Lab 7 acid base

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California State University, Los Angeles *

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1200

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Chemistry

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Feb 20, 2024

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Sadie Garcia Professor Vodka Acid-Base Stoichiometry CHEM 1100
Purpose: This experiment's goal is to standardize the NaOH solution and use acid-base titration methods to calculate the molarity of an unknown sulfuric acid. Data: A B C Mass of weighing paper, g 0.357 4 0.351 3 0.375 7 Mass of weighing paper, g + HSO3NH2, g 0.746 2 0.702 1 0.639 Burnett readings, NaOH Initial, mL 0 0 0 Final, mL 33.1 30.2 39.6 Burett readings, unknown I II Initial, mL 0 10 Final, mL 21.7 31.7 Theories: By interacting with a solute that has a standard solution with a known concentration, an analytical technique known as acid-base titration may be used to measure the concentration of a solute inside a sample. Function of the Indicator: For this experiment, we utilized Phenolphthalein as the Indicator. In acid-base titrations, a weak acid is employed to calculate the concentration of our material. The hue of phenolphthalein will be lost when it is combined with acids. However, phenolphthalein will change to a reddish tint when combined with bases.
Equivalence point as opposed to the endpoint: The equivalence point is the point at which the moles of the acid and the base are exactly equal. when the substance has reached neutrality (7 pH). The endpoint is when the color changes, indicating that the titration is complete. The concentration represented as the number of mols per kilogram of solvent is referred to as molarity , and it is characterized by the words M or mols/L. Experimental Procedure: 1. In the first stage, we must make our sodium hydroxide solution: a. Take 30 to 35 mL of our liquid. into our 1 L bottle of 3 M NaOH. b. Then, add distilled water to the remainder of the 1-liter bottle. 2. Cleaning the burette is the next step. a. Use our soap to scrub the buret's inside. then use tap water to rinse the soap away. b. The buret must next be rinsed with distilled water (three 5 mL pieces) and a solution of sodium hydroxide (three 5 mL portions). c. Next, we must completely fill our buret (0 mL mark) without adding any NaOH solution. 3. Standardizing our sulfuric acid is necessary. a. We need to weigh 1 g of sulfamic acid on weighing paper using a triple beam balance. b. To the closest 0.0001g, weigh three pieces of the weighing paper. c. On the pre-weighed weighing sheets, distribute the 1 g of sulfamic acid. d. We must reweigh the sulfamic acid sample to the nearest 0.0001 g after dividing it among the sheets. 4. Our sulfamic acid must now be placed in a conical flask. a. Divide our sulfamic acids into three separate conical flasks.
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b. 25 mL of distilled water should be added to each of the three conical flasks. c. To the three conical flasks, add a few drops of phenolphthalein. 5. Titrate a. Titrate our NaOH solution into our sulfamic acid according to a standard method. The sulfamic acid solution will become pink as a result, going from translucent. b. To get the desired pink color we must gradually add titrate our solution into the sulfamic acid while sometimes stirring. c. If the solution is dark red, you have titrated too much and must restart. d. Calculate our NaOH solution's molarity. Repeat this procedure with the additional two conical flasks. e. For the three procedures , determine the molarity and average it out. 6. Titrate the unknown sulfuric acid solution a. Autopipette 20.00 mL of the unknown you received from your lecturer into the 250 mL Erlenmeyer flasks. b. Add a few drops of phenolphthalein to the Erlenmeyer flask containing the unknown substance. c. Titrate and standardized NaOH with the sulfamic acid method d. Calculate the sulfuric acid solution's molarity and report the average Results-Calculations: Calculations for NaOH and H2SO4 Mass of Sulfamic Acid = Mass- Masspaper + samplepaper (A): 0.7462-0.3574= 0.3888g (B): 0.7021-0.3513= 0.3508g
©:0.6390-0.3757= 0.2633g Average: 0.3574+0.3513+0.3757= 1.0844/3 = 0.3615g Volume of titrant (NaOH)= V final – V initial 33.1 - 0.0 = 33.1 30.2 – 0.0 = 30.2 39.6 – 0.0 = 39.6 Average: 33.1+ 30.2 + 39.6 = 102.9/3 = 34.3mL (0.0343) Ratio of titrant volume to sulfamic acid mass = V(t)/Mass sulfamic acid 0.0343L/0.3615g = 0.09488 L/g Molarity sulfamic acid Moles of sulfamic acid = 0.3615g*97.1g mol = 35.1 moles Molarity of sulfonic acid = 35.1 moles/0.09488L = 369 Molarity of NaOH Moles of NaOH = MNaOH (Vt) 3mols/L*0.0343 = 0.1029 moles of NaOH MNaOH = 0.3615g/(97.1g mol)*0.0343L = 0.1086 MNaOH Calculations for Sulfuric Acid solution: Volume of titrant: 21.7 - 0.0 = 21.7 31.7 – 0.0 = 31.7 Average: 21.7 + 31.7 = 53.4mL Conclusion: The experiment's objectives were fulfilled. By following the guidelines in the lab handbook, we were able to determine the molarity of our unknown. I can say that the titration was effective.