1510, LAB 10, Maple, Daelin, FALL 2023
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1510
Subject
Chemistry
Date
Feb 20, 2024
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15
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This area is for TA only.
Lab 10, Atomic Emission o
Cell Colors
Your Point
All calculations mu
NAME:
Daelin x
Part 1
Table 1. Hydrogen emission data from Ocean Optics Spectrometer.
658.1
484.8
434.8
410.3
396.4
Use this data point
Hypothesis Testing
4
1
1
1
0
2
4
1
0
1
0
3
4
1
1
1
0
4
4
1
1
1
0
5
4
1
0
1
0
6
3
#N/A
#N/A
#N/A #N/A
m
#N/A #N/A
#N/A #N/A
#N/A #N/A
2
0
2
0
4
1
0
1
0
3
4
1
0
1
0
4
4
1
1
1
0
5
4
1
0
1
0
6
4
1
0
1
0
7
INPUT RAW DATA/ANSWERS TO QUESTIONS
INPUT CALCULATED VALUES, NO ROUNDING NECESSARY
INPUT CALCULATED VALUES, CORRECTLY ROUNDED OFF
Point of row
PLACE GRAPH IN THIS AREA
By checking the box with an X on the left side, I
Failure to sign this declaration will cost you 10%
λ (nm)
descending order
If a hypothesis is correct, a plot of 1/λ vs. 1/n
i
2
should be linear and n
f
(
Hypothesis #1
n
f
(assumed) = 1
n
i
= 2, 3, 4, 5, 6
n
i
s
m
R
2
n
f
(calculated)
Is n
f
(assumed) = n
f
(calc
Hypothesis #2
n
(assumed) = 2
n
i
3
#N/A
#N/A
#N/A #N/A
m
#N/A #N/A
#N/A #N/A
#N/A #N/A
2
#DIV/0!
2
2
4
1
0
1
0
4
4
1
1
1
0
5
4
1
0
1
0
6
4
1
0
1
0
7
4
1
1
1
0
8
3
#N/A
#N/A
#N/A #N/A
m
#N/A #N/A
#N/A #N/A
#N/A #N/A
2
0
2
0
Write the equation of the line at the 95% CI for the set that fits the Ryd
t=
3.182
2
0
0.0000
2
0
m
0.0000
2
0
0.00000
2
0
b
###
2
0
-2.045E-15
2
0
-5.7E-16
Ionization Energy and Energy Levels
h
c
IE (per atom)
3
0
6.62608E-34
2.997925E+08
-6.2E-09
n
f
(assumed) = 2
n
i
= 3, 4, 5, 6, 7
s
m
R
2
n
f
(calculated)
Is n
f
(assumed) = n
f
(calc
Hypothesis #3
n
f
(assumed) = 3
n
i
= 4, 5, 6, 7, 8
n
i
s
m
R
2
n
f
(calculated)
Is n
f
(assumed) = n
f
(calc
ts
m
ts
b
R
=-m (in SI units)
b
(in SI units)
Calculate the Ionization energy per atom
from nf
(
IE = hc·b
), where b is t
If n
f
is not 1, the IE calculated above is not the regular ionization energy.
to 0.75hcR as described in the help box. Calculation of IE per atom to the
3
0
IE(per atom) = hcb + 0.75hcR =
-2.000E+307
Avogandro's #
6.02214E+23
3
#NUM!
IE (per mole)
-3.83E-32
J/mol
n
h
2
0
α
6.62608E-34
2
0
4
6.62608E-34
2
0
3
6.62608E-34
2
0
2
6.62608E-34
2
0
1
6.62608E-34
Q1. Which of the three hypotheses fits the Rydberg
4
0
A: All of them fit because they are all reletively c
Q2.
4
0
A: The 3.96.4 wavelength has the most intense e
Q3.
4
0
A: It is very off from the literature value of 1.312
Q4.
4
0
A: Hydrogen atoms are controlled by n=2, while TOTAL POINTS:
#NUM!
