Explanation of Solution
a.
Spreadsheet set up for buy-alternative calculation:
Let us consider the assumption inputs are given below:
- Server cost is $2,500.
- Software costs is $1,250.
- Straight-line depreciation is 3 years.
- Maintenance percentage range varies from 2 to 7 %...
Explanation of Solution
b.
Spreadsheet set up for lease-alternative calculation:
Let us consider the assumption inputs are given below:
- The cost of 3 year lease is $285.
- The cost of 2 year lease is $335.
- The cost of 1 year lease is $415.
- Discount for 20 to 30 computers is 5%.
- Discount for 31 to 50 computers is 10%...
Explanation of Solution
c.
(1)
Organization needs 20 servers for 5 years.
For Buy-Alternative calculation:
The given inputs are,
- Server cost is $2,500.
- Software costs is $1,250.
- Straight-line depreciation is 3 years.
- Maintenance percentage is 3 %.
The formula to calculate the total buy payment is given below:
Total buy payment = Depreciation + Maintenance
For 1 year:
Server cost = Server cost × servers purchased
= 2500 × 20
= $50,000
Software cost = Software cost × servers purchased
= 1250 × 20
= $25,000
Depreciation1 = (Server1 cost + software1 cost) / Depreciation year
= (50000 + 25000) / 3
= $25,000
Interest Expense = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Maintenance = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 2 year:
Depreciation2 = Depreciation1
= $25,000
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 3 year:
Depreciation3 = Depreciation1
= $25,000
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 4 year:
Depreciation = (Server cost + software cost) / Depreciation year
= (0 – 0)/3
= 0
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 0 + 1500
= $1,500
For 5 year:
Depreciation = (Server cost + software cost) / Depreciation year
= (0 – 0)/3
= 0
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 0 + 1500
= $1,500
Total Server cost:
Total Server cost = Sum of the server cost for 5 years
= 50000+0+0+0+0
= $50,000
Total Software cost:
Total Software cost = Sum of the software cost for 5 years
= 25000+0+0+0+0
= $25,000
Total depreciation:
Total depreciation= Sum of the depreciation for 5 years
= 25000+25000+25000+0+0
= $75,000
Salvage value:
Salvage value = (Total Server cost + Total Software cost) – Total depreciation
= 50000+25000 – 75000
= $0.00
Total cost:
Sum of yearly costs less salvage value = sum of totals buy expenses for 5 years
= 26,500 + 26,500 + 26,500 + 1,500 + 1,500
= $82,500
Finally, the sum of the yearly costs less salvage value is,
Total = total cost – salvage value
= 82,500 – 0.00
= $82,500
Therefore, the sum of the yearly costs less salvage value for buy-alternative is “$82,500”.
For Lease-Alternative calculation:
The given inputs are,
- The cost of 3 year lease is $285.
- The cost of 2 year lease is $335.
- The cost of 1 year lease is $415.
- Discount for 20 to 30 computers is 5%.
- Discount for 31 to 50 computers is 10%.
The formula to calculate the total lease payment is given below:
Total lease payment = (Payment for leased servers – Discount amount) × 12
For 1 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 20
= 5700
Discount amount = Payment for leased servers × Discount
= 5700 × 0.05
= 285
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (5700 – 285) × 12
= 5415 × 12
= $64,980
For 2 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 20
= 5700
Discount amount = Payment for leased servers × Discount
= 5700 × 0.05
= 285
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (5700 – 285) × 12
= 5415 × 12
= $64,980
For 3 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 20
= 5700
Discount amount = Payment for leased servers × Discount
= 5700 × 0.05
= 285
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (5700 – 285) × 12
= 5415 × 12
= $64,980
For 4 year:
Payment for leased servers = Payment per unit × Servers leased
= 335 × 20
= 6700
Discount amount = Payment for leased servers × Discount
= 6700 × 0.05
= 335
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (6700 – 335) × 12
= 6365 × 12
= $76,380
For 5 year:
Payment for leased servers = Payment per unit × Servers leased
= 335 × 20
= 6700
Discount amount = Payment for leased servers × Discount
= 6700 × 0.05
= 335
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (6700 – 335) × 12
= 6365 × 12
= $76,380
Total cost:
Total = Sum of Lease payments for 5 years
= 64,980 + 64,980 + 64,980 + 76,380 + 76,380
= $347,700
Therefore, the sum of the yearly costs for lease-alternative is “$347,700”.
The screenshot ofBuy-Alternative calculation andLease-Alternative calculation:
(2)
Organization needs 20 servers for first 2 years and 40 servers for next 3 years.
