The values of ( a + b ) 3 , a 3 + b 3 , ( a + b ) ( a 2 − a b + b 2 ) , ( a + b ) ( a 2 + a b + b 2 ) , and ( a + b ) ( a + b ) ( a + b ) by taking a = − 2 and b = 3 .

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Answer 1

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Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

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6) Find the area of the shaded region. Leave your answer in terms of π. A 2 B C A) 16.5л B) 30д 3.1988 C) 3л π D) 7.5π 9.+2u

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Answer 2

Question

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

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Answer 3

Question

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

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Answer 4

Question

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

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Answer 5

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

Answer 6

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

Answer 7

Chapter F, Problem 39ES

To determine

To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. F - Prob. 1DE Ch. F - Prob. 2DE Ch. F - Prob. 3DE Ch. F - Prob. 4DE Ch. F - Prob. 5DE Ch. F - Prob. 6DE Ch. F - Prob. 7DE Ch. F - Prob. 8DE Ch. F - Prob. 9DE Ch. F - Prob. 10DE

The values of ( a + b ) 3 , a 3 + b 3 , ( a + b ) ( a 2 − a b + b 2 ) , ( a + b ) ( a 2 + a b + b 2 ) , and ( a + b ) ( a + b ) ( a + b ) by taking a = − 2 and b = 3 .

Solution Summary: The author calculates the sum of the two expressions that are cubes denoted by A3 and

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To calculate: The values of (a+b)3,a3+b3,(a+b)(a2−ab+b2),(a+b)(a2+ab+b2), and (a+b)(a+b)(a+b) by taking a=−2 and b=3.

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Chapter F Solutions