lab 3
docx
keyboard_arrow_up
School
Life University *
*We aren’t endorsed by this school
Course
MISC
Subject
Chemistry
Date
Feb 20, 2024
Type
docx
Pages
3
Uploaded by MateDiscoveryGazelle32
Ronald House Lab 3 The Effect of an Electric Field on a Moving Charge Abstract
This experiment is about how positively and negatively charged particles respond in different
electric fields. During this experiment we will look at how charged particles move by utilizing an
electron gun, varied voltage amounts, and a phosphor screen.
Objective
1. To investigate the effect of a static electric field on various moving charges. Introduction
Several types of fields, both electric and magnetic, have been used in many applications to change the flow of charged particles. Until about the 1990s, one of the most common applications was the TV where a beam of electrons was manipulated using an electric field to produce an image on a phosphor screen. While you cannot easily see an electric field, you are surrounded by them and use technology every day that harnesses the power of electric fields: from your microwave to your cell phone.
Method
Procedure Section 1 1. Start Virtual Physics and select The Effect of an Electric Field on a Moving Charge from the list of assignments. The lab will open in the Quantum laboratory. 2. The experiment will be set up on the table. There is an electron gun on the left side of the as the source. 3. There is a phosphor screen on the right-hand side of the table to detect the charged particles. Turn on the phosphor screen by clicking on the green/red button. Record your observations in Question 1. 4. Depending on the size of your screen, you may want to drag the lab window down and left and
the phosphor screen window up and right to minimize the overlap. Click on the Grid button on the phosphor screen. Click once above the ones place on the Electric Field modifier meter. Observe the spot. Click a few more times above the ones place on the Electric Field, until the field is at 5 V. (If you mistakenly click between digits, it will move the decimal point. Click it to place it where it was originally and then click above the ones place.) Record your observations in
Question 2.
Procedure section 2 1. Increase the voltage on the source by clicking above the hundreds place on the electron gun voltage controller. You are not changing the number of electrons leaving the gun, just giving them greater kinetic energy. Record your observation in Question 4.
Procedure section 3
1. Test your prediction from Question 5, then zero out the Electric Field meter by clicking
on the appropriate digit buttons until the spot on the phosphor screen is centered again. 2. Double-click or click and drag the electron gun to move it to the Stockroom counter. Enter the Stockroom by clicking inside the Stockroom. Double-click the electron gun to move it back to the shelf. Double-click on the alpha source to select it and move it to the Stockroom counter. Click on the green Return to Lab arrow to return to the lab. Drag the alpha source from the Stockroom counter and place it on the table where the electron gun was originally placed (the middle spotlight). Click on the front of the alpha source to open the shutter. Record your observations in Question 6. 3. Change the unit for the Electric Field from V to kV by clicking once above the unit. This electric field is one thousand times stronger than what we used for the electron gun. Observe the spot as you increase the Electric Field strength from 0 kV to 5 kV. The movement is slight so pay
careful attention. Record your observations in Question 7.
Results
1. What do you observe when the electrons from the electron gun hit the phosphor screen and what do you think that shows? Spots of light appear around the table; this shows the positions where the charged particles are impacting. 2. What happens to the spot from the electron gun on the phosphor screen when the electric field is changed? When the magnetic field is turned on the spot on the phosphor screen glows bright when the higher intensity light is put on it. 3. What do you think would happen to the spot if you increased the voltage of the electrons leaving the electron gun? Why? When the voltage of the electrons is increased as it glows brighter the spot on the phosphor screen will shrink. This is because of the kinetic energy held by
electrons. 4. What happens to the spot on the phosphor screen when the voltage of the source is changed? Why does this happen? If the Voltage source is changed the deflection level will be altered. This is because the change in amount of voltage occurs in a change of the deflection between electrons and the phosphorus screen. 5. What do you think would happen to the spot now if you increased the voltage on the Electric Field modifier that the electron beam is passing through? Why?
The size of the spot should increase because there would be a higher level of deflection between the electrons shot from the gun and the phosphor screen. A higher voltage level still increases the magnitude of force being exerted on the electrons, which will also increase the amount of deflection occurring.
