Back up period:

A company should choose strategies of back-up and recovery based on goals and operational needs.

The period of backup depends on volume of critical information.

The period may be hourly, daily or weekly.

The most important files should be backed up at least once a day.

Back up storage:

The backup should be moved to a secure location on a regular basis.

It can be a fireproof cabinet or an offsite storage area.

Scheduled backups could be accomplished using backup services or online tools.

It can automatically detect and save changed data to back up storage location.

Type of disasters:

The types of disasters the company includes:

Application failure:

It denotes failure of an application.

VM failure:

It denotes failure of virtual machine.

Host failure:

It denotes failure of a host machine.

Rack failure:

It denotes failure of a rack.

Communication failure:

It denotes failure in network.

Data center disaster:

It denotes failure in data center.

The data storage location may get affected...

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter B, Problem B4.1MBD

Chapter B, Problem B4.3MBD

Students have asked these similar questions

4. Suppose we have a perfect binary tree with height h 0 representing a heap, meaning it = has n 2+1 1 keys indexed from 1 to 2+1 1. When we run convertomaxheap we run maxheapify in reverse order on every key with children. Let's examine the worst-case - In the worst-case every single key gets swapped all the way to the leaf level. (a) For each level in the tree there are a certain number of nodes and each of those nodes [10 pts] requires a certain number of swaps. Fill in the appropriate values/expressions in the table: Level Number of Keys Number of Swaps per Key 0 2 .. (b) Write down a sum for the total number of swaps required. This should involve h, not n. [10 pts] Total

The next problem concerns the following C code: /copy input string x to buf */ void foo (char *x) { char buf [8]; strcpy((char *) buf, x); } void callfoo() { } foo("ZYXWVUTSRQPONMLKJIHGFEDCBA"); Here is the corresponding machine code on a Linux/x86 machine: 0000000000400530 : 400530: 48 83 ec 18 sub $0x18,%rsp 400534: 48 89 fe mov %rdi, %rsi 400537: 48 89 e7 mov %rsp,%rdi 40053a: e8 di fe ff ff callq 400410 40053f: 48 83 c4 18 add $0x18,%rsp 400543: c3 retq 400544: 0000000000400544 : 48 83 ec 08 sub $0x8,%rsp 400548: bf 00 06 40 00 mov $0x400600,%edi 40054d: e8 de ff ff ff callq 400530 400552: 48 83 c4 08 add $0x8,%rsp 400556: c3 This problem tests your understanding of the program stack. Here are some notes to help you work the problem: ⚫ strcpy(char *dst, char *src) copies the string at address src (including the terminating '\0' character) to address dst. It does not check the size of the destination buffer. • You will need to know the hex values of the following characters:

1234 3. Which line prevents compiler optimization? Circle one: 1234 Suggested solution: Store strlen(str) in a variable before the if statement. ⚫ Remove the if statement. Replace index 0 && index < strlen(str)) { 5 } } = str [index] = val;

Chapter B Solutions

Business Driven Technology

Ch. B - Prob. B1.1CCO Ch. B - Prob. B1.2CCO Ch. B - Prob. B1.3CCO Ch. B - Prob. B1.4CCO Ch. B - Prob. B1.1CCT Ch. B - Prob. B1.2CCT Ch. B - Prob. B1.3CCT Ch. B - Prob. B1.4CCT Ch. B - Prob. B1.5CCT Ch. B - Prob. B1.6CCT

Knowledge Booster