume that a % error ≤ 15% is a reasonable result. % error = | theoretical value experimental value theoretical value | × 100 | 602 kJ mol + 628.83 kJ mo l 602 kJ mol | × 100 = 4.46% error 14 P. Sotelo SP2023
DISCUSSION QUESTIONS Provide well-rounded answers composed with complete sentences for full credit. If you need to refer to any of the data or tables produced during the “Data Analysis” section, clearly indicate their location within your answers for the graders to find them readily. 1. (4 pts) Briefly describe, in words, how the “theoretical” molar enthalpy was calculated for the sub-reactions in Part B . Include the results of these calculations for all three reactions. The theoretical molar enthalpy was calculated in Part B by finding the ∆ H rxn values of the three reactions using their respective net ionic equations and enthalpies of formation. The ∆ H rxn for the first reaction is -55.84 kJ/mol and for equation 2 it is -3.62 kJ/mol. The appropriate sum of the H rxn from Reaction 1 and Reaction 2 should equal to the ∆ H rxn of Reaction 3, which is -52.22 kJ/mol according to the values on the table. 2. (2 pts) During the experimental procedure, were the three sub-reactions in Part B endothermic or exothermic? How did you know that the reactions were endothermic or exothermic? The three sub-reactions in part B were exothermic. The initial and max temperatures of the three reactions were recorded on table 1, since the max temperatures for all three reactions were greater than the initial temperatures, there was an increase in the temperature and the system released heat. 3. (4 pts) Briefly describe how the amount of heat energy ( q ) absorbed by the surroundings was calculated for the sub-reactions in Part B . Include the results of these calculations for all three sub-reactions. To calculate the amount of energy absorbed by the surroundings, the equation q=mcΔT+cΔT must be used. To calculate the mass (m) for each sub-reaction the mL of the solution (100 mL) is multiplied by the density of the solution (1.03 g/mL), then that value is multiplied by the specific heat of water (c) which is 4.184 J/g·°C, then the product of that is multiplied by the ΔT of the reaction. The ΔT varies in each reaction, ΔT is found by subtracting the initial temperature of the solution from the max temperature. Finally, mcΔT is added to the multiplication of the calorimeter constant (second c) which is 25.5 J/·°C times the ΔT. Reaction 1 had a q value of 6120 J, reaction 2 had a q value of 502 J, and reaction 3 had a q value of 5660 J. 4. (4 pts) Briefly describe how the enthalpy change (Δ H rxn ) was calculated for the sub-reactions in Part B . Include the results of these calculations for all three sub-reactions. To calculate the enthalpy change for the sub-reactions the Joules of the reaction are divided by 0.1 mol because that represents the limiting reactant, the Joules must have a negative sign since the reaction was endothermic, then that is multiplied by the result of the division of 1 kJ by 10^3 kJ, that should equal to the enthalpy change in kJ/mol. Reaction 1 had a (Δ H rxn ) value of -61.2 kJ/mol, reaction 2 had a value of -5.02 kJ/mol, and reaction 3 had a value of -56.6 kJ/mol. 15 P. Sotelo SP2023
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5. (4 pts) Describe in detail how Reactions 1 and 2 were combined to determine the experimental molar enthalpy change for Reaction 3 in Part B . Include the results of this calculation. To determine the molar enthalpy change for reaction 3, one must remember that reaction 1= reaction 2 + reaction 3. If the molar enthalpy change for equation 3 was not known, a simple equation can be made using the values of reaction 1 and 2, -61.2 kJ/mol = -5.02 kJ/mol + x, where x represents the Δ H rxn for reaction 3, and solving for x. x= 56.2 kJ/mol 6. (3 pts) The value of Δ H rxn for Reaction 3 in Part B was determined by three different methods: (1) The “theoretical” value was determined in DQ1 , (2) the experimental value was determined using Hess’ Law of Summation in DQ5, and (3) the value was obtained directly by measuring the temperature change for Reaction 3 in DQ4. State these three values of Δ H rxn and compare them. Was the Δ H rxn obtained in Step 5 of the Data Analysis accurate (what was the %error)? Explain. Do the results of this experiment support Hess’s Law? The theoretical Δ H rxn value for reaction 3 is -52.22 kJ/mol, the experimental Δ H rxn value is 56.2 kJ/mol, and the Δ H rxn obtained directly is -56.6 kJ/mol. The value obtained in step 5 is not totally accurate with a percentage error of 7.62% but considering that anything <15% is a reasonable result, this is very close. The results of the experiment do support Hess’ law because the enthalpy change of the reaction is the approximately the same for all three values. 7. (3 pts) Were the reactions in Part C endothermic or exothermic? How did you know that the reactions were endothermic or exothermic? Why was it necessary to use two different concentrations of HCl in the reactions? The reactions in part C were exothermic because heat was released by the system and the solution rapidly increased in temperature. Increasing the concentration of HCl allows for more molecules to interact with the Mg, a higher concentration affects the reaction rate and the amount of energy produced in a certain time frame. 8. (6 pts) Describe in detail how the enthalpy of formation of magnesium oxide was determined ( Part C ). Include all necessary steps that were used to convert Δ T to Δ H rxn . Describe how Equations 4, 5, and 6 were combined to determine the experimental molar enthalpy change for Equation 7. Include the results of these calculations by inserting Table 7 from the data analysis here. The enthalpy of formation of magnesium oxide was determined by adding reaction 5 and six while subtracting reaction 4, this gave me a value of -628.83 kJ/mol -Reaction 4+ reaction 5 + reaction 6 = reaction 7 155-498-285.33 = -628.83 kJ/mol Table 7 : Reaction schemes for the formation of MgO. 16 P. Sotelo SP2023
Equation Reaction Δ H rxn (kJ/mol) 4 MgO (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 O (l) -155 5 Mg (s) + 2 HCl (aq) MgCl 2 (aq) + H 2 (g) -498 6 H 2 (g) + ½ O 2 (g) H 2 O (l) –285.83 7 Mg (s) + ½ O 2 (g) MgO (s) -628.83 9. (2 pts) How did the experimental value of the change in enthalpy of formation of magnesium oxide compare to the “theoretical” value ( Part C )? Do the results of this experiment support Hess’s Law? The experimental value of the change in enthalpy of formation of magnesium oxide was close to the theoretical one with a percent error of only 4.46%. The results of the experiment do support Hess’ law because the enthalpy values are very close to each other. 10. (3 pts) Define Δ H rxn and Δ H f . Which Part of the experiment demonstrated the change in enthalpy per mole of a reaction? Which Part of the experiment demonstrated the standard molar enthalpy of formation for a reaction? Δ H rxn is the amount of heat released or absorbed during a chemical reaction as reactants are being converted into products, this change is determined from the balanced equation. Δ H f is the change in enthalpy that occurs when one mole of a substance at standard conditions is created from its elements in their standard states. Part B of the experiment demonstrated the change in enthalpy per mole of reaction while Part C demonstrated the standard molar enthalpy of formation for a reaction. 11. (3 pts) Discuss various observed or reasonably predictable experimental errors. What impact did/would those errors have on your experimental data? (be specific) There are probably many experimental errors in this lab probably primarily coming from imprecise measurements of the solutions used, the amount of MgO and Mg was not exact, and the temperature probe could have not measured data correctly due to stirring. These possible experimental errors can affect our experimental data by showing an incorrect change in temperature leading to incorrect Δ H rxn and Δ H f values. 17 P. Sotelo SP2023