Chapter 9.5, Problem 25PPS

To determine

The numbers in the increasing order

Answer to Problem 25PPS

  $2.4\times {10}^{-2}<2.45\times {10}^{-2}<2.4\times {10}^2<2.45\times {10}^2$

Explanation of Solution

Given:

The given terms are

  $2.4\times {10}^2,2.45\times {10}^{-2},2.45\times {10}^2,2.4\times {10}^{-2}$

Calculation:

The given terms can be simplified as

  $\begin{array}{l}\Rightarrow 2.4\times {10}^2\\ =\frac{24}{10}\times 100\\ =240\\ \\ \Rightarrow 2.45\times {10}^{-2}\\ =\frac{245}{100}\times \frac{1}{100}\\ =0.245\\ \\ \Rightarrow 2.45\times {10}^2\\ =\frac{245}{100}\times 100\\ =245\\ \\ \Rightarrow 2.4\times {10}^{-2}\\ =\frac{24}{10}\times \frac{1}{100}\\ =0.024\\ \\ \text{As,}\\ 0.024<0.245<240<245\\ 2.4\times {10}^{-2}<2.45\times {10}^{-2}<2.4\times {10}^2<2.45\times {10}^2\end{array}$