6. What appears on the phosphor screen when you use the alpha particle source? What charge do alpha particles have? When the alpha particle source is used, it causes a stream of electrons to appear on the phosphor screen. The charge of the alpha particles is +2
7. Which direction did the spot move when you increased the Electric Field? How does this compare with the direction of movement for the electron beam in the Electric Field? The spot moved right when we increased the electric field. This compares with the direction of movement for the electron beam in the electron field because it is the
8. Why does it take significantly stronger electric field strength to move the beam of alpha particles compared with the beam of electrons (beta particles)? it takes a significantly stronger electric field to move the beam of alpha particles compared to the beam of electrons because the charge of an alpha particle is twice as strong as the beta particle, meaning that it would need twice the energy to move the alpha particle.
Discussion This experiment was interesting to perform. I really liked doing the lab on beyond labz because it really felt like a can customize this experience like the real thing. This was a cool lab for me because I can physically see the effects of electric field on a moving charge, we had a large segment on electric field in a class before. Now I can use what I learned in physics now with other passed learned knowledge.
Conclusion I found this lab to be verry successful. When performing in this lab, I learned a better understanding of how Electric fields moving charge work and how the deflections change as the charges do. I did not find there to be many sources of error since the lab was performed on a computer and the lab records all data and everything was computed on the calculator. I did find I had to carefully read over the direction to not make a mistake in the lab experiment.
Your preview ends here
Eager to read complete document? Join bartleby learn and gain access to the full version
- Access to all documents
- Unlimited textbook solutions
- 24/7 expert homework help
Related Documents
Related Questions
Riboflavin, also known as vitamin B2, has a molar absorptivity coefficient of 3 x 10 ^3 . If the absorbance reading at a
Lmax = 350 nm is 0.90 using a 1 cm cell, what is the concentration of riboflavin in the sample.
a. 3.0 x 10^-4
b. 8.57
c. 1.80 x 10^3
d. 9.45 x 10-5
arrow_forward
Many ions form colored solutions when dissolved in water. For example, aqueous Cu2+ solutions are light blue and aqueous Ni2+ solutions look light green. These metals in particularare often found in stainless steel. Would you expect their presence in your samples to interfere in the spectrophotometric analysis of permanganate at 525 nm? Why or why not?
I think the answer is that I would expect the Cu2+ in my samples to interfere but not Ni2+ because the Ni2+ is green, signifying a higher wave length that the spectrometer wouldn't be able to pick up on because it was only set to 525 (blue-ish) where as the green is 530-ish. I just want to make sure thanks!
arrow_forward
Beaker Volume of KSCN
No
solution
1
0.50 mL
9.50 mL
Part I: Data for Calibration Graph
Accurate Concentration of potassium thiocyanate, KSCN stock solution: 0.001 M
0.2 M Fe(NO3)3- Iron(III)nitrate solution:
0.5M
Volume of HNO3
solution
0.2 M
Volume of 0.2 M
Fe(NO3)3 solution
10.00 mL
Absorbance
0.037
2
1.00 mL
9.00 mL
10.00 mL
3
2.00 mL
8.00 mL
10.00 mL
4
3.00 mL
7.00 mL
10.00 mL
0.122
0.313
0.547
5
4.00 mL
6.00 mL
10.00 mL
6
5.00 mL
5.00 mL
10.00 mL
0.791
0.868
arrow_forward
For the prelab today, all solutions were made using the procedure as outlined in your
lab manual. When the absorbances of the solutions were measured, the following
data were collected:
Part 1
Part 2
Solution
Absorbance
Solution
Absorbance
1
0.000
1
0.000
2
0.300
2
0.343
0.450
0.498
4
0.600
0.642
0.750
5
0.777
Use the data given above to calculate the average value of K for the equilibrium:
Fe* (aq) + SCN' (aq) - Fe(SCN)2*(aq)
Average K =
3.