For Buy-Alternative calculation:
The given inputs are,
- Server cost is $2,500.
- Software costs is $1,250.
- Straight-line depreciation is 3 years.
- Maintenance percentage is 3 %.
The formula to calculate the total buy payment is given below:
Total buy payment = Depreciation + Maintenance
For 1 year:
Server1 cost = Server cost × servers purchased
= 2500 × 20
= $50,000
Software1 cost = Software cost × servers purchased
= 1250 × 20
= $25,000
Depreciation1 = (Server1 cost + software1 cost) / Depreciation year
= (50000 + 25000)/3
= $25,000
Interest Expense = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Maintenance = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 2 year:
Depreciation2 = Depreciation1
= $25,000
Interest Expense = Server1 cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 3 year:
Server2 cost = Server2 cost × servers purchased
= 2500 × 20
= $50,000
Software2 cost = Software2 cost × servers purchased
= 1250 × 20
= $25,000
Depreciation3 = Depreciation2 + (Server3 cost + software3 cost) / Depreciation year
= 25,000 + (50000 + 25000)/3
= 25,000 + 25,000
= $50,000
Interest Expense = (Server2 cost × maintenance percentage)
= 50000× 0.03
=$1,500
Maintenance = (Server1 cost × maintenance percentage) + (Server2 cost × maintenance percentage)
= (50000 × 0.03) + (50000 × 0.03)
= 1500 + 1500
= $3,000
Total buy payment = Depreciation + Maintenance
= 50000+3000
= $53,000
For 4 year:
Depreciation4 = Depreciation2
= $25,000
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = (Server1 cost × maintenance percentage) + (Server2 cost × maintenance percentage)
= (50000 × 0.03) + (50000 × 0.03)
= 1500 + 1500
= $3,000
Total buy payment = Depreciation + Maintenance
= 25000 + 3000
= $28,000
For 5 year:
Depreciation5 = Depreciation4
=$25,000
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = (Server1 cost × maintenance percentage) + (Server2 cost × maintenance percentage)
= (50000 × 0.03) + (50000 × 0.03)
= 1500 + 1500
= $3,000
Total buy payment = Depreciation + Maintenance
= 25000 + 3000
= $28,000
Total Server cost:
Total Server cost = Sum of the server cost for 5 years
= 50000+0+50000+0+0
= $100,000
Total Software cost:
Total Software cost = Sum of the software cost for 5 years
= 25000+0+25000+0+0
= $50,000
Total depreciation:
Total depreciation= Sum of the depreciation for 5 years
= 25000+25000+50000+25000+25000
= $150,000
Salvage value:
Salvage value = (Total Server cost + Total Software cost) – Total depreciation
= 100000+50000 – 150000
= $0.00
Total cost:
Sum of yearly costs less salvage value = sum of totals expenses for 5 years
= 26,500 + 26,500 + 53,000 + 28,000 + 28,000
= $162,000.00
Finally, the sum of the yearly costs less salvage value is,
Total = total cost – salvage value
= 162,000– 0.00
= $162,000
Therefore, the sum of the yearly costs less salvage value for buy-alternative is “$162,000”.
For Lease-Alternative calculation:
The given inputs are,
- The cost of 3 year lease is $285.
- The cost of 2 year lease is $335.
- The cost of 1 year lease is $415.
- Discount for 20 to 30 computers is 5%.
- Discount for 31 to 50 computers is 10%.
The formula to calculate the total lease payment is given below:
Total lease payment = (Payment for leased servers – Discount amount) × 12
For 1 year:
Payment for leased servers = Payment per unit × Servers leased
= 335 × 20
= 6700
Discount amount = Payment for leased servers × Discount
= 6700 × 0.05
= 335
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (6700 – 335) × 12
= 6365 × 12
= $76,380
For 2 year:
Payment for leased servers = Payment per unit × Servers leased
= 335 × 20
= 6700
Discount amount = Payment for leased servers × Discount
= 6700 × 0.05
= 335
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (6700 – 335) × 12
= 6365 × 12
= $76,380
For 3 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 40
= 11400
Discount amount = Payment for leased servers × Discount
= 11400 × 0.10
= 1140
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (11400 – 1140) × 12
= 10260 × 12
= $123,120
For 4 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 40
= 11400
Discount amount = Payment for leased servers × Discount
= 11400 × 0.10
= 1140
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (11400 – 1140) × 12
= 10260 × 12
= $123,120
For 5 year:
Payment for leased servers = Payment per unit × Servers leased
= 285 × 40
= 11400
Discount amount = Payment for leased servers × Discount
= 11400 × 0.10
= 1140
Total lease payment = (Payment for leased servers – Discount amount) × 12
= (11400 – 1140) × 12
= 10260 × 12
= $123,120
Total cost:
Total = Sum of Lease payments for 5 years
= 76,380 + 76,380 + 123,120 + 123,120 + 123,120
= $522,120.00
Therefore, the sum of the yearly costs for lease-alternative is “$522,120”.