POINTS POSSIBLE: 128
E
n
(per atom) = -hcR/n
2
. n= 1, 2, 3, ... (your R in units of m
-1
)
E
n
E
α
E
4
E
3
E
2
E
1
Examine the hydrogen emission spectrum on th
and nf values are associated with this emission?
How well does your ionization energy compare
What quantum numbers control the electronic electronic energy in the sodium atom?
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POINTS POSSIBLE: 128
of Hydrogen & Magnetic Susceptibility
ust be performed only by excel's formula
Maple
Email:
1. Hydrogen Emission
λ (nm)
0.25
658.1
156.96
0.11111
484.8
353.16
0.0625
434.8
627.84
0.04
410.3
981
0.0277778
396.4
1412.64
-4595.5999029822
1157.9653460209
b
1784.4891370739
227.3015185177
0.6885441752
323.3370518813
1.9921559115
Yes
λ (nm)
0.11111111
658.1
-1.91E-17
0.0265
484.8
-3.43E-17
0.04
434.8
-5.40E-17
0.0277777778
410.3
-7.79E-17
0.79131937
396.4
-1.06E-16
Save this file as 1510, Lab #, Last name, first name.xlsx, then go to blackboard and submit: Data Analysis --> Lab #: xxxx --> Browse for Local File --> Submit --> Ok
Rounding Rule: Round STD to 1 significant figure and round the mean to the same number of decimal places. It may be necessary to use the scientific notation if STD>1. How to: Highlight cell -> Right click -> Format Cell -> Number -> Scientific -> Change decimal places.
dm8166522@ohio.edu
I certify that I have not falsified data and that I have not plagiarized any part of this lab report. % points. (assumed) = n
f
(calculated) where n
f
(calculated) = (-m/b)
1/2
.
1/n
i
2
1/λ (nm
-1 )
s
b
culated)?
1/n
i
2
1/λ (nm
-1 )
0
0
b
0
0
0.79131937
0
2.8710173897
yes
λ (nm)
0.0265
658.1
-3.46E-17
0.04
484.8
-5.43E-17
0.0277777778
434.8
-7.82E-17
0.0204081633
410.3
-1.07E-16
0.015625
396.4
-1.39E-16
2.05E-15
-1.51E-16
b
4.93E-16
1.84E-17
0.8516958661
1.85E-17
3.6849698445
Yes
dberg equation
nm-1 J
s
b
culated)?
1/n
i
2
1/λ (nm
-1 )
s
b
culated)?
nm
-1
nm
-1
nm
-1
m
-1
m
-1
the y-intercept in m
-1
. . We need to add an energy term from nf to the ground state (n =1). This energy term is equal e ground state (nf = 1) here
𝟏/𝝀=((𝒎±𝒕𝒔_𝒎 ))/
𝒏
〖
_𝒊
〗
^𝟐 +(𝒃±𝒕𝒔_𝒃 )
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J
c
R
2.997925E+08
-2.045E-15
1.000E+00
2.997925E+08
-2.045E-15
1.000E+00
2.997925E+08
-2.045E-15
1.000E+00
2.997925E+08
-2.045E-15
1.000E+00
2.997925E+08
-2.045E-15
1.000E+00
g equation? Explain your choice.
close to the expected n final value
emmission and is associated with the higher n initial values. 2x10^6 J/mole
sodium atoms are controlled by n=2 also. TA feedback
E
n
(J)
he right. Which wavelength has the most intense emission? Which ni ?
e with the literature value of 1.312 x 10
6
J/mol?
energy in the hydrogen atom? What quantum numbers control the
This area is for TA only.
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
Excel Help:
Help for excel 2007 and up (xlsx)
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#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
=K43
#N/A
=K44
#N/A
=K45
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
#N/A
=-2E+307-J8
#N/A
=$J$80
#N/A
=$J$80
#N/A
=$J$80
#N/A
=$J$80
#N/A
=$J$80
#N/A
=SUM(B27:E32,B33,B38:E46,B47,B52:E60,B61,B66:E139)
=SUM(A:A)
Hydrogen Emission Spectrum
656
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