Untitled document - 2023-12-27T163738.392

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AQA biology a-level paper 2 describe and explain the steps in the light dependent reaction of photosynthesis - ANS 1. photoionisation: light reaches chlorophyll in PSII, which is absorbed by an electron, which becomes excited and moves to a higher energy level. 2. the electron passes to a carrier protein in the thylakoid membrane, and is passed down a series of carrier molecules called an electron transfer chain. 3. as the electron moves down, energy is lost from the electron and is released as ATP. 4. the loss of electron from PSII is 'refilled' by an electron produced by photolysis, which also produces hydrogen and oxygen. 5. the lost electron reaches PSI, which absorbs light energy and boosts another electron to a higher energy level (excitation). 6. this electron also goes down an electron transport chain. 7. this reaches the final electron acceptor which is a proton. they combine to form H and reduce NADP to NADPH. describe and explain the steps in the light independent reaction pf photosynthesis. - ANS 1. CO2 diffuses into stroma and combines with ribulose bisphosphate (RuBP) using the enzyme rubisco. 2. this forms an unstable 6 carbon molecule, which splits into 2 3 carbon molecules, glyercate-3-phosphate (G3P) . 3. G3P is reduced by NADPH to triose-phosphate (TP), which is aided by ATP for energy. 4. TP can be converted into useful organic substances. 5. TP can also be reformed into RuBP using ATP. describe glycolysis in respiration. give net formation . - ANS 1. glucose is converted into phosphorylated glucose by 2ATP. this makes it very reactive, so it splits into 2 triose phosphate (TP). 2. 2TP is then oxidised by 2NAD and 4 ATP is formed to form pyruvate. 3. NET: 2ATP, 2Pyruvate, 2NADH, 2H+ describe links reaction in respiration. give net formation . - ANS 1. pyruvate diffuses into the matrix of mitochondria. 2. pyruvate is oxidised by NAD. CO2 is lost. this forms acetate.

3. acetate and co-enzyme A combine to form acetyl co-enzyme A. 4. NET: CO2, reduced NAD, acetyl co-enzyme A describe krebs cycle in respiration. give net formation . - ANS 1. acetyl co-enzyme A combines with 4 carbon molecule (oxaloacetate) to form 6 carbon citric acid. 2. CO2 is lost (decarboxylation), molecule is oxidised by NAD and ATP is produce. this forms 5 carbon compound. 3. it is oxidised by 2NADH and FAD, and is decarboxylated. 4. this forms 4 carbon molecule again. describe oxidative phosphorylation in respiration . - ANS 1. reduced coenzyme passes its H to a carrier protein in the ETC. this splits into a proton and electron. 2. the protons pass through the space between inner and outer mitochondrial membrane. 3. electrons pass through proteins on ETC. 4. protons return back via ATP synthase in the membrane, producing ATP. 5. the protons and electrons recombine to form H, which combines with O to form water. 6. oxygen is the last electron acceptor in the ETC. define biomass - ANS the total mass of organisms in a given area what is the 'gross primary production ' - ANS the chemical energy stored in a plants biomass what is the 'net primary production ' - ANS the chemical energy stores in a plants biomass after respiratory losses have been considered. this energy is available to consumers. how can you calculate the net primary production? - ANS NPP = GPP - R why is converting sunlight energy into biomass in producers inefficient? - ANS some light isn't the correct wavelength to be absorbed some light doesnt hit chloroplast some light is converted into heat energy

some light energy is reflected describe the nitrogen cycle. - ANS fixation: atmospheric nitrogen can be fixed by rhizbium bacteria. if struck by lightning, it becomes reactive and combines with oxygen to form NO. ammonification: saprobionts feed on organic matter and release ammonia, which then forms ammonium ions in the soil. nitrification: nitrifying bacteria convert ammonium ions into nitrite ions and then to nirate ions. denitrification: anaerobic denitrifying bacteria convert soil nitrates into gaseous nitrogen. homeostasis - ANS the maintenance of an internal environment within restricted limits in organisms. all cells are in an environment that meets their requirements and allows them to function normally despite external changes. why is homeostasis important? - ANS 1. the enzymes that control biochemical reactions in cells are sensitive to change e.g. in pH or temperature, which can cause them to denature. homeostasis allows enzyme controlled reactions to take place at a suitable rate. 2. homeostasis allows a constant blood glucose concentration to ensure a constant water potential, so cells don't shrink or burst. 3. homeostasis allows organisms to be more independent of external changes. list the parts of control mechanisms in homeostasis. - ANS 1. optimum temperature 2. receptor- detects any deviation from the optimum temperature 3. coordinator- info from receptor to effector 4. effector- often a muscle/gland, brings about change to return the system to optimum level 5. feedback mechanism

