
Concept explainers
(a)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The portion ‘
The IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(b)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘2, 2-dimethyl’ indicates that the methyl group is attached at C2, and C2 carbon atoms of the butyric acid. The structure of
The trivial names of carboxylic acids are in the general form alkionic acid while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.
The butyric acid is the trivial name, its IUPAC name is butanoic acid. Thus, the IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(c)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘2-amino’ indicates that
The trivial names of carboxylic acids are in the general form alkionic acid while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.
The propionic acid is the trivial name; its IUPAC name is propanoic acid. Thus, the IUPAC name of
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(d)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
Note the stereochemistry about the doubly bonded carbon atoms. The two high-priority groups are on the same side of the double bond making it (Z) stereoisomer.
The prefix
As the longest carbon chain has four atoms, the root name for carboxylic acid is
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
(e)
Interpretation:
The structure of the molecule is to be drawn and the IUPAC name is to be provided that corresponds to the given trivial name.
Concept introduction:
Carboxylic acids are the compounds containing
The carbonyl carbon atom is always numbered as C1 and the numbering continues. The substituents, if any, attached to the carbon chain are names according to the alphabetical order and the lowest locator number.
The trivial names of carboxylic acids are in the general form alkionic acid, while the IUPAC names are in the general form alkanoic acid. The suffix ‘ionic’ is replaced by ‘noic’ in the IUPAC name.

Answer to Problem F.12P
The structure of the molecule that corresponds to the given trivial name
The IUPAC name of
Explanation of Solution
The given IUPAC name is
The prefix ‘diethyl’ in the name suggests that an ethyl group is attached at C2 carbon atom of the root. The locator numbers 2 and 2 are not included in the name because there is only one carbon atom to which any substituent could get attached. Thus, the complete structure of
As the longest carbon chain has three atoms, the root name for this dicarboxylic acid is
The structure of the compound is drawn and the IUPAC name of the compound is written that corresponds to the given trivial name.
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Chapter F Solutions
Organic Chemistry: Principles And Mechanisms (second Edition)
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- Draw the Markovnikov product of the hydrohalogenation of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for caps lock Explanation Check 2 W E R + X 5 HCI Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Bil Y F G H K L ZZ X C V B N M control opption command F10 F10 command 4 BA Ar Carrow_forwardI don't understand why the amide on the top left, with the R attached to one side, doesn't get substituted with OH to form a carboxylic acid. And if only one can be substituted, why did it choose the amide it chose rather than the other amide?arrow_forwardesc Draw the Markovnikov product of the hydration of this alkene. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for this problem. Explanation Check BBB + X 0 1. Hg (OAc)2, H₂O 2. Na BH 5 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Bl P 豆 28 2 28 N 9 W E R T Y A S aps lock G H K L Z X C V B N M T central H command #e commandarrow_forward
- C A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. . If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. (X) This transformation can't be done in one step. + Tarrow_forwardく Predict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. No reaction. Explanation Check OH + + ✓ 2 H₂SO 4 O xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forwardDraw the skeletal ("line") structure of 1,3-dihydroxy-2-pentanone. Click and drag to start drawing a structure. X Parrow_forward
- Predicting edict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. + No reaction. Explanation Check HO Na O H xs H₂O 2 Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Iarrow_forwardChoosing reagents and conditions for acetal formation or hydrolysis 0/5 A student proposes the transformation below in one step of an organic synthesis. There may be one or more products missing from the right-hand side, but there are no reagents missing from the left-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. If the student's transformation is possible, then complete the reaction by adding any missing products to the right-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + This transformation can't be done in one step. 5 I H Autumn alo 值 Ar Barrow_forwardA block of copper of mass 2.00kg(cp = 0.3851 .K) and g temperature 0°C is introduced into an insulated container in which there is 1.00molH, O(g) at 100°C and 1.00 2 atm. Note that C P = 4.184. K for liquid water, and g that A H = 2260 for water. vap g Assuming all the steam is condensed to water, and that the pressure remains constant: (a) What will be the final temperature of the system? (b) What is the heat transferred from the water to the copper? (c) What is the entropy change of the water, the copper, and the total system?arrow_forward
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