The screenshot ofBuy-Alternative calculation andLease-Alternative calculation:
(3)
Organization needs 20 servers for first 2 years, 40 servers for next 2 years, and 50 servers for last year.
For Buy-Alternative calculation:
The given inputs are,
- Server cost is $2,500.
- Software costs is $1,250.
- Straight-line depreciation is 3 years.
- Maintenance percentage is 3 %.
The formula to calculate the total buy payment is given below:
Total buy payment = Depreciation + Maintenance
For 1 year:
Server1 cost = Server cost × servers purchased
= 2500 × 20
= $50,000
Software1 cost = Software cost × servers purchased
= 1250 × 20
= $25,000
Depreciation1 = (Server1 cost + software1 cost) / Depreciation year
= (50000 + 25000)/3
= $25,000
Interest Expense = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Maintenance = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 2 year:
Depreciation2 = Depreciation1
= $25,000
Interest Expense = Server1 cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = Server1 cost × maintenance percentage
= 50000 × 0.03
= $1,500
Total buy payment = Depreciation + Maintenance
= 25000 + 1500
= $26,500
For 3 year:
Server2 cost = Server2 cost × servers purchased
= 2500 × 20
= $50,000
Software2 cost = Software2 cost × servers purchased
= 1250 × 20
= $25,000
Depreciation3 = Depreciation2 + (Server3 cost + software3 cost) / Depreciation year
= 25,000 + (50000 + 25000)/3
= 25,000 + 25,000
= $50,000
Interest Expense = (Server2 cost × maintenance percentage)
= 50000× 0.03
=$1,500
Maintenance = (Server1 cost × maintenance percentage) + (Server2 cost × maintenance percentage)
= (50000 × 0.03) + (50000 × 0.03)
= 1500 + 1500
= $3,000
Total buy payment = Depreciation + Maintenance
= 50000 + 3000
= $53,000
For 4 year:
Depreciation4 = Depreciation2
= $25,000
Interest Expense = Server cost × maintenance percentage
= 0 × 0.03
= 0
Maintenance = (Server1 cost × maintenance percentage) + (Server2 cost × maintenance percentage)
= (50000 × 0.03) + (50000 × 0.03)
= 1500 + 1500
= $3,000
Total buy payment = Depreciation + Maintenance
= 25000 + 3000
= $28,000
For 5 year:
Server3 cost = Server3 cost × servers purchased
= 2500 × 10
= $25,000
Software2 cost = Software2 cost × servers purchased
= 1250 × 10
= $12,500
Depreciation5 = Depreciation4+ (Server5 cost + software5 cost) / Depreciation year
= 25000 + (25000 + 12500) / 3
= 25000 + 12500
= $37,500
Interest Expense = Server cost × maintenance percentage
= 25000 × 0...
Want to see the full answer?