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what is negative feedback? - ANS this is when the change produced by the system leads to a change in the stimulus detected by the receptor, turning the system off. what is positive feedback? - ANS this is when a deviation from the optimum causes changes that result in an even greater deviation from the norm e.g. in neurones, a stimulus leads to an influx of Na+, which increases the membrane permeability to allow further NA+ to enter. describe the second messenger model. - ANS 1. Adrenaline binds to transmembrane protein receptor in the cell surface membrane of a liver cell. 2. the binding of adrenaline causes the protein to change shape on the inside of the membrane. 3. the change in tertiary structure activates adenyl cyclase, which converts ATP to cAMP. 4. cAMP binds to kinase, changes structure and activates it. 5. this catalyses the conversion of glycogen to glucose, which moves out of the liver cell and into the blood by facilitated diffusion. glycogenesis - ANS conversion of glucose to glycogen. this is when glucose levels are abnormally high. glycogenolysis - ANS breakdown of glycogen to glucose. this is when glucose levels are abnormally low. gluconeogenesis - ANS production of glucose from sources other than carbohydrates, such as glycerol or fatty acids. occurs when there's insufficient glycogen. how does insulin and beta cells in the pancreas affect glucose levels? - ANS 1. the beta cells in the pancreas detect a rise in the blood glucose concentration and respond by secreting insulin into blood. 2. insulin binds to glycoprotein receptors on cells.

3. this causes a change in the tertiary structure of the glucose transport proteins, making them more permeable to glucose and so allowing more in by facilitated diffusion. 4. activates the enzymes that convert glucose to glycogen and fat. how does glucagon and alpha cells in the pancreas affect glucose levels? - ANS 1. alpha cells detect a fall in blood glucose levels and so secrete glucagon. 2. glucagon attaches to receptors on cell surface membrane of liver cells. 3. this activates enzymes which convert glycogen to glucose. 4. also activates enzymes that convert amino acids to glucose. does insulin increase or decrease glucose levels? - ANS decrease does glucagon increase or decrease glucose levels? - ANS increase does adrenaline increase or decrease glucose levels? - ANS increase describe and explain the role of hormones in osmoregulation. - ANS 1.osmoreceptors in hypothalamus detect fall in water potential as they begin to shrink, causing hypothalamus to produce ADH. 2. ADH goes to posterior pituitary gland, where it is secreted into capillaries. 3. ADH goes from blood to kidneys, where it binds to receptors on the cells of of distil convoluted tubule and collecting duct. 4. this activates phosphorylase enzyme. 5. this causes vesicles, which contain water channel proteins, to fuse with cell surface membrane. hence, making it more permeable to water. 6. also increases permeability of collecting duct to urea so it passes out and lowers water potential, so more water can pass out by osmosis. describe what is happening to a neurone at resting potential. - ANS 1. neurone is polarised 2. Na+ actively transported out of axon 3. K+ actively transported in to axon 4. 3 sodium move out for every 2 potassium in hence, the outward movement of Na+ is greater than the inward movement of K+. this creates an electrochemical gradient as the outside is more negative than inside.

5. K+ begins to diffuse back out while Na+ diffuses back in, although most Na+ gates are closed. describe the processes that occur when an action potential is formed. - ANS 1. the energy of a stimulus causes some sodium voltage-gated channels in the axon membrane to open and so Na+ diffuses into axon, down electrochemical gradient. 2. this triggers a reversal in potential difference across the membrane because Na+ is positively charged. 3. as more Na+ goes in, more channels open and so even more Na+ goes in. 4. when action potential is +40mV the Na+ channels close and the K+ channels open. 5. K+ diffuses out of axon. 6. there is overshoot of electrical gradient- hyperpolarisation. 7. K+ gates shut. resting potential is re-established. this is repolarisation. describe the processes that occur during the passage of an action potential along an unmyelinated axon. - ANS 1. at rest- the inside of axon is more negative than outside. 2. a stimulus causes influx of Na+ and so the charge of the axon is reversed- depolarised. 3. this causes localised electrical currents to open up the voltage-gated channels further along the axon, so more Na+ enters here and depolarises this area. 4. in the initial area, Na+ gates close and K+ open, so K+ leave the axon down electrochemical gradient. depolarisation moves along membrane. 5. outward movement of K+ and inward movement of Na+ continues until repolarisation; return to resting state. why do action potentials travel faster down a myelinated axon? - ANS myelin sheath prevents action potentials forming. action potentials form at the Nodes of Ranvier, and jump from node to node by saltatory conduction. in an unmyelinated axon, it takes longer as the events of depolarisation take place all the way along an axon. what are factors that affect the speed of an action potential? - ANS 1. myelin sheath

