EBK PRECALCULUS:GRAPHICAL,...-NASTA ED.
EBK PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780135795910
Author: Demana
Publisher: PEARSON CO
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Chapter P.1, Problem 69E
Solution

The inequality that corresponds to the interval −2,1 .

  E. −2≤x<1

Given:

The interval of real numbers, −2,1 .

Concept Used:

  • If there is the strict inequality symbol < or> , then use a parenthesis on the interval
  • If there is the inequality symbol ≤ or≥ , then use a bracket on the interval
  • To graph the endpoint with strict inequality < or>, use the open parenthesis or a hollow circle at that endpoint.
  • To graph the endpoint with inequality symbol ≤ or≥, use the bracket or a solid circle at that endpoint.

Calculation:

The given interval −2,1 represents the set of all real number that are greater than or equal to −2 and less than 1.

Since the left end point has a bracket, there must be the inequality sign ≤ with −2 . Also, there is an open parenthesis with 1, so use the strict inequality < with 1.

Thus, the corresponding inequality for the given interval is −2≤x<1 .

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Chapter P.1, Problem 68E
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Chapter P.1, Problem 70E

Chapter P Solutions

EBK PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. P.1 - Prob. 1QRCh. P.1 - Prob. 2QRCh. P.1 - Prob. 3QRCh. P.1 - Prob. 4QRCh. P.1 - Prob. 5QRCh. P.1 - Prob. 6QRCh. P.1 - Prob. 7QRCh. P.1 - Prob. 8QRCh. P.1 - Prob. 9QRCh. P.1 - Prob. 10QR
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