Check out a sample textbook solution
- Q12- A three phase transformer 3300/400 V,has D/Y connected and working on 50Hz. The line current on the primary side is 12A and secondary has a balanced load at 0.8 lagging p.f. Determine the i) Secondary phase voltage ii) Line current iii) Output power Ans. (230.95 V, 99.11 A, 54.94 kW)arrow_forwardmake corrections of this program based on the errors shown. this is CIS 227 .arrow_forwardCreate 6 users: Don, Liz, Shamir, Jose, Kate, and Sal. Create 2 groups: marketing and research. Add Shamir, Jose, and Kate to the marketing group. Add Don, Liz, and Sal to the research group. Create a shared directory for each group. Create two files to put into each directory: spreadsheetJanuary.txt meetingNotes.txt Assign access permissions to the directories: Groups should have Read+Write access Leave owner permissions as they are “Everyone else” should not have any access Submit for grade: Screenshot of /etc/passwd contents showing your new users Screenshot of /etc/group contents showing new groups with their members Screenshot of shared directories you created with files and permissionsarrow_forward
- ⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers, ⚫ your circuit diagrams for your extended full adder, designed in Section 1 and ⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2. 1 An Extended Full Adder In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj, Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit outputs: sj, Cout and rout. The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only on t₁ and to in the first place: t₁ to Description 00 Output Relationship Ignored Inputs Addition Mode 2 Coutsjaj + bj + Cin, Tout= 0 Tin 0 1 Shift Left Mode Sj = Cin, Cout=bj, rout = 0 rin, aj 10 1 1 Shift Right…arrow_forwardShow the correct stereochemistry when needed!! mechanism: mechanism: Show the correct stereochemistry when needed!! Br NaOPh diethyl ether substitutionarrow_forwardIn javaarrow_forward
- KeanPerson #keanld:int #keanEmail:String #firstName:String #lastName: String KeanAlumni -yearOfGraduation: int - employmentStatus: String + KeanPerson() + KeanPerson(keanld: int, keanEmail: String, firstName: String, lastName: String) + getKeanld(): int + getKeanEmail(): String +getFirstName(): String + getLastName(): String + setFirstName(firstName: String): void + setLastName(lastName: String): void +toString(): String +getParkingRate(): double + KeanAlumni() + KeanAlumni(keanld: int, keanEmail: String, firstName: String, lastName: String, yearOfGraduation: int, employmentStatus: String) +getYearOfGraduation(): int + setYearOfGraduation(yearOfGraduation: int): void +toString(): String +getParkingRate(): double In this question, write Java code to Create and Test the superclass: Abstract KeanPerson and a subclass of the KeanPerson: KeanAlumni. Task 1: Implement Abstract Class KeanPerson using UML (10 points) • Four data fields • Two constructors (1 default and 1 constructor with all…arrow_forwardPlz correct answer by best experts...??arrow_forwardQ3) using the following image matrix a- b- 12345 6 7 8 9 10 11 12 13 14 15 1617181920 21 22 23 24 25 Using direct chaotic one dimension method to convert the plain text to stego text (hello ahmed)? Using direct chaotic two-dimension method to convert the plain text to stego text?arrow_forward
- : The Multithreaded Cook In this lab, we'll practice multithreading. Using Semaphores for synchronization, implement a multithreaded cook that performs the following recipe, with each task being contained in a single Thread: 1. Task 1: Cut onions. a. Waits for none. b. Signals Task 4 2. Task 2: Mince meat. a. Waits for none b. Signals Task 4 3. Task 3: Slice aubergines. a. Waits for none b. Signals Task 6 4. Task 4: Make sauce. a. Waits for Task 1, and 2 b. Signals Task 6 5. Task 5: Finished Bechamel. a. Waits for none b. Signals Task 7 6. Task 6: Layout the layers. a. Waits for Task 3, and 4 b. Signals Task 7 7. Task 7: Put Bechamel and Cheese. a. Waits for Task 5, and 6 b. Signals Task 9 8. Task 8: Turn on oven. a. Waits for none b. Signals Task 9 9. Task 9: Cook. a. Waits for Task 7, and 8 b. Signals none At the start of each task (once all Semaphores have been acquired), print out a string of the task you are starting, sleep for 2-11 seconds, then print out a string saying that you…arrow_forwardProgramming Problems 9.28 Assume that a system has a 32-bit virtual address with a 4-KB page size. Write a C program that is passed a virtual address (in decimal) on the command line and have it output the page number and offset for the given address. As an example, your program would run as follows: ./addresses 19986 Your program would output: The address 19986 contains: page number = 4 offset = 3602 Writing this program will require using the appropriate data type to store 32 bits. We encourage you to use unsigned data types as well. Programming Projects Contiguous Memory Allocation In Section 9.2, we presented different algorithms for contiguous memory allo- cation. This project will involve managing a contiguous region of memory of size MAX where addresses may range from 0 ... MAX - 1. Your program must respond to four different requests: 1. Request for a contiguous block of memory 2. Release of a contiguous block of memory 3. Compact unused holes of memory into one single block 4.…arrow_forwardusing r languagearrow_forward
Database System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
Starting Out with Python (4th Edition)Computer ScienceISBN:9780134444321Author:Tony GaddisPublisher:PEARSON
Digital Fundamentals (11th Edition)Computer ScienceISBN:9780132737968Author:Thomas L. FloydPublisher:PEARSON
C How to Program (8th Edition)Computer ScienceISBN:9780133976892Author:Paul J. Deitel, Harvey DeitelPublisher:PEARSON
Database Systems: Design, Implementation, & Manag...Computer ScienceISBN:9781337627900Author:Carlos Coronel, Steven MorrisPublisher:Cengage Learning
Programmable Logic ControllersComputer ScienceISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education