Explanation Given info: x ¯ = 23 , n = 15 σ = 4 The hypotheses are given below: Null hypothesis: H 0 : μ = 22 Alternative hypothesis: H a : μ > 22 Calculation: Critical value approach: Critical value : For 5% level of significance, 1 − α = 1 − 0.95 α = 0.05 Hence, the cumulative area to the left is, Area to the left = 1 − Area to the right = 1 − 0.05 = 0.95 From Table II of the standard normal distribution of Appendix A, the critical value is 1.645. As the test is right tailed test so, the critical value is 1.645. Step by step procedure to obtain the test value using the MINITAB software: Choose Stat > Basic Statistics > 1-Sample Z . In Summarized data, enter sample size as 15 and sample mean as23 In Standard deviation , enter 4. In Perform hypothesis test, enter the test mean as 22 . Check Options ; enter Confidence level as 95%

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Author: Neil A. Weiss

Publisher: PEARSON

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Chapter 9.4, Problem 80E

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Chapter 9.4, Problem 79E

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Chapter 9 Solutions

Introductory Statistics (10th Edition)

Ch. 9.1 - Explain the meaning of the term hypothesis as used...Ch. 9.1 - Regarding the term null hypothesis: a. Originally,...Ch. 9.1 - What role does the decision criterion play in a...Ch. 9.1 - Suppose that you want to perform a hypothesis test...Ch. 9.1 - Suppose that you are considering a hypothesis test...Ch. 9.1 - Suppose that, in a hypothesis test, the null...Ch. 9.1 - Suppose that, in a hypothesis test, the null...Ch. 9.1 - What is the relation between the significance...Ch. 9.1 - Answer true or false and explain your answer: If...Ch. 9.1 - Answer true or false and explain your answer: For...

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