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2. diameter of axon: the greater the diameter, the faster the speed, because there's less leakage of ions from a large axon, so membrane potentials are easier to maintain. 3. temperature: the higher the temperature, the greater the rate of diffusion of ions, and hence the faster the impulse. what is the purpose of the refractory period? - ANS 1. Ensures action potentials travel in one direction only, since action potentials cannot move to a refractory region. 2. ensures action potentials are separated from one another. 3. limits the number of action potentials. spatial summation - ANS a number of different presynaptic neurones collectively release enough neurotransmitters to exceed the threshold value of the postsynaptic neurone, triggering a new action potential. temporal summation - ANS a single presynaptic neurone releases neurotransmitters many times over a short period. this exceeds the threshold value, triggering a new action potential. how do drugs affect synaptic transmission and action potentials? - ANS 1. stimulate the nervous system by mimicking neurotransmitters, stimulating neurotransmitter release or inhibiting enzymes that break down neurotransmitters, and so create more action potentials. 2. inhibit the nervous system by inhibiting release of neurotransmitter or blocking Na+/K+ channels on postsynaptic neurone, hence creating less action potentials. describe the processes that occur during synaptic transmission. - ANS 1. action potential arrives at end of presynaptic neurone. this stimulates Ca2+ channels to open so Ca2+ enter synaptic knob by facilitated diffusion. 2. this stimulates synaptic vesicles to fuse with presynaptic membrane, releasing acetylcholine into synaptic cleft. 3. acetylcholine binds to receptor sites on Na+ channel proteins on postsynaptic neurone membrane. this causes them to open to Na+ diffuse in. 4. influx of Na+ generates new action potential in postsynaptic neurone. 5. acetylcholinerase hydrolyses acetylcholine into choline and ethanoic acid, which diffuses back across into presynaptic neurone.

6. ATP recombines ethanoic acid and choline, which is stored in synaptic vesicles for later use. describe slow twitch fibres - ANS contract more slowly and provide less powerful contractions but over a longer period. adapted for aerobic respiration to avoid lactic acid build up. adapted for endurance work. has lots of myoglobin, rich bloody supply and many mitochondria. describe fast twitch fibres - ANS contract more rapidly and more powerful but over a shorter period of time. adapted for intense exercise have thicker and more numerous myosin filament, have more glycogen, have more enzymes to carry out anaerobic respiration, has phosphocreatine. what is a neuromuscular junction - ANS the point where motor neurone meets a skeletal muscle fibre. describe the processes that occur during muscle contraction - ANS 1. action potential travels down T-tubules, which are in contact with the sarcoplasmic reticulum. 2. calcium ion protein channels on sarcoplasmic reticulum open and calcium ions diffuse out by diffusion, down a concentration gradient. 3. calcium ions cause tropomyosin to change shape and unblock the binding sites on actin. 4. ADP attaches to myosin head, so it changes shape and can now bind to the actin filament, forming a cross bridge. 5. once attached, myosin heads alters angle, pulling the actin along with it. ADP is released. 6. ATP attaches to myosin head, causing it to detach from actin. 7. calcium ions activate ATPase to hydrolyse ATP to ADP, which releases enough energy for the heads to return to initial position. 8. repeat what type of stimulus does a pacinian corpuscle respond to? - ANS mechanical pressure

when at rest, what occurs at a pacinian corpuscle? - ANS the sodium ion channels on the membrane around the neurone are narrow and so don't allow Na+ to pass along them. it has resting potential. what happens when pressure is applied to pacinian corpuscle? - ANS 1. it deforms, so membrane around neurone stretches. 2. this widens Na+ channels and so Na+ diffuses into neurone. 3. this changes the potential of the membrane, depolarising it. a generator potential is formed. 4. generator potential forms an action potential. what kind of summation occurs in rod cells? - ANS spatial summation what kind of summation occurs in cone cells? - ANS temporal summation where are rod cells absent at? - ANS the fovea where are cone cells concentrated at? - ANS the fovea where are rod cells more highly distributed at? - ANS periphery of the retina do rod cells give good or poor visual acuity? - ANS poor visual acuity do cone cells give good or poor visual acuity? - ANS good visual acuity how many types of rod and cone cells are there? - ANS rod- 1 cone- 3, all responding to different wavelengths why do rod cells give poor visual acuity? - ANS many rod cells link to the same bipolar cells (spatial summation), so when light stimulates rod cells which share the same neurone, only 1 impulse will travel to the brain. so, the brain can't distinguish between separate sources of light that stimulated them. resolution is poor, hence low visual acuity. why do cone cells give high visual acuity? - ANS each cell is connected to a separate bipolar cell. if 2 separate rod cells are stimulated by light, then 2 separate impulses will be sent to the brain. so, the brain can distinguish between

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two sources of light that stimulate two different rod cells, hence better resolution, hence better visual acuity. what is a taxis? - ANS when the direction of a stimulus determines a simple response. motile organisms will move towards it if favourable (positive), or away if unfavourable (negative). what is a kinesis? - ANS a form of response whereby an organism changes the speed in which it moves and changes direction. this occurs when an organism reaches an area of unfavourable stimuli, so that it may return to a favourable environment. example of kinesis - ANS woodlice increase rate of movement/turning when they reach a dry area. this will allow them to reach a favourable damp area, where they don't turn as much. example of taxis - ANS earthworms have negative phototaxis and so stay deeper in soil to aid their chances of survival, so they are more likely to find food, avoid predators, and conserve water. what is a tropism? - ANS the growth of part of a plant in response to a directional stimulus. there can be positive and negative responses. describe the control of phototropism by IAA. - ANS 1. cells in shoot tip produce IAA which is transported evenly throughout all regions and then down the shoot. 2. light causes IAA to accumulate on the shaded side of the shoot, so much that there is a greater build up of IAA on shaded than unshaded side. 3. IAA causes the shaded side of the shoot to elongate further than the non shaded side. this causes the shoot to eventually grow and bend towards the light. describe the control of gravitropism by IAA. - ANS 1. root tip cells produce IAA, which is distributed evenly and down the root. 2. gravity causes IAA to accumulate on the LOWER side of the shoot than upper side, so there is a higher concentration on lower than upper. 3. IAA inhibits elongation in root cells, so inhibits elongation in lower side than upper side. so, the upper side of the shoot elongates further and bends towards gravity.

what effect does IAA have on roots? - ANS inhibits growth what effect does IAA have on shoots? - ANS stimulates growth describe the components of a reflex arc and give an example. - ANS 1. stimulus- heat 2. receptor- heat receptors to sensory neurone 3. sensory neurone- impulse to spinal cord 4. relay neurone- to motor neurone 5. motor neurone- spinal cord to muscle 6. effector- muscle in arm contracts 7. response- pulling hand away from heat which region of the brain controls the changes in heart rate? - ANS medulla oblongata what are the two centres of the medulla oblongata? - ANS 1. a centre that increases heart rate, linked to sinoatrial node by sympathetic NS. 2. a centre that decreases heart rate, linked to the sinoatrial node by parasympathetic NS. explain how chemoreceptors control heart rate. - ANS 1. chemoreceptors in the walls of the carotid arteries are sensitive in changes of pH. when they detect a lower pH (high CO2) then more impulses are sent to the specific heart rate increasing centre in the medulla oblongata. 2. this centre increases frequency of impulses to the sinoatrial node via sympathetic NS. this increases rate of electrical waves being produced. 3. increased heart rate results in increased blood flow, so more CO2 is removed by lungs and CO2 levels return to normal. pH rises to normal. 4. chemoreceptors reduce frequency of impulses, medulla oblongata reduces frequency of impulses. heart rate returns to normal. describe the control of heart rate by pressure receptors. - ANS 1. when blood pressure is higher than normal, pressure receptors in carotid arteries send more

impulses to centre in medulla oblongata that decreases heart rate via parasympathetic NS. 2. when blood pressure is lower than normal, pressure receptors send more impulses to the centre of the medulla oblongata that increases heart rate via sympathetic NS. name the negative effects of using nitrogen containing fertilisers. - ANS 1. reduced species diversity 2. leaching 3. eutrophication why does using nitrogen containing fertilisers result in reduced species diversity? - ANS nitrogen rich soils favour the growth of grasses etc., which can outcompete other species, which die as a result. what is "leaching"? - ANS the process by which nutrients are removed from the soil. rainwater will dissolve soluble nutrients and carry them deep into the soil, away from plant roots. the leached ions can reach rivers that drain into lakes. what is "eutrophication"? - ANS the process by which nutrient concentrations increase in bodies of water, often as a result of leaching. may result in algael bloom, which blocks sunlight from reaching plants underneath, causing them to die. define population. - ANS a group of individuals of one species that occupy the same habitat at the same time and are potentially able to interbreed. define community. - ANS all the populations of different species living and interacting in a particular place at the same time. define niche. - ANS the role and position a species has in its environment; how it meets its needs for food and shelter, how it survives, and how it reproduces. A species' niche includes all of its interactions with the biotic and abiotic factors of its environment.

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codominance - ANS occurs where heterozygote has a phenotype that is different from both homozygotes. neither allele is dominant over the other; they both contribute equally to the phenotype. sex linkage - ANS alleles carried on the X chromosome. why are sex linked diseases more common in males than females? - ANS because males only have one X chromosome, and so if there is a recessive allele there, then there will be no dominant allele on Y chromosome to "hide" it. multiple alleles - ANS this is where there are several different alleles of a gene e.g. blood type: IA, IB (codominant), and IO (recessive). dihybrid inheritance - ANS involves 2 genes at different loci. epistasis - ANS when one gene locus interacts with another gene at a different locus. linked genes - ANS genes on the same chromosome Hardy-Weinberg principle - ANS p2 + 2pq + q2 p2 = homozygous dominant q2 = homozygous recessive 2pq = heterozygous In any hardy-weinberg problem, start with homozygous recessive individuals. what assumptions need to be in place to use the hardy weinberg principle? - ANS 1. No mutations 2. Population is isolated 3. No selection 4. Large population 5. Mating is random

how can a population be separated and form different species? - ANS 1. Populations become separated. physical barriers may come between two groups. 2. Therefore they stop interbreeding. 3. Populations adapt to new environment. Selection pressures will be different in different areas. 4. Allele frequencies will change in the different populations. 5. Over time they become so different that they can no longer interbreed. formula to calculate the mean density of individuals from quadrats - ANS total no of individuals counted ------------------------------------ no of quadrats x area of quadrat allopatric speciation - ANS When populations of a species become geographically isolated. Gene flow between them ceases (reproductive isolation). the new environment will trigger a change in the gene pool due to natural selection imposed on them. If the populations are relatively small, they may experience a founder effect. Selection and genetic drift will act differently on these two different genetic backgrounds, creating genetic differences between the two new species. sympatric speciation - ANS become reproductively isolated from each other even though they occupy the same geographic range. Factors that could lead to them becoming reproductively isolated from each other are things like changes in courtship behavior, changes in feeding behavior, changes in coloration. The most common way this occurs is polyploidy. Rapid genetic changes can alter morphology, behavior, and habitat preferences. totipotent cells - ANS cells that can mature into any kind of specialized body cell. can divide to form a whole organism. they are found in very early mammalian embryos. after this stage, some of the genes become switched off and so are not translated into RNA, hence specialized.

pluripotent cells - ANS can become any kind of specialized body cell, but cannot divide to form a whole organism. induced pluripotent stem cells - ANS produced from unipotent cells. genetically altered in labs (transcription factors) to make them have the characteristics of embryonic stem cells. they turn on the genes that were otherwise turned off. multipotent cells - ANS can divide into some, but not all, specialized cells. unipotent cells - ANS divide to form just one type of cell. transcription factors - ANS transcription factors bind to the DNA sequence at specific target sequences. RNA polymerase recognizes the complex formed and so transcribes the gene. methylation of DNA - ANS addition of methyl groups to bases. added throughout life, sometimes in response to environmental factors e.g. diet. causes the DNA to wrap more tightly around histones, so transcriptional factors cannot bind to specific DNA sites and initiate transcription. acetylation of DNA - ANS acetyl groups added to histones, so DNA is less tightly wound round it, making it easier for RNA polymerase and transcriptional factors to bind, so transcription can occur. oncogenes - ANS mutated proto-oncogenes form oncogenes. oncogenes are permanently activated (switched off). explain how to produce DNA fragments with reverse transcriptase. - ANS 1. reverse transcriptase forms cDNA from an mRNA strand. 2. single stranded cDNA is isolated when mRNA is hydrolysed with an enzyme. 3. cDNA acts as a template for DNA nucleotides to bind to by complimentary base pairing. DNA polymerase joins them together. a copy of the gene is now formed. explain how to produce DNA fragments with restriction endonucleases. - ANS 1. cuts gene at recognition site. this can result in blunt or sticky ends. 2. promotor gene and terminator gene also inserted. marker genes too.

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3. same RE cut out complimentary recognition site in plasmid (vector). 4. DNA ligase is used to bind the nucleotides of the two DNA strands together. 5. plasmids introduced to host organisms. bacteria mixed with plasmids with calcium ions. what is a DNA probe? - ANS a short single-stranded length of DNA that has some sort of label attached to make it identifiable e.g. radioactively labelled and fluorescently labelled probes. how are DNA probes used to identify alleles? - ANS 1. DNA probes are made so that they are complimentary to part of the base sequence of the allele. 2. double-stranded DNA is treated so it becomes 2 separate strands. 3. the separated strands are mixed with the probes, which bind to the complimentary sites. this is DNA hybridisation. 4. the site at which it binds to can be identified as it will emit radioactivity or fluorescence. explain the steps of genetic fingerprinting. - ANS 1. extract DNA. quantity of DNA may be increased by PCR. 2. restriction endonucleases cut DNA into fragments. 3. gel electrophresis. dna put onto agar gel, voltage is applied across it. smaller fragments mover further than larger fragments. 4. DNA hybridisation- DNA probes have complimentary base sequences to non-coding DNA, and so bind under specific conditions. 5. X-ray film is exposed to radiation from probes. this film is put over a nylon membrane. a series of bars is shown which corresponds to the movement of the fragments. what is autosomal linkage? - ANS when 2 or more genes are carried on the same autosome describe the formation of glomerular filtrate by ultrafiltration - ANS blood enters Bowmans capsule. the walls of glomerular capillaries are made up of epithelial cells. high hydrostatic pressure in glomerulus. water, glucose and other ions are forced out, forming glomerular filtrate. leaves behind blood cells and proteins.

how is glucose reabsorbed in the proximal convoluted tubule? - ANS Na+ actively transported out of cells lining the PCT, into blood capillaries, which carry them away. Na+ diffuse down concentration gradient from the PCT into the epithelium by facilitated diffusion- cotransport. the molecules in the PCT then diffuse into blood, so they are reabsorbed. what is the role of the loop of henle? - ANS reabsorbs water from collecting duct, so it can concentrate urine so that it has a lower water potential than blood. how does the loop of henle concentrate urine? - ANS 1. filtrate enters descending limb. water passes out by osmosis and into the interstitial space as the walls are permeable. Na+ actively transported in. 2. this lowers water potential. lowest water potential is at the bottom of the hairpin. 3. at the ascending limb, the walls are not permeable to water and so it cant leave. Na+ is actively transported out into the interstitial space. this creates a higher water potential. 4. interstitial space between collecting duct and ascending limb has a wp gradient, from high to low, and so any water left passes out. explain how the loop of henle acts as a counter current multiplier. - ANS water in the loop of henle meets water in the interstitial space which is of a lower water potential, and so water can pass out by osmosis for the whole length of the descending tube and collecting duct. how does the distil convoluted tubule reabsorb material from the filtrate? - ANS the cells lining the DCT have microvilli and mitochondria. it selects which ions to reabsorb. this controls the pH of the filtrate. list the steps in osmoregulation - ANS 1. Ultrafiltration in Bowmans capsule 2. reabsorption in the proximal convoluted tubule 3. concentration in the loop of henle distil convoluted tubule explain the role of hormones in osmoregulation - ANS 1. osmoreceptors in the hypothalamus detect fall in water potential. this causes water to be lost from osmoreceptors.

2. this makes them produce ADH, which goes to pituitary gland to pass into blood. 3. ADH goes to kidneys and binds to surface of DCT ad collecting duct, activating phosphorylase. this causes vesicles to fuse with membrane and form aquaporins. 4. ADH increases permeability to urea, which passes out and decreases WP in interstitial space. this causes water to leave by osmosis, so more water is reabsorbed. effect of oestrogen on transcription - ANS 1. diffuses into cytoplasm of cell. Binds with complimentary TF. 2. alters tertiary shape of the binding site of TF, so it is activated and can now bind to genes. 3. TF enters nuclear pore and binds to gene. 4. This stimulates transcription.

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