4-
3.
arrow_forward
For my lab I had to find the unknown concentration of a solution. I found wavelength max of the potassium chromate. Then used that max to find the absorbtion for my sample dilutions. Based on my attached graph. Is my unknown concentration # making sense? Or did I make an error with the absorbance I wrote down in the lab. I did my calculations when I got home. They are correct, but my unknown concentration amount doesn't look like it will even be on the graph. Or am I wrong. Please advise and explain. Thank you
arrow_forward
22. Can you explain Beer's Law and how to solve problems which involve it?
arrow_forward
The best fit curve line to an absorbance vs. concentration plot for standard solutions of a dye
has a slope of 0.1815 mL/mg and intercept of 0.0477. A sample solution prepared of the same
dye has an absorbance of 0.464 at the wavelength used to establish the Beer's law plot. What
is the concentration of dye in the prepared solution?
Select one:
O a. 0.132 mg/mL
b. 2.29 mg/mL
O c. 0.464 mg/mL
O d. 2.82 mg/mL
e. 0.0365 mg/mL
Next page
Law Tutorial Part 2
Jump to...
Exp #9 - Laboratory Practical►
Worksheet
étv A
arrow_forward
Suppose a future student receives an copper sulfate solution unknown that is so darkly blue that no light can be transmitted through the sample and she can't determine the concentration. What should she do?
A) Discard the copper sulfate solution in the chemical waste container.
B) Dilute the copper sulfate solution with a carefully measured volume of water and try the measurement again.
C) Add a few millilters of water directly to the cuvette to get a solution with lighter color.
D) Ask her lab partner what their results were and just use the partner's data.
arrow_forward
The following absorbance values for four solutions with known MnO4 concentrations
were measured using a spectrophotometer:
Solution
1
2
3
4
[MnO4]
0.700 x 104 M
1.00 x 104 M
2.00 x 104 M
3.50 x 104 M
Absorbance
0.175
0.250
0.500
0.875
A. Using Microsoft Excel, plot a graph of Absorbance vs. Concentration of MnO4.
Write the trendline linear equation from the plotted graph.
B. Determine the slope of the graph and include its units.
C. Determine the concentration of an unknown MnO4 sample whose absorbance is
0.780.
arrow_forward
The protein content of the unknown samples were determined using BSA as standard. The
absorbance values of the standard solutions and samples are as follows.
BSA concentration (mg/mL)
Absorbance
0.000
20
0.110
40
0.192
60
0.248
80
0.325
100
0.400
120
0.460
a. What is the equation of the line?
b. Determine the protein concentration of samples in ug/mL.
Sample dilutions
1 in 14
A540
0.150
1 in 5
1 in 8
0.380
0.235
arrow_forward
A copper (II) sulfate solution of unknown concentration is placed in a colorimeter and an absorbance reading of 0.46 is recorded. Using the same solution cell, a 0.055 M of copper (II) sulfate gives an absorbance reading of 0.34. What is the concentration of the first solution?
A.
0.041 mol dm-3
B.
8.60 x10-3 mol dm-3
C.
0.35 mol dm-3
D.
0.074 mol mol dm-3
arrow_forward
Cathode Ray Discharge Tube Demonstration
An Exploration
(Because of the DANGER involved and the fragile nature of the device, this is a demonstration
rather than a true Exploration)
Background information:
Until recently, almost all televisions used a device known as the cathode ray tube, or CRT, to display
the images. In a cathode ray tube, the "cathode" is a heated filament (not unlike the filament in a
normal light bulb). The heated filament is in a vacuum created inside a glass envelope or "tube." The
"ray" is a stream of electrons that naturally pour off the heated cathode into the vacuum. The Cathode
Ray Tube is powered by an extremely high voltage DC current system and is dangerous! Electrons are
negative. The anode is positive, so the anode attracts the electrons pouring off the cathode. The
electrons hit the phosphorus screen and generate green photons, which we can see.
Safety:
The cathode ray discharge tube is not a toy and should be handled with a lot of precaution. An…
arrow_forward
please answer #10
arrow_forward
1. What factors are included in the Beer's law expression for determining how much light passes
through a liquid solution?
2. How would your test results be affected if you left fingerprints on the sides of the cuvette in line with
the light path of the spectrometer (or colorimeter)?
3. The chemical sunset yellow, also known as yellow #6, looks yellow. What color(s) must be
absorbed by this chemical?
