Suppose that the power series
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- The test for DIVERGENCE says: If lim ak does not exist or is not equal to 0 the series E ak is divergent k=1 If lim ak exist, the series 2 ak is convergent k=1 If lim ak is equal to 0 the series E ak is divergent k=1 If lim ak is equal to 0 the series 2 ak is convergent k=1arrow_forwardpart D E needarrow_forwardFind the radius of convergence, R, of the series. 2(-1)" (x - 3)" 2n + 1 R = Find the interval, I, of convergence of the series. (Enter your answer using interval notation.)arrow_forward
- Please use these questions to find non-zero terms!arrow_forward2. Consider the power series > ak(x + 2)*. Assume that we know that the series ak converges, but that k=0 k=0 ar(4*) diverges. k=0 (a) Does the power series converge at x = -1.3? Explain how you know, or explain why you don't have enough information to answer the question. (b) Does the series > ak (5)* converge or diverge? Explain how you know, or explain why you don't have k=0 enough information to answer the question.arrow_forwarda, b and c please. I'm very confusedarrow_forward
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