W3ab_Mendelian Extensions_practice problems

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Modifications of Mendelian Ratios Extra Practice
In Guinea pigs, curly hair is recessive to straight hair. Guinea pigs can also have a condition called bowlegged, where their legs curve noticeably outward. Bowlegged-ness is a dominant lethal allele in that the homozygous dominant genotype is lethal before birth. Show the cross between a curly haired, bowlegged guinea pig and a heterozygous straight haired pig that is also bowlegged. What proportion of their offspring would you expect to be normal with curly hair?
In Guinea pigs, curly hair is recessive to straight hair. Guinea pigs can also have a condition called bowlegged, where their legs curve noticeably outward. Bowleggedness is a dominant lethal allele in that the homozygous dominant genotype is lethal before birth. Show the cross between a curly haired, bowlegged guinea pig and a heterozygous straight haired pig that is also bowlegged. What proportion of their offspring would you expect to be normal with curly hair? hhBb x HhBb 1/2 Hh (straight) 1/2 hh (curly) 2/3 Bb (bowlegged) 1/3 bb (normal) Normal, curly = 1/3 * 1/2 = 1/6
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In beets, white-colored root is recessive to red- colored root. A heterozygous plant will produce a pink-colored root. Two pink-colored plants are mated. What phenotypic ratio will be seen among the offspring?
In beets, white-colored root is recessive to red- colored root. A heterozygous plant will produce a pink-colored root. Two pink-colored plants are mated. What phenotypic ratio will be seen among the offspring? Phenotypes and ratios: 1 white: 2 pink: 1 red Rr X Rr
Also in beets, tall plants are dominant to dwarf plants. When the two pink-colored plants above were mated, a mix of tall and dwarf plants were found. The ratio of tall to dwarf was a 3:1 ratio. What proportion of the offspring were both pink-colored and dwarf? a. 1/2 b. 3/4 c. 1/8 d. 1/4 e. 3/16
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2. Also in beets, tall plants are dominant to dwarf plants. When the two pink-colored plants above were mated, a mix of tall and dwarf plants were found. The ratio of tall to dwarf was a 3:1 ratio. What proportion of the offspring were both pink-colored and dwarf? a. 1/2 b. 3/4 c. 1/8 d. 1/4 e. 3/16
If a female with type AB blood decides to have children with a male with type O blood, which of the following blood types could their children possibly have? a. A and B b. AB and O c. A, B, and O d. A, B, and AB e. A, B, AB and O
If a female with type AB blood decides to have children with a male with type O blood, which of the following blood types could their children possibly have? a. A and B b. AB and O c. A, B, and O d. A, B, and AB e. A, B, AB and O
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In rabbits, the C gene encodes a protein responsible for coat color patterning. The following alleles are found at the locus, shown in order of dominance: wild type (C) > chinchilla (c ch ) > Himalayan (c h ) > albino (c). Give the genotype of the parents in the following situations: Parents Wild type Chinchilla Himalayan Albino Chinchilla x Himalayan 0 4 2 1 Wild type x Himalayan 3 0 3 0
In rabbits, the C gene encodes a protein responsible for coat color patterning. The following alleles are found at the locus, shown in order of dominance: wild type (C) > chinchilla (c ch ) > Himalayan (c h ) > albino (c). Give the most likely genotype of the parents in the following situations: Parents Wild type Chinchilla Himalayan Albino Chinchilla x Himalayan 0 4 2 1 Wild type x Himalayan 3 0 3 0 1.c ch /c x c h /c 2. C/c h x c h /c h or c h /c
In chickens, the form of the comb can vary and is controlled by two genes designated as P and R . The following interactions produce various phenotypes: • If at least one dominant allele is found only at the P locus, a pea-type comb is produced. • If at least one dominant allele is found only at the R locus, a rose-type comb results. • At least one dominant allele at both loci produces a walnut-type comb • Homozygous recessive genotype at both loci produces a single-type comb. Which of the following represents a mating between a pure-breeding pea-type chicken and a pure-breeding rose-type comb chicken. a. PPRR x pprr b. PPrr x ppRR c. Pprr x ppRr d. PpRr x pprr
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In chickens, the form of the comb can vary and is controlled by two genes designated as P and R . The following interactions produce various phenotypes: • If at least one dominant allele is found only at the P locus, a pea-type comb is produced. • If at least one dominant allele is found only at the R locus, a rose-type comb results. • At least one dominant allele at both loci produces a walnut-type comb • Homozygous recessive genotype at both loci produces a single-type comb. Which of the following represents a mating between a pure-breeding pea-type chicken and a pure-breeding rose-type comb chicken. a. PPRR x pprr b. PPrr x ppRR c. Pprr x ppRr d. PpRr x pprr
Duroc Jersey pigs are typically red, but a sandy variation is also seen. When two different varieties of true-breeding sandy pigs were crossed to each other, they produced F1 offspring that were red. When these F1 offspring were crossed to each other, they produced red, sandy and white pigs in a 9:6:1 ratio. Explain this pattern of inheritance by assigning alleles and giving genotypes of the two true-breeding pigs, the F1 pigs and their F2 progeny.
Duroc Jersey pigs are typically red, but a sandy variation is also seen. When two different varieties of true-breeding sandy pigs were crossed to each other, they produced F1 offspring that were red. When these F1 offspring were crossed to each other, they produced red, sandy and white pigs in a 9:6:1 ratio. Explain this pattern of inheritance by assigning alleles and giving genotypes of the two true-breeding pigs, the F1 pigs and their F2 progeny. 9:6:1 A_B_ 9 red A_bb 3 sandy aaB_ 3 sandy aabb 1 white F1 must be AaBb to give a modified 9:3:3:1 ratio So P must be AAbb X aaBB Having either dominant allele (but not both) gives sandy color.
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Inheritance of coat color in Labrador dogs: Two loci together control coat color. A recessive genotype at one locus masks the expression of the alleles at the second locus. B – black; b – brown B is dominant to b E/e locus is epistatic to the B/b locus E – allows black or brown; e – golden (does not allow black or brown)
A pure-breeding black lab and a pure-breeding golden lab produce a litter of 6 black puppies. These puppies are mated and produce offspring in the following phenotypes and ratio: 9 black: 4 golden: 3 brown What are the genotypes of the pure-breeding dogs? What are the genotypes of the F 1 generation? B – black; b – brown B is dominant to b E/e locus is epistatic to the B/b locus E – allows black or brown; e – golden (does not allow black or brown)
P: BBEE x bbee F 1 : BbEe x BbEe F 2 : B_E_ (black) à 9/16 B_ee (golden) à 3/16 bbE_ (brown) à 3/16 bbee (golden) à 1/16 9 black : 4 golden: 3 brown
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