Assignment 006 - (1)

analyte concentration(C)(mg/ml) injection volume (ul) elution time (time) peak DAD signal(mAU) caffeine 1 1 4.67 302.85 aspartame 5 1 7.53 15.83 benzoic acid 1 1 8.14 89.98 saccharin 1 1 1.91 84.86 mixture(add everything above with 1:1:1:1 ratio)   1 4.47 69.58 How to get the concentration of the mixture in this case?

ESF X empt/quiz_start_frame_auto.d21?ou=9739790&isprv=&qi=11007766&cfql=0&dnb=0&fromQB=0&inProgress=1 ystems Question 5 (1 point) Ben starts walking along a path at 3 mi hr¹. Amanda starts jogging along the same path 1 hour later at 5 mi hr. After how much time jogging does Amanda catch up to Ben? 3.5 hr 2.5 hr 2 hr 16

urses/55527/quizzes/401369/take → # 3 Complete the data table using the calculation process you used to complete the previous question. Be sure to keep a copy of the completed table to include in the lab report for this experiment. $ Trial 1 Trial 2 Trial 3 Trial 4 Trial 5 4 1.00 M Acetic Acid volume HC₂H3O2 25.0 mL 25.0 mL 25.0 mL 25.0 mL 25.0 mL Q Search f5 % moles 5 f6 Mole Ratio 6 HC₂H3O2 : NaHCO3 3:1 2:1 *All values should contain three (3) significant digits. 1:1 1:2 1:3 U hp NaHCO3 Molar Mass: 84.007 g/mol moles fg * 99+ 8 a fg mass needed DO 9 f10 ► 11

With the image attached please do the calculations/calculate what is highlighted in yellow please Please also calculate - percent % error in molar mass - percent % error in pKa Please please please answer as fast as possible

Need complete solutions no need ai solutions okk just solve accurate

Use the calibration curve or linear regression equation to determine the concentration of FD&C blue dye No. 1 in Kool-aid. Food Coloring is 0.026 M in FD&C blue dye No. 1 7.5 x 10 -5 M is 29 mL -> 1000 mL

Ba(NO,l(aq) + K,SOlaq) Baso(s) + 2 KNOlaq) Volume Volume Trial 0.10 M Ba(NO)2 (ml) 0.10 M K,SO, (ml) Mass Baso4 (s) Limiting Reagent 50. 20. 0.46 50. 40. 0.92 3 50. 50. 1.15 4 50. 60. 1.15 50. 80. 1.15 • Question 8 Use the data to identify the limiting reagent for each reaction performed. V Trail 1 a. Neither/Both EV Trial 2 b. Baso4 EV Trial 3 C. KSO4 EV Trial 4 d. Ba(NO3)2 EV Trial 5 e. KNO3 Question Help: Message instructor I Calculator Submit Question • Question 9 Why is the amount of precipitate in the Data Table above the same in Trials 3 through 5? Edit Insert Formats B IVX x' A

An analysis where we know what analytes we are looking for is called An analysis where we do not know what analytes are in the sample is called a An example is A) untargeted, confirmation, targeted, Comprehensive drug screen B) targeted, confirmation, untargeted, comprehensive drug screen C) targeted, comprehensive drug screen, untargeted, confirmation analysis. An example is analysis. ▪ True or false: The purpose of the internal standard is to make quantitation of the analyte insensitive to injection errors

Sample Name: Test2 Acq. Operator : SYSTEM Sample Operator: SYSTEM Acq. Instrument : 6890N_GC-FID Injection Date Acq. Method Last changed : 11/11/2024 2:21:09 PM Location : 1 Inj Volume Manually : C:\CHEM32\1\METHODS \DEHYD351L.M : 11/8/2024 3:26:55 PM by SYSTEM Analysis Method : C:\CHEM32\1\METHODS\DEF_GC.M 11/12/2024 10:20:57 AM by SYSTEM FID1A, (CHEM351LITest2 2024-11-11 14-21-09.D) Last changed PA 1750 1500 1250 1000 750 500 250 0 1.226 1.338 1.393 1.445 1.513 0.2 0.4 0.6 0.8 1.2 1.4 1.6 1.8 min Area Percent Report Sorted By Multiplier : Signal 1.0000 Dilution 1.0000 Use Multiplier & Dilution Factor with ISTDS # [min] Signal 1: FID1 A, Peak RetTime Type Width ----|-------|----|-------|-------| Area [min] [PA*s] Height [PA] Area % |--------| 1 1.226 BB 0.0138 2.49083 2.96068 0.12408 2 1.338 BB 0.0173 6.06945 5.33509 0.30236 3 1.393 BV 0.0175 180.39203 156.04135 8.98645 4 1.445 VB 0.0147 17.87214 5 1.513 BB S 19.50680 0.89032. 0.0151 1800.55408 1899.02905 89.69679 Totals: 2007.37852…