RED
YELLOW
GREEN
WHITE
CYAN
MAGENTA
RGB System
(Transmitted light)
Additive color system
colored light
Rendered with Corel Draw 9
RGB pollete
40 M
iscalled
BLUE-VIOLET
4. Sunset yellow has an extinction coefficient of 20,000 M-1 cm-1 at a lambda max of 470 nm. What is
the concentration of a solution that has an absorbance of 0.893?
arrow_forward
1. Write the balanced chemical equation for the reaction of Na2S2O3 and HCl in aqueous solution.
2. Consider the following experiment. Twenty mL of a 1.00 M HCl solution is added to 100 mL
of a 0.100 M aqueous solution of sodium thiosulfate. After 40 seconds, the reaction has
produced enough sulfur to cause a decrease in the percent transmittance to 90%T. If this
reaction is repeated using 0.05 M sodium thiosulfate, how long should it take for the reaction
mixture to give a 90%T reading if the reaction is first order with respect to Na2S2O3? Second
order? Third order? Explain.
arrow_forward
© Macmillan Learning
The spectroscopic data in the table is generated with five solutions of known concentration.
Concentration (M)
0.0163
m =
0.0326
0.0652
0.130
0.261
Absorbance
0.1233
0.2143
0.5231
0.8887
2.008
Use a spreadsheet program, such as Microsoft Excel, to graph the data points and determine the equation of the best-fit line.
What is the slope of the linear regression line formed by these points?
M-1
arrow_forward
In today’s experiment, you will be using the following relationship:
A = εcl
What does the symbol l represent in this equation?
- concentration
- molar absorptivity
- path length of the solution
- charge
- absorbance
arrow_forward
You have prepared several dilutions of a standard compound. You measure the absorbance of each solution at
340 nm using a 1 cm cuvette and your results are listed in the table below. Determine the concentration of an
unknown sample with an absorbance of 0.085 at 340 nm.
Concentration (uM) Absorbance at 340 nm
2.
0.009
4.
0.020
0.061
16
0.111
32
0.189
arrow_forward
SEE MORE QUESTIONS
Recommended textbooks for you

Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning

Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Related Questions
- Riboflavin, also known as vitamin B2, has a molar absorptivity coefficient of 3 x 10 ^3 . If the absorbance reading at a Lmax = 350 nm is 0.90 using a 1 cm cell, what is the concentration of riboflavin in the sample. a. 3.0 x 10^-4 b. 8.57 c. 1.80 x 10^3 d. 9.45 x 10-5arrow_forwardMany ions form colored solutions when dissolved in water. For example, aqueous Cu2+ solutions are light blue and aqueous Ni2+ solutions look light green. These metals in particularare often found in stainless steel. Would you expect their presence in your samples to interfere in the spectrophotometric analysis of permanganate at 525 nm? Why or why not? I think the answer is that I would expect the Cu2+ in my samples to interfere but not Ni2+ because the Ni2+ is green, signifying a higher wave length that the spectrometer wouldn't be able to pick up on because it was only set to 525 (blue-ish) where as the green is 530-ish. I just want to make sure thanks!arrow_forwardBeaker Volume of KSCN No solution 1 0.50 mL 9.50 mL Part I: Data for Calibration Graph Accurate Concentration of potassium thiocyanate, KSCN stock solution: 0.001 M 0.2 M Fe(NO3)3- Iron(III)nitrate solution: 0.5M Volume of HNO3 solution 0.2 M Volume of 0.2 M Fe(NO3)3 solution 10.00 mL Absorbance 0.037 2 1.00 mL 9.00 mL 10.00 mL 3 2.00 mL 8.00 mL 10.00 mL 4 3.00 mL 7.00 mL 10.00 mL 0.122 0.313 0.547 5 4.00 mL 6.00 mL 10.00 mL 6 5.00 mL 5.00 mL 10.00 mL 0.791 0.868arrow_forward
- For the prelab today, all solutions were made using the procedure as outlined in your lab manual. When the absorbances of the solutions were measured, the following data were collected: Part 1 Part 2 Solution Absorbance Solution Absorbance 1 0.000 1 0.000 2 0.300 2 0.343 0.450 0.498 4 0.600 0.642 0.750 5 0.777 Use the data given above to calculate the average value of K for the equilibrium: Fe* (aq) + SCN' (aq) - Fe(SCN)2*(aq) Average K = 3. 4- 3.arrow_forwardFor my lab I had to find the unknown concentration of a solution. I found wavelength max of the potassium chromate. Then used that max to find the absorbtion for my sample dilutions. Based on my attached graph. Is my unknown concentration # making sense? Or did I make an error with the absorbance I wrote down in the lab. I did my calculations when I got home. They are correct, but my unknown concentration amount doesn't look like it will even be on the graph. Or am I wrong. Please advise and explain. Thank youarrow_forward22. Can you explain Beer's Law and how to solve problems which involve it?arrow_forward
