Chapter 9.5, Problem 30AYU

To determine

To find: The magnitude of the force required to keep the Silverado from rolling down the hill. What is the magnitude of the force perpendicular to the hill?

Answer to Problem 30AYU

Solution:

$F=781.4\text{ lbs}$, required uphill force to prevent rolling down the hill and $F=4431.6\text{ lbs}$, required the force perpendicular to the hill.

Explanation of Solution

Given:

A Chevrolet Silverado with a gross weight of 4500 pounds is parked on a street with a ${10}^{\circ }$ grade.

Calculation:

$F=$ Downhill force $=4500\times \text{ sin}{10}^{\circ }$

$F=781.4\text{ lbs}$, required uphill force to prevent rolling down the hill.

Perpendicular force $=4500\times \text{ cos}{10}^{\circ }$.

$F=4431.6\text{ lbs}$, required the force perpendicular to the hill.