Data Collection Kinetic Data Collection Time, t (s) Volume of added base (mL) First addition 40 0.50 Second addition 101 1.00 Third addition 160 1.52 Fourth addition 224 1.99 Fifth addition 278 2.49 Sixth addition 334 3.01 Seventh additlon 389 3.48 Calculations Concentration of NaOH stock solution: 0.01 M Concentration of t-BuCl stock solution: 0.2 M Volume of t-BuCl solution: 10 mL stock stock solution added to 25 mL acetone Table view List view Kinetic Data Volume of Moles of Amount of t-Bucl (mol) [-Buc] In[-BuC Time, t (s) added base added base (mL) (mol) First addition 40 0.50 Second additlon 101 1.00 Third addition 160 1.52 Fourth addition 224 1.99 Flfth additlon 278 2.49 Sixth additlon 334 3.01 Seventh addition 389 3.48 Use the data in the table above to plot In[t-BuC]]; vs time (s). Include labelled axis, a title, and a linear trendline. Upload your plot here.

20,18,2,4,15,15,10 Using these data, construct a 80% confidence interval for the average net change in a student's score after completing the course. Assume the population is approximately normal.  Construct the 80% confidence interval. Round your answer to one decimal place.

Instructions You are required to produce a short lab report using the information given in the accompanying document, ‘Lab report assessment_student data’. This document introduces an experiment, and also provides a set of experimental data for this experiment. You are required to use this data to perform steps 8 and 9 of the procedure. This includes calculations of a particular value, and then comparison to the true value. Consider any experimental errors when comparing calculated values and true values. Your report should be between 300 and 500 words (including all table contents and titles of tables and graphs). Your lab report should consist of three sections only: • Experimental • Results and Discussion • Conclusion You do NOT need to include an introduction section. Your experimental section should be written in appropriate lab report format, (passive voice, 3 rd person, in paragraphs). Your results and discussion section should contain the data presented in table format, and…

ter 9- CHEM A054 520 2 x Question 12 - Chapter 9 part 2 X с Chapter 9 part 2 Homework i 12 1 points ezto.mheducation.com/ext/map/index.html?_con=con&external_browser=0&launchUrl=https%253A%252F%25 8 01:46:13 eBook Hint Print References Mc Graw Hill CH6_Chem103 - Kenai Peninsu X + °C Determine the freezing point of an aqueous solution that is 0.584 m sucrose. Saved DU

26) The floor tiles in SE 27 are about 1 square foot and the lab is about 25 tiles wide and about 36 tiles from front to back. When the emergency shower was demonstrated, in 10. seconds the water in the trash can was about 1 foot deep. One student estimated this was 2.5 gallons. Estimate how deep the room will get in inches after a 15 minute shower. List 3 simplifving assumptions you make in this calculation rea L-36 Tile fiDw ill it cost2 The density of gold is 27l An artist plans to apply gold leaf to a painting with an area of 2.32 f? and a thickness of 1.50

[References) A method for the determination of the corticosteroid methylprednisolone acetate in solutions obtained from pharmaceutical preparations yielded a mean value of 3.7 mg mL with a standard deviation of 0.3 mg mL. For quality control purposes, the relative uncertainty in the concentration should be no more than 3%. How many samples of each batch should be analyzed to ensure that the relative standard deviation does not exceed 9% at the 95% confidence level? samples

Initial temp: 19.06 C trial 1: 0.5 M concentration trial 2 : 1.0 M concentration 200 mL of HCl and 200 mL of NaOH are combined in an insulated container. HCl = 0.5 mol/ml x 200 x 10^-3 ml = 0.1 mol NaOH =  0.5 mol/ml x 200 x 10^-3 ml= 0.1 mol H+(aq) + OH-(aq) - - -> H2O (l) ∆H H++ = 0, ∆H OH−− = -230 kJ/mol, ∆H H2O = -286 kJ/mol ∆H reactants = ∆H H++ + ∆H OH−− = -230 + 0 = -230 kJ/mol ∆H reactants = -286 kJ/mol - ( -230 kJ/mol) = -56 kJ/mol   For each trial, calculate how much energy is released during this reaction.

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