Lab 7 acid base
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Feb 20, 2024
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Sadie Garcia
Professor Vodka
Acid-Base Stoichiometry
CHEM 1100
Purpose:
This experiment's goal is to standardize the NaOH solution and use acid-base titration methods to calculate the molarity of an unknown sulfuric acid.
Data:
A
B
C
Mass of weighing paper, g
0.357
4
0.351
3
0.375
7
Mass of weighing paper, g + HSO3NH2, g
0.746
2
0.702
1 0.639
Burnett readings, NaOH
Initial, mL
0
0
0
Final, mL
33.1
30.2
39.6
Burett readings, unknown I II
Initial, mL
0
10
Final, mL
21.7
31.7
Theories:
By interacting with a solute that has a standard solution with a known concentration, an analytical technique known as
acid-base titration
may be used to measure the concentration of a solute inside a sample.
Function of the Indicator: For this experiment, we utilized Phenolphthalein as the Indicator. In acid-base titrations, a weak acid is employed to calculate the concentration of our material. The hue of phenolphthalein will be lost when it is combined with acids. However, phenolphthalein will change to a reddish tint when combined with bases.
Equivalence point as opposed to the endpoint: The equivalence point is the point at which the moles of the acid and the base are exactly equal. when the substance has reached neutrality (7 pH). The endpoint is when the color changes, indicating that the titration is complete.
The concentration represented as the number of mols per kilogram of solvent is referred to as molarity
, and it is characterized by the words M or mols/L.
Experimental Procedure:
1. In the first stage, we must make our sodium hydroxide solution:
a. Take 30 to 35 mL of our liquid. into our 1 L bottle of 3 M NaOH.
b. Then, add distilled water to the remainder of the 1-liter bottle.
2. Cleaning the burette is the next step.
a. Use our soap to scrub the buret's inside. then use tap water to rinse the soap away.
b. The buret must next be rinsed with distilled water (three 5 mL pieces) and a solution of sodium hydroxide (three 5 mL portions).
c. Next, we must completely fill our buret (0 mL mark) without adding any NaOH solution.
3. Standardizing our sulfuric acid is necessary.
a. We need to weigh 1 g of sulfamic acid on weighing paper using a triple beam balance.
b. To the closest 0.0001g, weigh three pieces of the weighing paper. c. On the pre-weighed weighing sheets, distribute the 1 g of sulfamic acid.
d. We must reweigh the sulfamic acid sample to the nearest 0.0001 g after dividing it among the sheets.
4. Our sulfamic acid must now be placed in a conical flask.
a. Divide our sulfamic acids into three separate conical flasks.
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b. 25 mL of distilled water should be added to each of the three conical flasks.
c. To the three conical flasks, add a few drops of phenolphthalein.
5. Titrate a. Titrate our NaOH solution into our sulfamic acid according to a standard method. The sulfamic acid solution will become pink as a result, going from translucent.
b. To get the desired pink color we must gradually add titrate our solution into the sulfamic acid while sometimes stirring.
c. If the solution is dark red, you have titrated too much and must restart.
d. Calculate our NaOH solution's molarity. Repeat this procedure with the additional two
conical flasks.
e. For the three procedures , determine the molarity and average it out.
6. Titrate the unknown sulfuric acid solution
a. Autopipette 20.00 mL of the unknown you received from your lecturer into the 250 mL Erlenmeyer flasks.
b. Add a few drops of phenolphthalein to the Erlenmeyer flask containing the unknown substance.
c. Titrate and standardized NaOH with the sulfamic acid method
d. Calculate the sulfuric acid solution's molarity and report the average
Results-Calculations:
Calculations for NaOH and H2SO4
Mass of Sulfamic Acid = Mass- Masspaper + samplepaper
(A): 0.7462-0.3574= 0.3888g
(B): 0.7021-0.3513= 0.3508g
©:0.6390-0.3757= 0.2633g
Average: 0.3574+0.3513+0.3757= 1.0844/3 = 0.3615g
Volume of titrant (NaOH)= V final – V initial
33.1 - 0.0 = 33.1
30.2 – 0.0 = 30.2
39.6 – 0.0 = 39.6
Average: 33.1+ 30.2 + 39.6 = 102.9/3 = 34.3mL (0.0343)
Ratio of titrant volume to sulfamic acid mass = V(t)/Mass sulfamic acid
0.0343L/0.3615g = 0.09488 L/g
Molarity sulfamic acid
Moles of sulfamic acid = 0.3615g*97.1g mol = 35.1 moles
Molarity of sulfonic acid = 35.1 moles/0.09488L = 369
Molarity of NaOH
Moles of NaOH = MNaOH (Vt)
3mols/L*0.0343 = 0.1029 moles of NaOH
MNaOH = 0.3615g/(97.1g mol)*0.0343L = 0.1086 MNaOH
Calculations for Sulfuric Acid solution:
Volume of titrant: 21.7 - 0.0 = 21.7
31.7 – 0.0 = 31.7
Average: 21.7 + 31.7 = 53.4mL
Conclusion:
The experiment's objectives were fulfilled. By following the guidelines in the lab handbook, we were able to determine the molarity of our unknown. I can say that the titration was effective.
