Week 8 HW

.xlsx

School

University of Maryland Global Campus (UMGC) *

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Course

PMAN 639

Subject

Business

Date

Jun 22, 2024

Type

xlsx

Pages

13

Uploaded by MateNarwhalPerson1141

The following data are the production units from a manufacturing line for the pas Week Monday Tuesday Wednesday Thursday Friday X Bar 1 12 15 8 7 10 10.4 2 6 9 11 13 7 9.2 3 15 11 9 6 12 10.6 4 8 7 6 11 14 9.2 5 20 12 10 5 14 12.2 6 13 10 9 8 12 10.4 7 10 14 11 8 5 9.6 8 10 15 17 11 9 12.4 X2 Bar 10.5 R Bar 8.625 A2 0.58 UCL Xbar 15.5025 LCL Xbar 5.4975 UCL R 18.1988 LCL R 0 D3 0 D4 2.11 Calculate the Averages from the weeks to collect the X bar Calculation Calculate the Ranges of the Data for the R Bar Calculations (MAX - Min) Calculate the Averages of both the Xbar and Rbar data to get X2 Bar and R Bar Calculate the UCL Xbar & LCL Xbar using the A2 which was from the Sample Size Calculate the UCL Rbar & LCL Rbar with the D3 and D4 values from sample size 1 2 0 2 4 6 8 10 12 14 16 18 X Ba
st 8 weeks. The manager wants to know if the process is stable and in control. Pro R Bar UCL XBAR LCL XBARX2 BAR UCL R LCL R 8 15.5025 5.4975 10.5 18.1988 0 7 15.5025 5.4975 10.5 18.1988 0 9 15.5025 5.4975 10.5 18.1988 0 8 15.5025 5.4975 10.5 18.1988 0 15 15.5025 5.4975 10.5 18.1988 0 5 15.5025 5.4975 10.5 18.1988 0 9 15.5025 5.4975 10.5 18.1988 0 8 15.5025 5.4975 10.5 18.1988 0 3 4 5 6 7 8 X BAR CHART ar UCL XBAR LCL XBAR X2 BAR 1 2 0 2 4 6 8 10 12 14 16 18 20
oduce Xbar and R charts and comment on the process R BAR 8.625 8.625 8.625 8.625 8.625 8.625 8.625 8.625 3 4 5 6 7 8 R BAR CHART R Bar UCL R LCL R R BAR
A project manager at Q Corporation has a commitment to deliver 200 cylinde a ) Calculate the process capability index (CP and CPk) and indicate if the p USL (60+1) cm = 61 cm LCL (60-0.5) cm=59.5 cm Standard Deviation (r) 0.5 Mean (m) 60.4 Cp = (USL - LSL) / 6r (61-59.5)/(6*.5) = .5 CPp for USL (USL-m)/(3*r) (61-60.4)/(3*.5) = .4 Cp for LSL (m-LSL)/3*r) (60.4-59.5)/(3*.5) = .6 Cpk = Min {CPu, CPI} (Min{.4,.6} = .4 The Process is not capable because CP is <1 b ) How many cylinders the PM should plan to produce in order for 200 of t % less than 59.5 = LSL-m/r = (59.5-60.5)/0.5 = -1.8 = 3.59% % more than 61 = (USL-m)/r = (61-60.4)/0.5 = 1.2 = 88.49% = 15.1% (100-88.4 Percentage beyond specification limit= (11.51+3.59)% = 15.1% Percentage within specification limit = (100-15.1)% = 84.9% Number of cylinders = t (84.9/100)*t = 200 236 Cylinders need to be produced to meet specification c ) What should be the standard deviation in order for the process to becom For the process to be cables CP >1 {(61 - 59.5)/6r}>1 6r >1.5 r>.25 Standard Deviation (r) needs to be >.25 for the process to be capable
ers to a customer. The internal diameter of these cylinders must be 60 centim process is capable. them to meet specification. 49%) me capable? Note the process is not centered.
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