Concept explainers
Videos
A student names the second structure above 2,3-dimethylcyclohex-1-ene. What rule does thisviolate?
Interpretation:The rules violate by the student during naming of thegiven structure as 2, 3-dimethylcyclohex-1-ene needs to be determined.
Concept introduction:
The chemical name of the compound can be defined as the name of each element or sub-compounds which are present in the chemical composition of the compound.
Answer to Problem 1CTQ
The rule of branching in the ring is violated by the student. Therefore, the name of the compound is 1, 6-dimethylcyclohexane.
Explanation of Solution
The structure of the compound is given as −
The student named the above compound as 2, 3-dimethylcyclohex-1-ene. It is to be determined that the name given by the student is correct or not. Label all the carbon atoms which are present in the ring structure to determine that the name of the compound is correct or not. The parent chain is numbered in such a way to give the lowest possible number to the double bond and these two numbers will be placed before the suffix.
In the compound structure, the carbon with double bond should have lowest number because it has the greatest number of branches. Therefore, the numbering of the atom will start with the double bonded carbons which have methyl substituent.
Hence, the compound will be named as 1,6-dimethylcyclohexane. In this rule of the branching in a ring containing double bond is violated by the student.
Thus, the student violated the rule of branching in the ring. Hence the name of the structure is 1,6-dimethylcyclohexane.
Want to see more full solutions like this?
Chapter NW2 Solutions
Organic Chemistry: A Guided Inquiry
- 2. Use Hess's law to calculate the AH (in kJ) for: rxn CIF(g) + F2(g) → CIF 3 (1) using the following information: 2CIF(g) + O2(g) → Cl₂O(g) + OF 2(g) AH = 167.5 kJ ΔΗ 2F2 (g) + O2(g) → 2 OF 2(g) 2C1F3 (1) + 202(g) → Cl₂O(g) + 3 OF 2(g) о = = -43.5 kJ AH = 394.1kJarrow_forwardci Draw the major product(s) of the following reactions: (3 pts) CH3 HNO3/H2SO4 HNO3/ H2SO4 OCH3 (1 pts)arrow_forwardProvide the product for the reactionarrow_forward
- What is the net ionic equation for the reaction between tin(IV) sulfide and nitric acid?arrow_forwardThe combustion of 28.8 g of NH3 consumes exactly _____ g of O2. 4 NH3 + 7 O2 ----> 4 NO2 + 6 H2Oarrow_forwardWhat is the molecular formula of the bond-line structure shown below OH HO ○ C14H12O2 ○ C16H14O2 ○ C16H12O2 O C14H14O2arrow_forward
- Check all molecules that are acids on the list below. H2CO3 HC2H3O2 C6H5NH2 HNO3 NH3arrow_forwardFrom the given compound, choose the proton that best fits each given description. a CH2 CH 2 Cl b с CH2 F Most shielded: (Choose one) Least shielded: (Choose one) Highest chemical shift: (Choose one) Lowest chemical shift: (Choose one) ×arrow_forwardConsider this molecule: How many H atoms are in this molecule? How many different signals could be found in its 1H NMR spectrum? Note: A multiplet is considered one signal.arrow_forward
- For each of the given mass spectrum data, identify whether the compound contains chlorine, bromine, or neither. Compound m/z of M* peak m/z of M + 2 peak ratio of M+ : M + 2 peak Which element is present? A 122 no M + 2 peak not applicable (Choose one) B 78 80 3:1 (Choose one) C 227 229 1:1 (Choose one)arrow_forwardShow transformation from reactant to product, step by step. *see imagearrow_forwardCheck the box if the molecule contains the listed item. *See imagearrow_forward
Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning