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- Construct an explanation for why sulfuric acid is such a strong acid. (Note that sulfur is in thethird row of the periodic table and can have more than eight electrons.)The following are equivalent ways of asking about the acidity of an H atom: • What is the most acidic H on the molecule? • Which H is associated with the published pKa value? • Which H on the molecule is easiest to remove? • Which H on the molecule takes the least energy to remove? • Which bond to an H is most polarized? • For which H atom is removal least uphill in energy? • Which bond to an H atom, when broken, results in the lowest PE conjugate base? We will often find the last of these questions is easiest to answer. To do this, find all the different Hatoms on the molecule, and draw all possible conjugate bases.Only the lowest-energy one is the “real” conjugate base. Identify this structure, and you have found the most acidic H. Use this strategy to find the most acidic H on each of the following molecules. Note: Each structure hasat least three different kinds of H’s, so draw at least three unique conjugate bases for each.Question 1 Which of the following is/are a Bronsted base? Multiple answers are possible HBr O NH, O H2S HCO3 Question 2
- 2. Each of these species is a hard or soft acid or base. Write an "x" in the appropriate box under each species. Lit TIt C NH3 Pt2+ Ni2+ OH hard acid soft acid hard base soft baseI just need an answer. An explanation isn’t necessary. Thank you.Select all of the compounds that would be classified as an Acid. A HF HNO2 C ASF5 CuBr2 E NazSO3 F RU2SO4 G PF3 H3PO4 CsBr WCI2 K KCN L H2CO3 M CO2 Mn203 H2SO4 K2CO3 Q P205
- Which of the following is not an acid? Group of answer choices a. HC2H3O2 b. HNO3 c. H2SO4 d. all of these are acids e. CH412. Circle all those compounds that are Lewis acids from among the group of compounds shown below. H HCCH H A B HHHHH ||||| нсссссн TITT HHHHH H. H Cl DDraw a Lewis structure for the conjugate acid. Write in any non-zero formal charges and make sure all atoms in your structure fully satisfy the octet rule. molecule H :0: H-C-C-H H conjugate acid of the molecule Click and drag to start drawing a structure. X S