Chapter 9.4, Problem 14E

To determine

To find: The magnitude of the given vector.

Answer to Problem 14E

The magnitude of the given vectoris $3\sqrt{5}$ .

Explanation of Solution

Given information:

The vector is $\langle 1,-6,2\sqrt{2}\rangle$ .

Calculation:

The magnitude of vector $v$ is,

$\left|v\right|=\sqrt{v_1^2+v_2^2+v_3^2}$

Substitute the values in above equation.

$\begin{array}{c}\left|v\right|=\sqrt{{\left(1\right)}^2+{\left(-6\right)}^2+{\left(2\sqrt{2}\right)}^2}\\ =\sqrt{1+36+8}\\ =3\sqrt{5}\end{array}$