Related Questions
Calculate the percentage CH3COOH in a sample of vinegar from the following data.Sample = 15.00 g, NaOH used = 43.00 ml ; 0.600 N H2SO4 used for back titration =0.250 ml ; 1.00ml NaOH is equivalent to 0.0315 g H2C2O4. 2H2O.
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5. A typical aspirin tablet contains 325mg of acetylsalicylic acid (HC9H7O04) which is
a weak acid. The Ka of this acid is 3.69 x 10-4.
a. Give the equation for dissociation of the weak acid HC9H7O4.
b. What is the initial concentration, in units of molarity, of acetylsalicylic acid if 2
tablets are dissolved in 500. mL of water?
c. What is the equilibrium concentration of all species of this solution of
acetylsalicylic acid?
d. What is the pH, pOH, and % ionization of this solution?
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To best accurately determine the molarity of a base, a scientist would need the following:
An Erlenmeyer flask, a weighed solid primary standard acid, and NaOH
A buret, a weighed solid monobasic base, and an indicator
A buret, a weighed solid primary standard acid, and an indicator
A buret, a weighed solid primary standard acid, and NaOH
A graduated cylinder, a weighed solid primary standard acid, and an indicator
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An aqueous solution is made of the diprotic acid H2A to a concentration of 0.15 M H2A.
Ka1 = 3.0 x 10-4 and Ka2 = 2.5 x 10-9
What is the [A2-] in this solution?
Your answer should have 2 significant figures and be expressed in scientific notation (i.e. 3.0 x 10-2 as 3.0e-2)
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Determine the initial concentrations of the species below, after the solutions are mixed.
Volume0.0350 MKMnO4(mL)
Volume0.0650 MH2C2O4(mL)
VolumeH2O(mL)
InitialConcentrationKMnO4(M)
InitialConcentrationH2C2O4(M)
(3 significant figures)
(3 significant figures)
1.00
1.00
18.00
2.00
2.00
16.00
3.00
3.00
14.00
4.00
4.00
12.00
5.00
5.00
10.00
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For question 5 could you find the best value and explain how you arrive to the best value please
thank you!
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Please answer Q1
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EXPERIMENT 5; Acid-Base Titration
A.
Trial 1
Trial
2
Trial 3
5.210 g
Mass of KHP
5.210 g
5.210 g
(C3H,O4)
Mole of KHP
Initial Burette
0.00
0.50
5.00
Volume NaOH (mL)
Final Burette
31.00
26.25
29.95
Volume NaOH (mL)
Total Volume of
NaOH (mL)
Moles of NaOH
Molarity of NaOH
(mol/L)
Calculate the average Molarity of NaOH
B. Titration of Vinegar (HC,H3O2)
A 2.352 g sample of Vinegar is titrated with 0.08751M
NaOH, and it requires 22.31 mL of NaOH to reach the
endpoint. Calculate the mass percent of acetic acid
(HC,H;O,) in the vinegar sample?
Hint for Calculation of Mass percent of Vinegar
(HC,H;O2)
1. Calculate mole of HC,H;O2 from concentration
(M) and volume of NaOH (L)
needed to titrate Vinegar
2. Calculate mass (g) of Vinegar from mole of
Vinegar
3. Mass % Vinegar = (calculated mass Vinegar/
2.352 g) X 100
C. A solution of malonic acid, H;C;H¿O4 ¸was
standardized by titration with 0.100 M NaOH solution.
If 20.76 mL of the NaOH solution were required to
neutralize completely 13.15 mL of…
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Gg.80.
