Principles of Instrumental Analysis, 6th Edition
Principles of Instrumental Analysis, 6th Edition
6th Edition
ISBN: 9788131525579
Author: Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher: Cenage Learning
Question
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Chapter A1, Problem A1.3QAP
Interpretation Introduction

(a)

Interpretation:

The copper yield results are lowered by the value 0.5 mg. The percent relative error due to the source is to be determined when the weight of the copper sample is 25mg.

Concept introduction:

The following formula will be used for the calculation of the relative error-

Er=EmEtEt×100 ............….. (1)

Where,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(b)

Interpretation:

The copper yield results are lowered by the value 0.5 mg. The percent relative error due to the source is to be determined when the weight of the copper sample is 100mg.

Concept introduction:

The following formula will be used for the calculation of the relative error-

Er=EmEtEt×100 ............….. (1)

Where,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(c)

Interpretation:

The copper yield results are lowered by the value 0.5 mg. The percent relative error due to the source is to be determined when the weight of the copper sample is 250mg.

Concept introduction:

The following formula will be used for the calculation of the relative error-

Er=EmEtEt×100 ............….. (1)

Where,

Er = relative error

Em = measured value

Et = true value

Interpretation Introduction

(d)

Interpretation:

The copper yield results are lowered by the value 0.5 mg. The percent relative error due to the source is to be determined when the weight of the copper sample is 500mg.

Concept introduction:

The following formula will be used for the calculation of the relative error-

Er=EmEtEt×100 ............….. (1)

Where,

Er = relative error

Em = measured value

Et = true value

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