Chapter 9.4, Problem 40AYU

In Problems 37-42, find $\Vert v\Vert$.

$v=6i+\text{2}j$

To determine

To find: $\Vert v\Vert$

Answer to Problem 40AYU

Solution:

$\sqrt{40}$

Explanation of Solution

Given:

$v=6i+2j$

Calculation:

Let $v=a_{1}i+b_{1}j=\langle a_1,b_1\rangle$. Then $\Vert v\Vert =\sqrt{a_1^2+b_1^2}$.

Here $a_1=6;b_1=2$.

$\Vert v\Vert =\sqrt{{\left(6\right)}^2+{\left(2\right)}^2}=\sqrt{36+4}=\sqrt{40}$