(a) Interpretation: The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined. Concept introduction: The minimum weight is calculated by the relative error formula which is given below- E r = E m − E t E t × 100 Here, E r = relative error E m = measured value E t = true value

Question

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Answer 1

Question

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

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For Raman spectroscopy/imaging, which statement is not true regarding its disadvantages? a) Limited spatial resolution. b) Short integration time. c) A one-dimensional technique. d) Weak signal, only 1 in 108 incident photons is Raman scattered. e) Fluorescence interference.

Answer 2

Question

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Expert Solution & Answer

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Answer 3

Question

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 4

Question

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Expert Solution & Answer

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Check out a sample textbook solution

See solution

Answer 5

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 6

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 7

Chapter A1, Problem A1.4QAP

Interpretation Introduction

(a)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.1% needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 8

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 9

Interpretation Introduction

(b)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.5 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 10

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 11

Interpretation Introduction

(c)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 0.8 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 12

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 13

Interpretation Introduction

(d)

Interpretation:

The minimum weight of the sample for relative error due to 0.5 mg loss to be less than 1.2 % needs to be determined.

Concept introduction:

The minimum weight is calculated by the relative error formula which is given below-

Er=Em−EtEt×100

Here,

Er = relative error

Em = measured value

Et = true value

Answer 14

Expert Solution & Answer

Answer 15

Expert Solution & Answer

Answer 16

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Answer 17

Ch. A1 - Prob. A1.1QAP Ch. A1 - Prob. A1.2QAP Ch. A1 - Prob. A1.3QAP Ch. A1 - Prob. A1.4QAP Ch. A1 - Prob. A1.5QAP Ch. A1 - Prob. A1.6QAP Ch. A1 - Prob. A1.7QAP Ch. A1 - Prob. A1.8QAP Ch. A1 - Prob. A1.9QAP Ch. A1 - Prob. A1.10QAP

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Chapter A1 Solutions