BIO 1A03 Post-lab 3 Assignment

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Feb 20, 2024

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BIO1A03 Post-lab 3 Assignment 1) State your resulting hypothesis created at the Letter of Information/Consent form. You do not need to include or attach the entire form in the assignment - you only need to state your hypothesis. (1 mark). When an individual's diet and their ancestral diet have high starch consumption, there will be an increase in the AMY1 diploid gene copies. This will lead to an increased concentration of the amylase enzyme in individuals' saliva. 2) What is happening in the amylase reaction tubes when you add the liquid from Tube Set 2 into Tube Set 3? Why are some of the Set 1 tubes a darker blue color than others at the end of this reaction? What causes the tubes to turn blue in the color? (2 marks) When the liquid from tube set 2 were added into the corresponding tubes in tube set 3, varying concentrations of the amylase enzyme were added into a set concentration of the stock starch solution. The reason why Some of the tubes in set 1 were a darker blue color than others at the end of the reaction was due to the concentration of starch in the solution. Since the iodine marker only binds to starch molecules and not monosaccharides such as glucose and maltose (products of starch metabolism), the more blue the solution, the more starch in the solution. This starch is a result of the varying amylase enzyme concentrations. More amylase, more starch will be metabolized, making the solution less blue. In the presence of starches, iodine solution will become blue as a result of a chemical reaction that occurs between starch and iodine. 3) Attach the amylase standard curve that you created in Lab 3. Please follow the formatting instructions given in Excel tutorial 2. (5 marks)
4) Using your amylase standard curve and the absorbance values that you measured in the lab, calculate the total salivary amylase concentration of Unknown Student A and Unknown Student B in mg/ml. Remember to account for the 100x dilution factor. Show your calculations (3 marks). Using the equation of the line of best fit to do these calculations Unknown Student A (Absorbance (1.08 nm)): Absorbance = -0.0392(Amylase Concentration ug/mL) + 1.1367 1.08 = -0.0392(Amylase Concentration ug/mL) + 1.1367 (1.08 - 1.1367)/(-0.0392) = 1.446ug/mL Multiply by 100x dilution factor: 1.446ug/ml x 100 = 1446ug/mL = 0.1446mg/mL Therefore the Concentration of the Unknown Student A Amylase Concentration is 0.1446mg/ml Unknown Student B (Absorbance (0.27)): Absorbance = -0.0392(Amylase Concentration ug/mL) + 1.1367 0.27 = -0.0392(Amylase Concentration ug/mL) + 1.1367 (0.27 - 1.1367)/(-0.0392) = 22.1096ug/mL Multiply by 100x dilution factor: 22.1096ug/ml x 100 = 22109.6ug/mL = 2.21096mg/mL Therefore the Concentration of the Unknown Student B Amylase Concentration is 2.20196mg/ml 5) Fill in the concentration of amylase for both Unknown student A and Unknown Student B in Table 3B-6. Using the Table of values of self reported starch consumption levels and measured salivary amylase concentrations, create a bar graph that shows the average amylase concentration for each category of starch consumption (low, moderate, high). You will create two versions of this figure with the same data. One figure will display standard deviation error bars and the other will display range error bars. Instructions for creating these bar graphs, and accompanying error bars, can be found in the Excel Tutorial 3 on Avenue. The procedure for the creation of both figures is similar. Please submit both figures.
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