Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card
9th Edition
ISBN: 9781305701021
Author: John E. McMurry
Publisher: Cengage Learning
Question
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Chapter 9.SE, Problem 21MP
Interpretation Introduction

a)

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 9.SE, Problem 21MP , additional homework tip  1

Interpretation:

Given that the final step in the hydration of an alkyne under acidic conditions is the tautomerization of the enol intermediate to give the corresponding ketone. The mechanism involves protonation followed by deprotonation. Based on this information a mechanism for the tautomerization reaction shown is to be drawn.

Concept introduction:

The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation ion then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.

To propose:

A mechanism for the tautomerization reaction shown.

Interpretation Introduction

b)

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 9.SE, Problem 21MP , additional homework tip  2

Interpretation:

Given that the final step in the hydration of an alkyne under acidic conditions is the tautomerization of the enol intermediate to give the corresponding ketone. The mechanism involves protonation followed by deprotonation. Based on this information a mechanism for the tautomerization reaction shown is to be drawn.

Concept introduction:

The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.

To propose:

A mechanism for the tautomerization reaction shown.

Interpretation Introduction

c)

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card, Chapter 9.SE, Problem 21MP , additional homework tip  3

Interpretation:

Given that the final step in the hydration of an alkyne under acidic conditions is the tautomerization of the enol intermediate to give the corresponding ketone. The mechanism involves protonation followed by deprotonation. Based on this information a mechanism for the tautomerization reaction shown is to be drawn.

Concept introduction:

The enol picks up a proton from H3O+ using the unshared pair of electrons on oxygen and the π electrons in the double bond to yield a carbocation. The carbocation then loses a proton and the electrons in the O-H bond are moved towards the positively charged carbon to yield the ketone.

To propose:

A mechanism for the tautomerization reaction shown.

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Chapter 9 Solutions

Bundle: Organic Chemistry, 9th, Loose-Leaf + OWLv2, 4 terms (24 months) Printed Access Card

Ch. 9.8 - Prob. 11PCh. 9.9 - Show the terminal alkyne and alkyl halide from...Ch. 9.9 - Beginning with acetylene and any alkyl halide...Ch. 9.SE - Name the following alkynes, and predict the...Ch. 9.SE - From what alkyne might each of the following...Ch. 9.SE - Prob. 16VCCh. 9.SE - The following cycloalkyne is too unstable to...Ch. 9.SE - Prob. 18MPCh. 9.SE - Assuming that strong acids add to alkynes in the...Ch. 9.SE - Prob. 20MPCh. 9.SE - Prob. 21MPCh. 9.SE - Prob. 22MPCh. 9.SE - Prob. 23MPCh. 9.SE - Prob. 24MPCh. 9.SE - Reaction of acetone with D3O+ yields...Ch. 9.SE - Give IUPAC names for the following compounds:Ch. 9.SE - Draw structures corresponding to the following...Ch. 9.SE - Prob. 28APCh. 9.SE - Prob. 29APCh. 9.SE - Prob. 30APCh. 9.SE - Predict the products from reaction of l-hexyne...Ch. 9.SE - Prob. 32APCh. 9.SE - Prob. 33APCh. 9.SE - Propose structures for hydrocarbons that give the...Ch. 9.SE - Identify the reagents a-c in the following scheme:Ch. 9.SE - Prob. 36APCh. 9.SE - Prob. 37APCh. 9.SE - Prob. 38APCh. 9.SE - How would you carry out the following...Ch. 9.SE - Prob. 40APCh. 9.SE - Synthesize the following compounds using 1-butyne...Ch. 9.SE - Prob. 42APCh. 9.SE - Prob. 43APCh. 9.SE - Prob. 44APCh. 9.SE - Prob. 45APCh. 9.SE - A hydrocarbon of unknown structure has the formula...Ch. 9.SE - Compound A(C9H12) absorbed 3 equivalents of H2 on...Ch. 9.SE - Hydrocarbon A has the formula C12H8. It absorbs 8...Ch. 9.SE - Occasionally, a chemist might need to invert the...Ch. 9.SE - Prob. 50APCh. 9.SE - Prob. 51APCh. 9.SE - Prob. 52APCh. 9.SE - Prob. 53APCh. 9.SE - Prob. 54APCh. 9.SE - Prob. 55APCh. 9.SE - Prob. 56APCh. 9.SE - Prob. 57AP
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