EBK ORGANIC CHEMISTRY
EBK ORGANIC CHEMISTRY
9th Edition
ISBN: 8220100591310
Author: McMurry
Publisher: CENGAGE L
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Chapter 9.SE, Problem 36AP
Interpretation Introduction

a)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  1

Interpretation:

How to convert an alkyne into an alkene, if necessary using more than one step, is to be shown.

Concept introduction:

Alkynes can be converted in to the corresponding alkenes by treating with H2 in the presence of Pd-BaSO4.

To show:

How to convert an alkyne into an alkene, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

Alkynes can be reduced to the corresponding alkenes in a single step as shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  2

Explanation of Solution

Alkynes when treated with H2 in the presence of Pd-BaSO4 add two equivalents of hydrogen to yield an alkane. In the presence of Pd-BaSO4, the reduction stops in the alkene stage itself as only one equivalent of hydrogen is added by the alkynes.

Conclusion

Alkynes when treated with hydrogen in the presence of Pd-BaSO4 get reduced to alkenes in a single step.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  3
Interpretation Introduction

b)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  4

Interpretation:

How to convert an alkyne into an alkane, if necessary using more than one step, is to be shown.

Concept introduction:

Alkynes add two equivalents of hydrogen when treated with H2 in the presence of Raney nickel catalyst.

To show:

How to convert an alkyne into an alkane, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

Alkynes can be reduced to the corresponding alkanes by using the step shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  5

Explanation of Solution

Alkynes when treated with H2 in the presence of Raney Ni add two equivalents of hydrogen to yield the corresponding alkane.

Conclusion

Alkynes can be reduced to the corresponding alkanes by using the step shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  6
Interpretation Introduction

c)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  7

Interpretation:

How to convert an alkyne into an aldehyde, if necessary using more than one step is to be shown.

Concept introduction:

Symmetrical internal alkynes yield an aldehyde as a single product during ozonolysis. The alkyne given can be converted in to a higher symmetrical alkyne by treating with NaNH2 in NH3 and RCl. The symmetrical alkyne thus obtained upon ozonolysis followed by reduction with Zn and acetic acid give an aldehyde as the only product.

To state:

How to convert an alkyne into an aldehyde , if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The terminal alkyne can be converted into an aldehyde through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  8

Explanation of Solution

The alkyne is first converted in to a higher alkyne by treating it with NaNH2 and then with RCl. The higher alkyne, being symmetrical, upon ozonolysis followed by reduction with Zn and acetic acid gets cleaved to give the aldehyde required as the product.

Conclusion

The terminal alkyne can be converted into an aldehyde through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  9
Interpretation Introduction

d)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  10

Interpretation:

How to convert an alkyne into secondary alkyl halide, if necessary using more than one step, is to be shown.

Concept introduction:

Terminal alkynes when reduced with H2 in the presence of Pd-BaSO4 catalyst yield the corresponding alkenes. The alkenes when treated with HCl yield an alkyl halide following Markovnikov regiochemistry.

To state:

How to convert an alkyne into a secondary alkyl halide, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The alkyne can be converted into a secondary alkyl halide through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  11

Explanation of Solution

The alkyne is first converted in to an alkene by treating it with H2 in the presence of Pd-BaSO4catalyst. Addition of HCl to alkenes follows Markovnikov regiochemistry. The chlorine atom adds to the carbon with one substituent and H adds to the terminal carbon without substituents to yield the product required.

Conclusion

An alkyne can be converted into a secondary alkyl halide through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  12
Interpretation Introduction

e)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  13

Interpretation:

How to convert (if necessary using more than one step) an alkyne into a primary alcohol that contains one more carbon is to be shown.

Concept introduction:

Alkynes can be converted into a primary alcohol through the following steps. The alkyne is first reduced to an alkene using H2 and Pd-BaSO4. Hydrohalogenation converts the alkene in to an alkyl halide which when treated with NaOH yields the required alcohol.

To state:

How to convert an alkyne into a primary alcohol, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The alkyne can be converted in to the alcohol through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  14

Explanation of Solution

The alkyne gets reduced to an alkene when treated with H2 and Pd-BaSO4. The alkene gets converted in to a primary alkyl halide when treated with HCl in the presence of a peroxide following anti Markovnikov regiochemistry. The alkyl halide yields the alcohol when the nucleophile OH- displaces Cl- when treated with NaOH.

Conclusion

The alkyne can be converted in to the alcohol through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  15
Interpretation Introduction

f)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  16

Interpretation:

How to convert an alkyne into its next higher alkyne, if necessary using more than one step, is to be shown.

Concept introduction:

Terminal alkynes are converted in to acetylides by treating with NaNH2 in liquid ammonia. The acetylides can be converted to higher alkynes by treating with alkyl halides having required number of carbon atoms.

To state:

How to convert an alkyne into its next higher alkyne, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The alkyne can be converted in to its next higher alkyne through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  17

Explanation of Solution

The alkyne, being acidic, when treated with NaNH2 in liquid ammonia is converted in to the sodium acetylide. The acetylide upon treatment with methyl chloride yields the next higher alkyne.

Conclusion

The alkyne can be converted in to its next higher alkyne through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  18
Interpretation Introduction

g)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  19

Interpretation:

How to convert an alkyne into a ketone, if necessary using more than one step, is to be shown.

Concept introduction:

Terminal alkynes when hydrated in the presence of dilute H2SO4 in the presence of HgSO4 are converted in to enols. The addition of water takes place following Markovnikov regiochemistry. The enols upon tautomerization yield ketones as the product.

To state:

How to convert an alkyne into a ketone, if necessary, using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The alkyne can be converted in to a ketone using the step shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  20

Explanation of Solution

Addition of water takes place to the triple bond when the alkyne is treated with dilute H2SO4 in the presence of HgSO4 following Markovnikov regiochemistry. The OH adds on to the carbon with one substituent and H adds on to the terminal carbon with no substituent to yield an enol. The enol then undergoes tautomerization to give the ketone as the product.

Conclusion

The alkyne can be converted in to a ketone using the step shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  21
Interpretation Introduction

h)

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  22

Interpretation:

How to convert an alkyne into an epoxide, if necessary using more than one step, is to be shown.

Concept introduction:

Terminal alkynes are converted in to alkenes by treating with H2 in the presence of Pd-BaSO4. The alkenes are converted in to epoxides by treating them with peracids like meta - chloroperoxybenzoic acid.

To state:

How to convert an alkyne into an epoxide, if necessary using more than one step.

Expert Solution
Check Mark

Answer to Problem 36AP

The alkyne can be converted in to an epoxide using the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  23

RCO3H=meta - chloroperoxybenzoic acid

Explanation of Solution

The terminal alkyne when reduced with H2 in the presence of Pd-BaSO4 yield the corresponding alkene. When the alkene is treated with meta -chloroperoxybenzoic acid, transfer of an oxygen atom from the acid to the double bond in alkene takes place with syn stereochemistry to yield the epoxide.

Conclusion

The alkyne can be converted in to the epoxide through the steps shown.

EBK ORGANIC CHEMISTRY, Chapter 9.SE, Problem 36AP , additional homework tip  24

RCO3H=meta - chloroperoxybenzoic acid.

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Chapter 9 Solutions

EBK ORGANIC CHEMISTRY

Ch. 9.8 - Prob. 11PCh. 9.9 - Show the terminal alkyne and alkyl halide from...Ch. 9.9 - Beginning with acetylene and any alkyl halide...Ch. 9.SE - Name the following alkynes, and predict the...Ch. 9.SE - From what alkyne might each of the following...Ch. 9.SE - Prob. 16VCCh. 9.SE - The following cycloalkyne is too unstable to...Ch. 9.SE - Prob. 18MPCh. 9.SE - Assuming that strong acids add to alkynes in the...Ch. 9.SE - Prob. 20MPCh. 9.SE - Prob. 21MPCh. 9.SE - Prob. 22MPCh. 9.SE - Prob. 23MPCh. 9.SE - Prob. 24MPCh. 9.SE - Reaction of acetone with D3O+ yields...Ch. 9.SE - Give IUPAC names for the following compounds:Ch. 9.SE - Draw structures corresponding to the following...Ch. 9.SE - Prob. 28APCh. 9.SE - Prob. 29APCh. 9.SE - Prob. 30APCh. 9.SE - Predict the products from reaction of l-hexyne...Ch. 9.SE - Prob. 32APCh. 9.SE - Prob. 33APCh. 9.SE - Propose structures for hydrocarbons that give the...Ch. 9.SE - Identify the reagents a-c in the following scheme:Ch. 9.SE - Prob. 36APCh. 9.SE - Prob. 37APCh. 9.SE - Prob. 38APCh. 9.SE - How would you carry out the following...Ch. 9.SE - Prob. 40APCh. 9.SE - Synthesize the following compounds using 1-butyne...Ch. 9.SE - Prob. 42APCh. 9.SE - Prob. 43APCh. 9.SE - Prob. 44APCh. 9.SE - Prob. 45APCh. 9.SE - A hydrocarbon of unknown structure has the formula...Ch. 9.SE - Compound A(C9H12) absorbed 3 equivalents of H2 on...Ch. 9.SE - Hydrocarbon A has the formula C12H8. It absorbs 8...Ch. 9.SE - Occasionally, a chemist might need to invert the...Ch. 9.SE - Prob. 50APCh. 9.SE - Prob. 51APCh. 9.SE - Prob. 52APCh. 9.SE - Prob. 53APCh. 9.SE - Prob. 54APCh. 9.SE - Prob. 55APCh. 9.SE - Prob. 56APCh. 9.SE - Prob. 57AP
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