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(a)
Interpretation:
The IUPAC name for the given compound is to be written.
Concept introduction:
The IUPAC name of a compound is made of three parts, prefix, root, and suffix. If the compound contains different
If any chiral carbons are present, their absolute configurations are determined on the basis of Cahn-Ingold-Prelog rules, and listed at the start along with the carbon number.
(b)
Interpretation:
The IUPAC name for the given compound is to be written.
Concept introduction:
The IUPAC name of a compound is made of three parts, prefix, root, and suffix. If the compound contains different functional groups, the highest priority group is determined. This determines the suffix. The longest continuous chain of carbons that contains the highest priority group forms the root. The final ‘e’ in the name of the corresponding alkane is replaced by the suffix corresponding to the highest priority group, except in case of nitriles, when the suffix ‘nitrile’ is simply added to the root name. The position (locant) of the highest priority group on the longest chain is inserted between the root name and the suffix unless redundant. The longest carbon chain is numbered in the direction that gives the highest priority group the lowest possible locant. If the root is a ring, the position of highest priority group is always 1. Any other low priority groups are treated as substituents and listed alphabetically in the prefix along with their locants. In case of rings, the numbering of ring carbons is done in the direction that gives the substituents the lowest possible locants. If more than one instance of any functional group (including highest priority) is present, their numbers are specified by adding a di, tri, etc. to the respective functional group name.
If any chiral carbons are present, their absolute configurations are determined on the basis of Cahn-Ingold-Prelog rules, and listed at the start along with the carbon number.
(c)
Interpretation:
The IUPAC name for the given compound is to be written.
Concept introduction:
The IUPAC name of a compound is made of three parts, prefix, root, and suffix. If the compound contains different functional groups, the highest priority group is determined. This determines the suffix. The longest continuous chain of carbons that contains the highest priority group forms the root. The final ‘e’ in the name of the corresponding alkane is replaced by the suffix corresponding to the highest priority group, except in case of nitriles, when the suffix ‘nitrile’ is simply added to the root name. The position (locant) of the highest priority group on the longest chain is inserted between the root name and the suffix unless redundant. The longest carbon chain is numbered in the direction that gives the highest priority group the lowest possible locant. If the root is a ring, the position of highest priority group is always 1. Any other low priority groups are treated as substituents and listed alphabetically in the prefix along with their locants. In case of rings, the numbering of ring carbons is done in the direction that gives the substituents the lowest possible locants. If more than one instance of any functional group (including highest priority) is present, their numbers are specified by adding a di, tri, etc. to the respective functional group name.
If any chiral carbons are present, their absolute configurations are determined on the basis of Cahn-Ingold-Prelog rules, and listed at the start along with the carbon number.
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Chapter F Solutions
Get Ready for Organic Chemistry
- Transmitance 3. Which one of the following compounds corresponds to this IR spectrum? Point out the absorption band(s) that helped you decide. OH H3C OH H₂C CH3 H3C CH3 H3C INFRARED SPECTRUM 0.8- 0.6 0.4- 0.2 3000 2000 1000 Wavenumber (cm-1) 4. Consider this compound: H3C On the structure above, label the different types of H's as A, B, C, etc. In table form, list the labeled signals, and for each one state the number of hydrogens, their shifts, and the splitting you would observe for these hydrogens in the ¹H NMR spectrum. Label # of hydrogens splitting Shift (2)arrow_forwardNonearrow_forwardDraw the Lewis structure of C2H4Oarrow_forward
- a) 5. Circle all acidic (and anticoplanar to the Leaving group) protons in the following molecules, Solve these elimination reactions, and identify the major and minor products where appropriate: 20 points + NaOCH3 Br (2 productarrow_forwardNonearrow_forwardDr. Mendel asked his BIOL 260 class what their height was and what their parent's heights were. He plotted that data in the graph below to determine if height was a heritable trait. A. Is height a heritable trait? If yes, what is the heritability value? (2 pts) B. If the phenotypic variation is 30, what is the variation due to additive alleles? (2 pts) Offspring Height (Inches) 75 67.5 60 52.5 y = 0.9264x + 4.8519 55 60 65 MidParent Height (Inches) 70 75 12pt v V Paragraph B IUA > AT2 v Varrow_forward
- Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStaxChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
- Organic And Biological ChemistryChemistryISBN:9781305081079Author:STOKER, H. Stephen (howard Stephen)Publisher:Cengage Learning,General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning
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