- The best fit curve line to an absorbance vs. concentration plot for standard solutions of a dye has a slope of 0.1815 mL/mg and intercept of 0.0477. A sample solution prepared of the same dye has an absorbance of 0.464 at the wavelength used to establish the Beer's law plot. What is the concentration of dye in the prepared solution? Select one: O a. 0.132 mg/mL b. 2.29 mg/mL O c. 0.464 mg/mL O d. 2.82 mg/mL e. 0.0365 mg/mL Next page Law Tutorial Part 2 Jump to... Exp #9 - Laboratory Practical► Worksheet étv Aarrow_forwardSuppose a future student receives an copper sulfate solution unknown that is so darkly blue that no light can be transmitted through the sample and she can't determine the concentration. What should she do? A) Discard the copper sulfate solution in the chemical waste container. B) Dilute the copper sulfate solution with a carefully measured volume of water and try the measurement again. C) Add a few millilters of water directly to the cuvette to get a solution with lighter color. D) Ask her lab partner what their results were and just use the partner's data.arrow_forwardThe following absorbance values for four solutions with known MnO4 concentrations were measured using a spectrophotometer: Solution 1 2 3 4 [MnO4] 0.700 x 104 M 1.00 x 104 M 2.00 x 104 M 3.50 x 104 M Absorbance 0.175 0.250 0.500 0.875 A. Using Microsoft Excel, plot a graph of Absorbance vs. Concentration of MnO4. Write the trendline linear equation from the plotted graph. B. Determine the slope of the graph and include its units. C. Determine the concentration of an unknown MnO4 sample whose absorbance is 0.780.arrow_forward
- The protein content of the unknown samples were determined using BSA as standard. The absorbance values of the standard solutions and samples are as follows. BSA concentration (mg/mL) Absorbance 0.000 20 0.110 40 0.192 60 0.248 80 0.325 100 0.400 120 0.460 a. What is the equation of the line? b. Determine the protein concentration of samples in ug/mL. Sample dilutions 1 in 14 A540 0.150 1 in 5 1 in 8 0.380 0.235arrow_forwardA copper (II) sulfate solution of unknown concentration is placed in a colorimeter and an absorbance reading of 0.46 is recorded. Using the same solution cell, a 0.055 M of copper (II) sulfate gives an absorbance reading of 0.34. What is the concentration of the first solution? A. 0.041 mol dm-3 B. 8.60 x10-3 mol dm-3 C. 0.35 mol dm-3 D. 0.074 mol mol dm-3arrow_forwardCathode Ray Discharge Tube Demonstration An Exploration (Because of the DANGER involved and the fragile nature of the device, this is a demonstration rather than a true Exploration) Background information: Until recently, almost all televisions used a device known as the cathode ray tube, or CRT, to display the images. In a cathode ray tube, the "cathode" is a heated filament (not unlike the filament in a normal light bulb). The heated filament is in a vacuum created inside a glass envelope or "tube." The "ray" is a stream of electrons that naturally pour off the heated cathode into the vacuum. The Cathode Ray Tube is powered by an extremely high voltage DC current system and is dangerous! Electrons are negative. The anode is positive, so the anode attracts the electrons pouring off the cathode. The electrons hit the phosphorus screen and generate green photons, which we can see. Safety: The cathode ray discharge tube is not a toy and should be handled with a lot of precaution. An…arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningOrganic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning

Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning