
1)
Name of the quadrant containing the given point.
1st quadrant.
Given information:
Point is:
Formula used:
- If both the coordinates, i.e. both x and y coordinate of a point are positive then it is in 1st quadrant.
- If the x coordinate of point is negative and y coordinate of that point is positive, then it is in 2nd quadrant.
- If both the coordinates, i.e. both x and y coordinate of a point are negative then it is in 3rd quadrant.
- If the x coordinate of point is positive and y coordinate of that point is negative, then it is in 4th quadrant.
Calculation:
To give the name of the quadrant of the point
Since, both the coordinates, i.e. both x and y coordinate of a point are positive then it is in 1st quadrant. Thus, the point
2)
Name of the quadrant containing the given point.
y-axis
Given information:
Point is:
Formula used:
- If both the coordinates, i.e. both x and y coordinate of a point are positive then it is in 1st quadrant.
- If the x coordinate of point is negative and y coordinate of that point is positive, then it is in 2nd quadrant.
- If both the coordinates, i.e. both x and y coordinate of a point are negative then it is in 3rd quadrant.
- If the x coordinate of point is positive and y coordinate of that point is negative, then it is in 4th quadrant.
- The y coordinate of point on x -axis is 0.
- The x coordinate of point on y -axis is 0.
Calculation:
To give the name of the quadrant of the point
First note that the x coordinate of given point is 0, and it indicates that the point is on y-axis.
Thus,
3)
Name of the quadrant containing the given point.
2nd quadrant.
Given information:
Point is:
Formula used:
- If both the coordinates, i.e. both x and y coordinate of a point are positive then it is in 1st quadrant.
- If the x coordinate of point is negative and y coordinate of that point is positive, then it is in 2nd quadrant.
- If both the coordinates, i.e. both x and y coordinate of a point are negative then it is in 3rd quadrant.
- If the x coordinate of point is positive and y coordinate of that point is negative, then it is in 4th quadrant.
Calculation:
To give the name of the quadrant of the point
Since, the sign of x coordinate of point is negative and sign of y coordinate of that point is positive, then it is in 2nd quadrant.
Thus, the point
4)
Name of the quadrant containing the given point.
3rd quadrant.
Given information:
Point is:
Formula used:
- If both the coordinates, i.e. both x and y coordinate of a point are positive then it is in 1st quadrant.
- If the x coordinate of point is negative and y coordinate of that point is positive, then it is in 2nd quadrant.
- If both the coordinates, i.e. both x and y coordinate of a point are negative then it is in 3rd quadrant.
- If the x coordinate of point is positive and y coordinate of that point is negative, then it is in 4th quadrant.
Calculation:
To give the name of the quadrant of the point
Since, the sign of both the coordinates, i.e. both x and y coordinate of a point are negative then it is in 3rd quadrant.
Thus, the point
Chapter P Solutions
EBK PRECALCULUS:GRAPHICAL,...-NASTA ED.
- plese do #48arrow_forward43-46. Directions of change Consider the following functions f and points P. Sketch the xy-plane showing P and the level curve through P. Indicate (as in Figure 15.52) the directions of maximum increase, maximum decrease, and no change for f. T 45. f(x, y) = x² + xy + y² + 7; P(−3, 3)arrow_forwardSolve the differential equation by variation of parameters 3x2y" + 7xy' + y = x2 - xarrow_forward
- Which sign makes the statement true? 9.4 × 102 9.4 × 101arrow_forwardDO these math problems without ai, show the solutions as well. and how you solved it. and could you do it with in the time spandarrow_forwardThe Cartesian coordinates of a point are given. (a) (-8, 8) (i) Find polar coordinates (r, 0) of the point, where r > 0 and 0 ≤ 0 0 and 0 ≤ 0 < 2π. (1, 0) = (r. = ([ (ii) Find polar coordinates (r, 8) of the point, where r < 0 and 0 ≤ 0 < 2π. (5, 6) = =([arrow_forward
- The Cartesian coordinates of a point are given. (a) (4,-4) (i) Find polar coordinates (r, e) of the point, where r > 0 and 0 0 and 0 < 0 < 2π. (r, 6) = X 7 (ii) Find polar coordinates (r, 8) of the point, where r < 0 and 0 0 < 2π. (r, 0) = Xarrow_forwardr>0 (r, 0) = T 0 and one with r 0 2 (c) (9,-17) 3 (r, 8) (r, 8) r> 0 r<0 (r, 0) = (r, 8) = X X X x x Warrow_forward74. Geometry of implicit differentiation Suppose x and y are related 0. Interpret the solution of this equa- by the equation F(x, y) = tion as the set of points (x, y) that lie on the intersection of the F(x, y) with the xy-plane (z = 0). surface Z = a. Make a sketch of a surface and its intersection with the xy-plane. Give a geometric interpretation of the result that dy dx = Fx F χ y b. Explain geometrically what happens at points where F = 0. yarrow_forward
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning