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Suppose a 0.027 M aqueous solution of oxalic acid (H₂C₂O4) is prepared. Calculate the equilibrium molarity of C₂04. You'll find information on
the properties of oxalic acid in the ALEKS Data resource.
Round your answer to 2 significant digits.
M
0
S
?
OFF
olo
arrow_forward
2:10
2-
3C₂²-
+
1 2 3 4
N
Complete the balanced chemical
reaction for the following weak base
with a strong acid. In this case, write
the resulting acid and base as its own
species in the reaction.
NH3(aq) + HCl(aq)
(s)
Question 1 of 10
O
Reset
LO
5
OH
H₂O
6
CI
7
6
个
x H₂O
Tap here or pull up for additional resources
Submit
8
9
11
(aq)
O
H H3O+
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With the image attached write the objective of the experiment in one paragraph
Write more than one sentence please
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In a 0.60 mM aqueous solution of acetic acid (CH,CO,H), what is the percentage of acetic acid that is dissociated? You can find some data that is useful for
solving this problem in the ALEKS Data resource.
Round your answer to 2 significant digits.
| %
x10
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I am getting the wrong amount of sig figs for each equation, even though I am using the smallest amount given. May you please solve so that I can see the steps?
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300
37-613
*100 = $4.25
7. Base your calculations on the following balanced neutralization reaction:
H₂SO4 + 2NaOH → Na2SO4 + 2H₂O
a) If you have 35.0mL of 0.50M H₂SO4, how many moles of H₂SO4 do you have?
1.6285
b) If you have 45.0mL of 0.60M NaOH, how many moles of NaOH do you have?
c) Based on the balanced equation above, which reactant is the Limiting Reactant?
concept:
Explain your answer using either calculations
d) How many moles of the excess reactant will remain?
e) How many molecules of water are produced in the reaction above?
arrow_forward
Suppose a 0.027 M aqueous solution of oxalic acid (H₂C₂O) is prepared. Calculate the equilibrium molarity of C₂O You'll find information on the properties
of oxalic acid in the ALEKS Data resource.
Round your answer to 2 significant digits.
M
0.9
X
5
arrow_forward
Suppose a student performed a similar standardization titration experiment. Below is the calculated concentration of NaOH from each of their titrations.
Titration #1
Titration #2
Titration #3
The concentration of NaOH (M)
0.9554
0.9540
0.9551
Using the 3 concentrations, calculate the average concentration of the student's NaOH solution and calculate the ± error in parts per thousand (ppt). Show the complete calculation. Express your final answer in the form of average (with units) ± error in ppt.
arrow_forward
3. Titration: Strong Acid / Weak Base. (I warned you to be ready!) Here's the cool chart!
Analyte: 20.00 mL 0.100 M Hydrazine (N₂H4)
Hd
A: initial
Vertical (Value) Axis Title
0
B: half equivalence
C: equivalence
5
10
15
20
Titrant: mL of 0.100 M HCI added
25
20.00 mL of 0.100 M hydrazine (N₂H4, pKb = 5.77) is titrated with 0.100 M HCl.
a) Find the initial pH (point A) and the pH at the equivalence point (point C).
b) Find the pH at the half equivalence point (point B).
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You collected the following data from a titration experiment using a 0.123M standardized NaOH solution to titrate a 27.36 mL solution with an unknown Molarity concentration (M) of
sulfuric acid (H2SO4).
Initial
Final
Vol
Acid
Burette
Burette
Delivered
Concentration
Reading
(mL)
Reading
(mL)
(mL)
(M)
Trial 1
0.56
19.20
??
Trial 2
0.57
19.7
Trial 3
0.92
19.56
For just Trial 1, determine the Molarity concentration of the H2SO4 to 3 significant digits. Do not include units.
Answer:
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Please send me the questions in 20 minutes it's very urgent plz
arrow_forward
Suppose a student performed a similar standardization titration experiment. Below is the calculated concentration of NaOH from each of their titrations.
Titration #1
Titration #2
Titration #3
Concentration of NaOH (M)
0.9554
0.9540
0.9551
Using the 3 concentrations, calculate the average concentration of the student's NaOH solution and calculate the ± error in parts per thousand (ppt). Show the complete calculation. Express your final answer in the form of average (with units) ± error in ppt. use the right significant figures
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